It occurred to me in the particle creation scenario above that there are two interpretations of frequency of rotation: one, that the frequency is a small fraction of c around a Planck length circumference; and the other, that the frequency is a speed of c around a larger circumference. So for example a proton frequency of ~2.26381e23 Hz would be a rotational speed of c around a circumference of ~8.19415 Planck lengths. And an electron frequency of ~1.2339e20 would be a rotational speed of c around a circumference of ~1.50336e23 Planck lengths.

This give a radius for an electron of ~2.38267e23 Planck lengths, or ~3.8665e-13 meters, which takes the electron farther away from the Bohr radius than it is above. However, there are different radii involved in this scenario. One is the radius at which the particle is created; another is the radius of the particle itself; and a third is the distance between the two particles. There are different possible systems involved; for example, in one system the electron would be an orbital sheath, while in another the electron would have a circular orbit around which it rotated, or would form a circular orbit by its rotation. At this point I do not know which of these systems (if any) will work in this scenario (if the scenario works at all). So I don’t believe the Bohr radius is necessarily ruled out by this interpretation.

However, the interpretation of frequency in which both particles move at c brings up what is to me an even more startling feature than the Bohr radius feature. The product of the two frequencies above for the proton and electron, namely ~2.7933e43 Hz, is extremely close to the ‘Planck frequency’ which I said above would be the limiting frequency in this scenario, namely the inverse, ~1.855e43 Hz, of the Planck time. This would explain why, in this scenario, an electron does not fall into a proton: if their combined frequencies are any greater (their radii any smaller), they will deplete the field. This would also explain why an electron has the frequency it does. However, it does not explain why the proton has the frequency it does. Nor does this scenario yet include a neutron.