I sure hope you do, BA, as it needs someone to handle it properly. Too bad it's not simple, however.

For instance, the gravitational force from F=G*M1*M2/r^2 between me (90kg) and the moon says I am only .0007 lbs. lighter when the moon is overhead. Surprisingly, this same force equation says I am .12 lbs lighter when the sun is overhead. So the Sun's gravitational force is 170x's greater than the moon.

The websites show that tidal forces, however, vary as the inverse cube of the distance not the square. I wish I could find a clear explanation for this.

Also, it appears the horizontal component not the radial component is the main player in an ocean tide.

Here is an animated vector tidal force site that is pretty neat....

>>> Round n Round We Go <<<

For fun, and to use exaggeration to emphasize gravity forces, I used the gravitational equation for a blackhole. If I get within 1/2 million miles of a million sun BH, the force on me becomes 4 billion lbf. The only difference in force for 1 meter closer is only about 10 lbf. However, at 100,000 miles this difference in 1 meter is about 6,000 lbf. Ouch!

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Lighten up! This is a stellar board! Author: duh.

"The Sun, with all the planets revolving around it, and depending on it, can still ripen a bunch of grapes as though it had nothing else in the universe to do..." Author: Galileo supposedly.