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Old 15-July-2005, 11:20 PM
Metricyard Metricyard is offline
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Quote:
Originally Posted by nutant gene 71

Exactly! So what is Jupiter's "kilograms" per my bold? Is 100 kg on Earth still 100 kg on Jupiter, in (assumed) 5 G? Or is it this same mass now 20 "kg" per Jupiter's 5X (Earth) G? Don't you see that in Jupiter's greater graivtational G "proportional" each kilogram is now five times greater? Of course the end result is the same mass with 100 kg, but can you see the qualitative difference here, or not?
What happens to the other 80kgs? And how does having a larger G replace the missing mass? This is why I think you didn't want to do my little thought experiment. To prove you theory without using any math, you're going to have to remove mass. All you have to do is explain why a larger G would have anything to do with replacing mass.


Quote:
Don't get frustrated about it, but think of what is happpening if a body's gravitational G is different: to arrive at the same kilograms of mass we use on Earth, the "kilograms" of a different G world have to be adjusted for the higher G. There is no getting around this, and this is why the mass acts differently there, because (per above example) each kg.-Earth is now equivalent to 0.2 kg-Jupiter. This is not so confusing, and I'm sure if you can understand Relativity, you can understand a variable G, in fact it's easier!
Why is this easier? You're creating a formula that is way overcomplicated. Why spend so much time to try and prove a variable G and m that's trying to give the same results as a standard formula would?
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