_____________________________________B____________ _______________
------------------------------------------LS
_____________________________________A____________ _______________
Okay, let's keep this as simple as possible, mainly because it is so simple...
A and B is stationary with respect to each other, just as Einstein started them out, when he put the light source (LS) halfway between them, so that the beams from that halfway LS could synch both A and B's clocks, when that beam reached A and B simultaneously............so I agree that both A and B's clocks both read 0.
Now, let's say that A and B are both stationary, 10 light seconds apart, with a LS halfway between.
So, when that LS is turned on, it takes five light seconds to get to A and five seconds to get to B, which is when they both set their clocks to 0...
Now, right when the beam gets to B, his clock reading 0, and A's reading 0, it triggers a very bright light on B's helmet to emit a light beam.....that beam then takes 10 seconds to get back to A.
But you think that because both A and B's clocks said 0, simultaneously, that A and B's "Nows" must be simultaneous or together....that you can make two observer's 0's read 0, at the same time...
with no distance considered
Look what Northern Boy did here...
Quote:
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Originally Posted by NothernBoy
Now, you have just stated that we have an event at observer 1 when his clock reads zero. Observer two sees this when his clock reads 2.5 million years, but what of it? He notes this, notes that observer 1 is 2.5 million light years away, and concludes that observer one would have seen it when observer 1's clock read zero.
Given that he knows that the clocks are synchronised, he can go further, and say that, for obserer 2, the supernova happened at T=0 also.
Both observers agree that the supernova happened at T=0, on both of their clocks. How on earth does this invalidate any synchronisation?
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He did NOT synch clocks correctly here, he justs says they are synched...if you followed my 10 light second seperation of two observer's A and B above, this is very easy to figure out! Fifth Grader stuff...
Now, according to Relativity, what is the "Proper Distance" from the emission of that very bright light on B's helmet, according to the stationary observer A?