Tom2Mars sez,
starship1- I don't know whether to say, "Welcome to the Forum", or "We're not Worthy!"
I'm sorry I missed your first post
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For a one way trip to the the closest star at a constant 1g wrt earth to mid trip point and decelerating at 1 g the remainder of the journey.
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You slipped that in when I had responded to Asei and then spent a few minutes writing about light bulbs.
And your second post...Wow. I'll have whatever StarLab's having right now, and make it a double, then I'll try to absorb some more.
I can tell you've spent some quality time on this.
Again, Welcome.
Star Lab sez,
Umm...Holy C******p!.... :huh:
:wacko:
I'll say it for Tom: Welcome to the forum! We, the members, moderators and administrator, look forward to your input.
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Tom2Mars
I'll have whatever StarLab's having right now.
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I cannot describe in detail what I'm having right now, but it could be one of the following: seizure, shock (& awe), relief, or just plain satisfaction that I'm not the only critical thinker in the entire forum
Starship1 sez
I am blushing
Spike sez,
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Starship1 isn't your first paragraph wrong? This kind of messes up all the other stuff. You can't just use the simple v=at when you approach light speed. As speed increases, mass increases so the energy needs to accelerate also increase.
Ultimately, you need an infinite amount of energy to accelerate to light speed therefore conventional acceleration of any sort cannot do it.
"v=at" only works in the slow, Newtonian world that we normally inhabit.
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Starship sez,
No, It is correct as the relativity equations are derived from Newtonian mechanics equations so relativity is not possible without them.
The effect you refer to is the "infinite energy argument" and it indeed holds true for conventional machines to date and is measured for particle accelerators whose particles are limited to sub light speed as the energy required from the accelerator base frame interacts to accelerate the particle whose relativistic mass increases towards infinity tends towards infinity. This is not the case with all machines such as rockets. Einstein warned do not mix frames of reference in relativity.
The argument fails in non conventional means of accelerating a mass as, in the case of the rocket moving mass to some velocity near c as one only need to eject some mass to accelerate the rocket further and since the energy is provided from the inertial frame of reference instead of a rest frame then the energy tending towards infinity is not observed or measured or calculated.
This can be easily visualized by observing an infinite number of observers outside the rocket traveling an infinite number of velocities each measuring and calculating an infinite number of different relativistic masses. Einstein determined all would then be incorrect as relativistic mass and relativistic energy had no real meaning as there was no absolute velocity or absolute frame of reference. Therefore both the rocket man and the external observer at rest can use the distance traveled and his own clock to calculate different velocities as V=AT. In simple terms Einstein's relativity applied to a car on a race track. Both the official and the driver can calculate the different velocities using their own watches with both velocities being valid eliminating the need for an "official" or proper time from Lorenz's relativity equations.
As he found velocities were relativistic than acceleration was relativistic so he derived the equation for relativistic acceleration in which A'=A times (gamma to the third power) with gamma being the time dilation factor.
Replacing A of 1 g and Plugging that Agamma^3 into Einstein's equations of the given Java calculator from the deasy site the gamma factors in both the denominators and numerators both cancel out so Einstein's relativity equations returns to V=AT permitting one to calculate both light speed and above light speed relativistic effects. It is observed that once the ship meets or exceeds light speed wrt earth the ship disappears from the observer ability to observe.
Emitted or reflected light from a C plus V object travels towards the observer at a constant light speed of C in a vacuum, However since the wave front is traveling at C wrt the ship of c plus v it obtains a minus velocity wrt the observer so traveling away from the observer at some v velocity never to be observed. Light from a rocket at C then would hang in space from where it was emitted. All is normal in space and time aboard the moving rocket at minus C, C and C plus V velocities.
Is that clear and have I answered your question?