Quote:
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Originally Posted by Tassel
Quote:
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Originally Posted by Tassel
Continuing to assume for the sake of example that G = 5G at Jupiter (or G=10G...whatever you want), and assuming a radius of approximately 68,000km for Jupiter, can you show how you would calculate the acceleration due to gravity at 68,000km from the center of Jupiter (ie: surface gravity)? I'm interested in the steps you would take to measure the mass of Jupiter (and what value you think that should be), and then the steps you would take to use that mass to determine the acceleration due to gravity.
Perhaps working through an example would help us understand what you are trying to say. |
You keep saying we need "new" kilograms to support (hypothetical, of course...) variable G. So, I'd like to see the practical application of the "variable kilogram" idea.
I'm also still waiting on your definition of "kilogram". |
Sorry I couldn't answer you earlier, but I was catching your posts on the fly in between other projects. Can you be more specific? Please give me an equation to which I can answer, since your question is vague.
The bottom line, if I understand what you're asking, is that 23 meters per second squared is still Jupiter's gravity (at its atmospheric surface), same as now have it. Remember the planet did not change, it's still the same planet, even if its G is different affecting how its mass is measured. Measured in our 1 G postulate for the universe, or measured for its local G, the end result is the same. Please provide me with an equation to address this better. Thanks.