Isn't the change in position just = arctan(Earth-Moon distance/Earth - Alpha Centauri distance*)

I know Alpha Centauri is off at an angle, so the change in position is smaller but I digress:

4.5 x 10^5 km/4.3 x 10^13km = 1 x 10^-8

So, whatever arctan(10^-8) is is the apparent difference in a star at 4.3 light years away... so 5.73e-7 degrees or .002 arcseconds.

Certainly measurable, but hardly noticeable.

(Am I doing this right?)






<font size=-1>[ This Message was edited by: Rodina on 2003-01-14 16:02 ]</font>