Quote:
Originally Posted by chriscurtis
((2^3)^3)^3 = 2^127 not 2^9
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((2^3)^3)^3 = 2^(3^3) = 2^27, not 2^127
And every number in
what chain? 2^F(n), where F(n) is the nth Fibonacci number? F(6) = 8, 2^8 - 1 = 255 = 3*5*17...that is, 2^F(6) is not prime.
Quote:
Originally Posted by chriscurtis
Primes. Use Fi (Fibonacci units where 2 is 11) Fibonnaci has no factors of 2 including square numbers. Every number made up of the Fibonacci sequence is prime.
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2, 8, 34, and 144 occur fairly early in the Fibonacci sequence. They all contain factors of 2, and 144 is a square number.