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Originally Posted by Neverfly
Didn't you address this in post 122 and Fortis replied in 123?
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I did but I didn't know that there was already page 5 so I thought that the message diddn't show up and that's why I repeated the message, and then deleted the duplicate, however you were faster than my deletion
Quote:
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Originally Posted by Fortis
When you say "internal energy", are you referring to the "0" component of the 4-momentum?
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Yes. The "rest energy". The difference between "total energy" of the particle and its "kinetic energy".
It turns out that c^2 in E=mc^2 is actually C^2=c^2*sqrt(g_00) (see Landau's "Theory of fields", a small difference but important) and that's why dE/dx=-mg, where x is displacement, and g is acceleration, since dC/dx=g/(2C) which shows that -dE/dx is "gravitational force", and so E is the same as "gravitational energy". Unfortunately while E=mC^2 is mainstream science (see Landau) differentiating this equation is ATM for some reason and can't be published in polite society's scientific journals so please don't believe the above blindly.