Thread: A quantum theory of gravity
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Old 23-October-2006, 03:25 AM
Tensor Tensor is offline
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Originally Posted by Uclock View Post
I assert that the radius of a quantum field generated by a mass-less particle in one second will be equal to ‘c’ or 299 792 458 m giving a volume of V = 4/3*pi*c^3 and here V = Phi = 1.129 x 10^26 m^3 s^-1.

To make this ATM a quantum theory I need a time and space quanta which will be 1/Phi = 1.86 x 10^-27 m^-3 s^-1.
I don't have a lot of time, but this one was glaring. Leaving aside the dimensional values, when I invert the numerical portion of your V (and Phi) value, I get 8.85 X 10-27, not 1.86. Getting back to the dimensional values, how exactly do your dimensional quantities go from m3s-1 to m-3s-1 by inverting them?
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