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Originally Posted by RussT
Okay, let's keep this as simple as possible, mainly because it is so simple...
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simple is always easy
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Originally Posted by RussT
A and B is stationary with respect to each other, just as Einstein started them out, when he put the light source (LS) halfway between them, so that the beams from that halfway LS could synch both A and B's clocks, when that beam reached A and B simultaneously............so I agree that both A and B's clocks both read 0.
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nitpick: A and B
are stationary
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Originally Posted by RussT
Now, let's say that A and B are both stationary, 10 light seconds apart, with a LS halfway between.
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Distance is irrelevant
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Originally Posted by RussT
So, when that LS is turned on, it takes five light seconds to get to A and five seconds to get to B, which is when they both set their clocks to 0...
Now, right when the beam gets to B, his clock reading 0, and A's reading 0, it triggers a very bright light on B's helmet to emit a light beam.....that beam then takes 10 seconds to get back to A.
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Yes, and???????????????????????????????????
so A will see the light beam from B at T=10 sec. Interestingly A has a mirror and shines the light back and B will see the reflection at T=20 sec. What is the frakking big deal here?
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Originally Posted by RussT
But you think that because both A and B's clocks said 0, simultaneously, that A and B's "Nows" must be simultaneous or together....that you can make two observer's 0's seperated by distance read 0, at the same time...
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the both have the same T=0 when the first light arrives. What is so difficult to understand here, what is your problem. You seem to complain about something that is obscured to anyone else here on the board.
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Originally Posted by RussT
He did NOT synch clocks correctly here, he justs says they are synched...if you followed my 10 light second seperation of two observer's A and B above, this is very easy to figure out! Fifth Grader stuff...
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Just because it takes time to go from A to B does not mean that the clocks are not ticking at the same rate with the same T=0. Apparently, you might have to return to the fifth grade. Please spell us out
what exactly your problem is here up to now you have only written stuff that is not in the least interesting.
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Originally Posted by RussT
Now, according to Relativity, what is the "Proper Distance" from the emission of that very bright light on B's helmet, according to the stationary observer A?
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Well, if A knows that both observers set their T=0 in the same way with a light source that is known to be halfway between A and B, then A knows that when he sees B's light at T=10 that the distance is 10 lightseconds, simple 5th grade math. But as usual with your "explanatory skills" you once more seem to imply something here, because suddenly it is "the stationary observer A" which could mean that you somehow think that B is not stationary or whatever.
If you want to make something clear, that obviously nobody here seems to understand, the first thing you need to do is put high value to correct writing skills to unambiguously describe what exactly you want to say.