Quote:
Originally Posted by Pippin
Cern also didn't say that they weren't throwing a big party for us all, so they must be throwing one? nice logic....
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They *did* say that collisions like these happen often in nature. They didn't say these temperatures, the quark gluon plasma, etc occurred as well, because given the information that the collisions produce these conditions and that the collisions occur in nature, it should be unnecessary for them to do so.
Once again, there is nothing,
nothing unique about the LHC collisions aside from the fact that they take place inside a massive pile of detectors.
Quote:
Originally Posted by Warren Platts
I keep hearing talk that two 7 TeV beams will collide, resulting in a 14 TeV collision. E.g. when cjameshuff said that a stationary, 14 TeV mBH formed by the two beams colliding that happened to get hit again by one of the beams would turn into a 21 TeV mBH, and then go skittering off into the universe. But perhaps he's wrong about that.  |
Mass-energy is conserved, as is momentum. But it's much more than twice as hard to achieve a 14 TeV beam as it is to achieve a 7 TeV beam, and the products would emerge in a extremely narrow cone, making it difficult to see anything.
That was actually a very conservative, beyond-worst-case back-of-the-napkin estimate. It gains both mass and kinetic energy from the third impact, so it would actually violate conservation laws if it really massed 21 TeV. It would realistically be something less than that, and have a higher velocity. But the chances of the proton-MBH event occurring in the first place are ridiculously slim.
Quote:
Originally Posted by jj_0001
Do you guys understand what a fast-moving tiny black hole would do to the planet in terms of tidal force?
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Do you? We're talking about one with <25 zeptograms of mass. There wasn't even a defined SI prefix for quantities this small until 1991. It's direct gravitation won't have any significant effect, its tidal force will be practically nonexistent. If you dropped a particle into it from a hydrogen atom's radius away, it would take:
sqrt(2*25 pm/((G*14 TeV/c^2)/(25 pm)^2))
4.3 seconds for it to reach the black hole!
And the target has essentially no size, even in subatomic terms...if the particle has any sideways velocity, it'll miss. And if it's positively charged, it will be pushed away with far more force than the attraction of gravity from such a small mass...until the black hole grows large enough for its gravity to outweigh its charge, a proton or atomic nucleus will have to have an initial velocity that throws it at the black hole hard enough to overcome the repulsion. Electrons will be attracted by the charge more than the gravity, but they're so light and there are so many other competing electromagnetic fields in matter that they're unlikely to be captured and neutralize the charge that actively prevents it from absorbing protons.