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Originally Posted by mike alexander
Given the known total, once the value for a or b is known the other is also determined. By my thinking, if the race is only between a and b and 12,000 votes are cast, of the 12,000 possible outcomes (Wait. 12,001) one is a tie. so, by chance alone the probability of a tie score is 1/12,001.
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What if there were six voters and two candidates? There's only one way to get the 6-0 tally, have all six vote for the first candidate. But there's more than one way to get 3-3, including just having them switch votes!
I guess I should've done it for two voters, two candidates
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Since there were actually six names on the ballot it gets messier, of course (Perhaps a Messier Number could be used here).
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way to swing it to astronomy