Papageno wrote.
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When the photon is "off-resonance", (electrons+nucleus) act as a classical electric dipole.
Feynman talks about "electron picking up photons" because the electron is the most "mobile" part of the system (electron+nucleus).
It still an interaction between light and atoms.
It is not an interaction with free particles as in a plasma.
This is the point you keep missing.
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I don’t ‘keep missing’ anything. The charges interact by long range coulomb forces. In Papageno’s world, how far apart do electrons protons have to be before there is no forces acting between them and they are free?
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I am not talking here about glass, but about plasma, which is different.
It is your "tired light theory" that envisions the light traveling through IG plasma as a series of scattering events.
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Yes, just as happens in glass and by the same interaction
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Your "double Mossbauer effect" is an ad hoc assumption, because you found out that Compton scattering does not yield the result you were hoping for.
However, your "double Mossbauer effect" is not something that would actually happen in a plasma.
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It is well known and documented that systems of electrons recoil on absorbing and re-emitting photons. This is not ‘ad hoc’ but proven physics.
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Distance effects: the closer the object, the larger the blurring.
It is a statistical effect: the lower the number of scattering events, the stronger the relative effect of fluctuations in the number of these scattering effects.
Typically Doppler effect produces broadening of spectral lines if you have a gas emitting light (like a lamp).
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But one doesn’t get ‘cosmological’ redshifts in nearby galaxies. They have to be in the ‘Hubble flow’ which is several million light years away. The Bb says its ‘local gravitational effects’ I say it could be that but I think it is statistical. Consequently either your point doesn’t apply if it is gravitational, or we are in agreement in that one doesn’t see redshifts because you need a large statistical sample before they are noticeable.
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Anyway, how do you get a red-shift which is the same for all observations of the same object?
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Sigh! See my website I work it all out.
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You do not understand.
The electrons do not need to oscillate back forth, in order for the charge density to oscillate.
That's why I brought up the analogy with sound.
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Aand they do, a displaced electron in a plasma performs SHM about it’s ‘mean’ position.
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lyndonashmore wrote:
papageno wrote:
Do you remember my analogy with sound?
Sound waves in air are oscillations in the density of air molecules.
However, single molecules do not oscillate back and forth.
not the same.
Of course you do not explain what is wrong with my analogy
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What is wrong with your analogy is that atoms in air are electrically neutral. There are no electrical forces between them so they have to literally bump into each other to interact. Hence you get ‘shock waves’. In plasma there are electrical forces which vary with distance and so they provide restoring forces which enable the electrons to perform SHM.
Cheers,
Lyndon