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Originally Posted by Tassel
No.
W = 20kg * 23m/s^2 = 460N which is NOT what we would observe, if we were wrong about G at Jupiter.
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What happened to the 5 G? You're missing it.
(1G*m) = (5G*0.2m)
Your correct example should have read:
W = 5(20kg) * 23m/s^2 = 2300 N.
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Originally Posted by Tassel
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So if you weigh on earth 100 kg (Earth scale), your weight on Earth (at 9.8 m/s^2) is 980 N. If G is 5 times greater on Jupiter, your Jupiter weight woud be five times Earth’s N (times 23 m/s^2), so you would weigh 23 * 4900 N, which now makes you in Newtons force = 112,700 N.
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You are saying that W(Jupiter) is W(Earth) * 5 * g(Jupiter). This is just horrendously wrong. In the real, constant G universe, you don't multiply W(earth) by g(Jupiter) to get W(Jupiter). You multiply the mass of the object by the "g" of the planet you are weighing it on. You further mangle the issue by multiplying by the increase in G, which also makes no sense, since g(Jupiter) already includes G (old or "new"). |
You are correct, my mistake. I had double multiplied Earth's N. The correct version should have been:
W = 100 kg * 9.8 m/s^2 = 980 N for Earth
W = 100 kg * 23 m/s^2 = 2300 N for Jupiter.
That is how we know it in one G. Now, if (1G*m) = (5G*0.2m), for Jupiter's five times higher G, then it should read:
W" = 5(20 "kg" * 23 m/^2) = 2300 N for Jupiter, if you factor in the 5 G.
The way you see it, the 5 G doesn't exist anywhere, and if I did it your way, if I understand what you're saying, factoring in the 5 G, it would look like this:
W'" = 5(100 kg * 23.m^2) = 11,500 N , which is wrong.