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Originally Posted by cyrek1
fortis
Can you draw a mathematical picture of how the atom radiates this wavelength?
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Have a look at the link in my earlier quote which contains a derivation of this using QM.
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My visualization sees an electron circling a proton (planetary style) to cause the proton to spin. This proton spin then generates a magnetic field. The electrons magnetic field resulting from its orbital motion interacts with the protons magnetic field. These fields are repulsive towards each other to stabilize the electron into a ground state orbit. As long as there are no nearby charged particles, this balanced state will remain that way.
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But your visualisation doesn't seem to be able to make any quantatitive prediction of the 21 cm wavelength, whereas (as shown in the earlier link) QM does.
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There are free electrons in all parts of space that have been blasted out of the stars during the flaring activity. A wayward electron could be passing a HA in space to knock the electron to its deepest lowest orbital energy state which would weaken the electric attractive interaction between the two particles to make the electron radiate a 21 cm photon as it slowly returns to its ground state.
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Your model would need to explain
why the radiation is at 21 cm and not, for example, 22 cm.
Also, you talk about orbitals. If you look at the orbitals associated with higher angular momentum states (such as d, and, f) you'll see that they are difficult to visualise within the simple planetary model of the H atom.
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I am not interested in the details. The electron is the smallest fragment of electric current. It is measured by the strength of its magnetic fields in its electric circuits.
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Normally in terms of a bulk property, i.e. your classical current is a (relatively) uniform density of electrons moving with some velocity. It is not a single point charge.
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My formulation of the electron at the atomic level is a proper analogy of the ampere definition. I have proven that there is an intrinsic force within the photon fields to justify the intrinsic expansion.
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Do you agree that the definition of the Ampere requires
long wires? It is akin to asking what the electrostatic field due to a point charge is, and answering with the field for a long line of charge. (The first has a 1/r^2 behaviour, while the second does not.) It is not the appropriate expression to use to calculate the field due to a moving point charge.
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Is the Bio-Savart equation necessary to understand the defined experiment of the Ampere?
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Yes, because this equation allows you to calculate the field due to a current in a
long wire. (And also allows you to see how this changes as you make the wire shorter.) Even then, it is only an approximation and to do things properly you should use Maxwell's laws. (Due to the finite speed with which the field propagates.
)