Sylas, we have been through this many times before and time and time again I have shown you where you have gone wrong.
You ignore my responses but keep generating random numbers in an attempt to discredit a perfectly good theory.
Let me remind you once again, Light is a transverse wave. In transverse waves the energy is stored in oscillating electric and magnetic fields that oscillate in a direction perpendicular to that in which the wave travels. A light wave travelling from left to right has momentum from left to right but the
electric fields oscillate up and down. Now when our electron absorbs this chunk of light it recoils from left to right but it oscillates up and down – in the direction of the field and this is where the energy is.
Do we understand that Sylas? If not say so and we will go over it again. If yes then let us look at your first paragraph.
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Originally Posted by Sylas
Here is an example of a quantified energy momentum analysis.
Values for speed of light, Planck's constant, electron charge and mass:
c = 3.00e8 m/s
h = 6.63e-34 kg.m^2/s
e = 1.60e-19 C
m = 9.11e-31 kg
Initial photon, wavelength, energy, and momentum:
λ = 5.00e-7 m
Q = 3.97e-19 J (Q = hc/λ)
p = 1.325e-27 kg.m/s (p = h/λ)
This is the energy and momentum that must remain balanced. If numbers are not given adding up to these values, both for energy and momentum, then the balance has not been shown.
Recoil electron with kinetic energy K after absorbing momentum p
v = 1.46e3 m/s (v = p/m)
K = 9.64e-25 J (K = mv^2/2)
At this point in the analysis, we can balance the momentum, but (1-K/Q) = 99.99976% of the energy is still unaccounted for.
If this energy transfers to the rest of the plasma, then it will require over 400,000 more electrons with the same amount of energy to make up the balance (Q/K = 4.12e5). Energy transfers to the rest of the plasma occur as an electron moves through the electric fields; but the electron cannot transfer more than the energy K of its own motion. The photon is allegedly absorbed; it can't go on and interact with 400,000 more electrons itself.
Thus there is no possibility of energy balance at this point in the interactions.
In real physics, the energy of photo-absorption is actually taken up by excitation of an atom to a new energy level. This is how it occurs in French, and in every published source we have considered on photo-absorption. This is why photo-absorption in real science is for electrons bound to atoms; never for ionized electrons a meter or so away from any other particle.
Cheers -- Sylas
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You have a recoil velocity of 1.46e3m/s and recoil energy of 9.64e-25J. Which is fine and this is the amount emitted as a photon of CMB. But you then come up with a strange idea that somehow, there is a great deal of energy ‘missing’ and somehow the only way that this energy can be transferred to other electrons is by a repetition of the recoil shown above and thus involving 400,000 other electrons – ie longitudinal waves. Utter rubbish!
The ‘missing’ energy is stored in the oscillations of the electron up and down and this is caused by the electric fields of the light wave driving it. This is the energy that is re-emitted as a new photon.
Let’s do this once again, The photon comes in and sets the electron and it neighbours oscillating. This is where most (99.99976%) of the energy goes (to use your figures). The electron recoils in picking up the momentum of the photon and collects 0.00024% of the energy which is radiated as a photon of CMB. On re-emission the energy of the electron oscillations is given out as a new photon with, again, a little lost as CMB in recoil.
How can such sparse plasma involve such an amount of energy, says Sylas? Well let’s do some sums. Instead of involving a cast of millions as Sylas does let’s use just three electrons and give them the whole energy of the photon for good measure. If it works here then it will work anywhere.
The effect we are looking at is a linear one so, to simplify the situation slightly, let’s nail the outer two electrons down and let the middle one absorb the photon and oscillate between them.
Photon comes in from left to right and is absorbed, our middle electron is set into oscillation up and down between our two neighbours above and below it (whilst our electron recoils from left to right). We have done the recoil so let us look at the oscillations. According to Sylas the energy stored in this oscillation is equal to the energy of the photon which is 3.97e-19J. At the center of the oscillation all this energy takes the form of KE so what is the velocity of the electron? Answer is 9.5x10^5 m/s. Not a problem there is there since the random thermal energy gives the electron a velocity of 2.1x10^6m/s? Hardly an exceptional result is it? So there is no problem with the KE, let’s look at the PE.
As the electron oscillates upwards towards the electron above it, that electron repels our oscillating electron and slows it down. KE of electron is converted to electrical potential energy. Let’s work out how far our electrons will be apart when it is brought to rest and all of our photon energy, having been firstly converted to KE is now converted to electrical PE. We will ignore the effects of the lower electron as being negligible at this point.
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[[ Minor grammatical edits applied, and converted some formulae to simpler classical approximations; all numbers remain as original. ]]
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