Quote:
Originally Posted by knicholson
To Grav
If you do it the way I set it up, then I can check your progress. After you do it that way, even if it doesn't look optimum to you, you can improve it later. What you need to do first is to get a simple working program for the forward problem. You'll learn a lot by doing it this easy way first.
Ken Nicholson
|
Yes, I've done that actually. It is what I was referring to in the first part of post #96. For a disk with a radius that is 100 times as large as the thickness, using 120 rods per ring for 20 rings, I found a rotation speed at the rim that is 1.7087 times as great as that of a sphere with the same radius. At the edge of the first ring, however, or 1/20 of the radius, the acceleration was negative, giving a complex rotation speed. When I ran it for ten times as many rods for each of ten times as many rings, however, I got a rotation speed at the rim of 1.9842 and at the edge of the first disk of .9232 as great as that of within a sphere with the same radius as the radius of the disk. The actual speeds are about 2.015 at the rim and 1.0005 at 1/20 of the radius.
__________________
Let's put together the pieces of
The Grand Puzzle . (website)
"Let's define another operator, Sz, which we won't pay any attention to."
"This transformation will automatically make zero equal zero."
"It may be true that zero equals zero -- and that is certainly an equality -- but I don't want to go into the details at this time."