mugaliens,
I'm not sure how much of the thread you are actually reading. I am in the same camp as you guys that gravity cannot actually be infinite. It only becomes so when using straightforward Newtonian gravity that is in inverse proportion to the square of the distance. But as far as gaining an actual infinite gravity is concerned, there are probably many factors that constrain it, such as the limit of the speed of light, all real bodies having magnitude in all three dimensions, and others. I am only demonstrating the potential of nonlimited gravity using Newtonian physics at the edge of a disk plane to show the great difference between the gravity of a sphere and disk. Any real disk will have some thickness, however, and as long as the thickness is at least appreciable, much greater than the Swartzschild radius for the mass, say, then Newtonian physics should suffice. The gravity at the edge of a disk with some thickness will have some gravity between just slightly greater than that of a sphere with the same mass and radius to some very large but finite value, depending on the measured non-zero thickness of the disk.
Also, that second post was quoted out of context. It referred to something Jeff posed for the non-infinite gravity of a thick disk. That is where the +h^2 comes in. Only if h is zero (for the height of the disk) do infinities show up. And as far as the gravity at the apex of a cone integration goes in the third post, the result was not infinite for that either. It showed up to 6 times as much gravity as that of a sphere with the same mass at a distance equal to the radius of the base for a cone of very short height, and a limit of 3 times as great for a cone with a very large height as compared to a sphere with the same mass at the same distance as the height of the cone.
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Let's put together the pieces of The Grand Puzzle . (website)
"Let's define another operator, Sz, which we won't pay any attention to."
"This transformation will automatically make zero equal zero."
"It may be true that zero equals zero -- and that is certainly an equality -- but I don't want to go into the details at this time."
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