02-May-2007, 04:26 PM
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Senior Member
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Join Date: Mar 2006
Posts: 1,340
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Quote:
Originally Posted by Bogie
... and see if there is any discussion.
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Quote:
Originally Posted by Bogie
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That answers the question. There is no discussion.
See if this sparks any consternation or appreciation:
If the ground state energy for the electron of a hydrogen atom consisted of a cloud of smaller particles, i.e. EEPs swarming the proton, then the energy of the EEP would be determined by the electron ground state energy of -13.6 eV divided by the number of EEPs in the electron cloud at the quantum state n=1, I think.
If so, using the formula 1 eV = 1.6 × 10–19 J, then the energy in joules of one unifying particle would be the eV of that particle times 1.6 × 10–19 wouldn’t it?
That being the case, then the energy per cubic meter of the perfect background at equilibrium, i.e. the energy density of the greater universe when matter and energy are in balance, would be the joules of one EEP times the number of the EEPs in that volume of space in the greater universe at that density.
Given the landscape of the greater universe in the ISU, some reasonable estimates of the energy of space could be made if the energy of the ground state EEP were known.
Knowing this energy and using the “infinite reach of gravity” explanation, the energy of the gravitational field in a volume of space would be determinable by comparing the energy at ground state of that volume with the energy of the backfill process that is occurring. That is to say, how many EEPs are shifted into that volume of space vs. how many EEPs are shifted out of that volume of space by the presence of the low energy density space surrounding the mass at some distance away. Therefore the energy of the gravitational field would be directly related to the mass of the object causing the gravitational field and inversely related to the distance that a volume of space is from the object.
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