Quote:
Originally Posted by cjameshuff
((2^3)^3)^3 = 2^(3^3) = 2^27, not 2^127
And every number in what chain? 2^F(n), where F(n) is the nth Fibonacci number? F(6) = 8, 2^8 - 1 = 255 = 3*5*17...that is, 2^F(6) is not prime.
2, 8, 34, and 144 occur fairly early in the Fibonacci sequence. They all contain factors of 2, and 144 is a square number.
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I see where the confusion is 4^(4^(4^(4))) is what I should have written
4 to the power of (4 to the power of (4 to the power of(etc
Is that right? all I mean is you start "backwards" on the calculator in that nothing is multiplied or added together until you've raised the powers to them selves.