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Old 09-September-2008, 03:23 PM
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cjameshuff cjameshuff is offline
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Quote:
Originally Posted by Pippin View Post
Ok I'll provide a definitive answer as to why I believe there is a fundamental difference between what occurs in nature and what will occur in the lab.
The first collision will be similar to a cosmic ray collision. However further collisions occurring in each test will occur under increasing temperatures.
Interactions following the initial collision occur at *lower* temperatures, since they have only a portion of the total energy. And they occur with cosmic rays as well.


Quote:
Originally Posted by Pippin View Post
The energy release of each individual collision will remain consistent, but the final collisions in the "experimental programme" will occur at "temperatures more than 100 000 times hotter than the heart of the Sun, concentrated within a minuscule space". This is not the temperature at which cosmic rays collisions take place in nature.
No. Every single collision occurs at that temperature, and individual cosmic ray collisions reach and vastly exceed that temperature.

Once again, a car collision on a street is a terrible analogy. The energy densities are astronomically higher, and the collision volume is a vast empty space on particle scales. The first collision is identical to a cosmic ray collision. The second collision is no different, neither is the third, the hundredth, the millionth...

edit: temperature is just a measure of average kinetic energy of the particles in a system. In a LHC collision between two lead nuclei at 2.76 TeV per nucleon or two protons at 7 TeV per proton, and 3 quarks per nucleon, this equates to extreme temperatures, despite the energy involved being utterly unnoticeable on a human scale.

Last edited by cjameshuff; 09-September-2008 at 03:30 PM.. Reason: clarification of temperature
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