
06-May-2007, 03:48 PM
|
 |
Established Member
|
|
Join Date: Mar 2006
Posts: 1,340
|
|
Quote:
Originally Posted by Bogie
See if this sparks any consternation or appreciation:
If the ground state energy for the electron of a hydrogen atom consisted of a cloud of smaller particles, i.e. EEPs swarming the proton, then the energy of the EEP would be determined by the electron ground state energy of -13.6 eV divided by the number of EEPs in the electron cloud at the ground state (equivalent to n=1 quantum state in QM), I think.
If so, using the formula 1 eV = 1.6 × 10–19 J, then the energy in joules of one unifying particle would be the eV of that particle times 1.6 × 10–19 wouldn’t it?
|
I think this is 5.71 x 10^-27 joules (to be revised as others provide input). Is there some shorthand notation that will let me refer to this value?
Maybe E1 or something?
Quote:
That being the case, then the energy per cubic meter of the perfect background at equilibrium, i.e. the energy density of the greater universe when matter and energy are in balance, would be the joules of one EEP times the number of the EEPs in that volume of space in the greater universe at that density.
Given the landscape of the greater universe in the ISU, some reasonable estimates of the energy of space could be made if the energy of the ground state EEP were known.
|
You may not yet see how having this value relates to the infinite reach of gravity, but …
Quote:
Knowing this energy and using the “infinite reach of gravity” explanation, the energy of the gravitational field in a volume of space would be determinable by comparing the energy at ground state of that volume with the energy of the backfill process that is occurring. That is to say, how many EEPs are shifted into that volume of space vs. how many EEPs are shifted out of that volume of space by the presence of the low energy density space surrounding the mass at some distance away. Therefore the energy of the gravitational field would be directly related to the mass of the object causing the gravitational field and inversely related to the distance that a volume of space is from the object.
|
And any patch of space contains the pattern of the gravitational fields that are coursing through it.
Now put on your thinking caps and go with me for just a second.
Put in your mind the idea that our arena is expanding (that’s an easy one).
Put in there with that thought that when it expands, the energy density of all of the contiguous space in our arena is affected by that expansion (not a radical thought is it?).
Think of the expansion as a process of equalization between two different energy environments, i.e. our arena is one environment, and the greater universe is the other environment (I’m referring to a huge energy density differential between those two environments).
There are EEPs in all of the contiguous space of our arena as the arena expands.
Each of those individual EEPs moves relative to all of the others as the expansion progresses. That may not seem like such a big point but there is a reason why it is significant. The gravitational fields of all of the mass in our arena are influencing the movement of each of the EEPs as the arena expands.
This makes any patch of space in the arena a little GPS device to the extent that if we could plot the movement of each of the EEPs in that patch of space as the arena expands, we could get a picture of all of the gravitational fields that are coursing through it.
Since the reach of gravity is infinite, any patch of space contains a record of the location of all of the objects in the arena. Triangulation using this technique could precisely pinpoint each mass within the triangle.
Last edited by Bogie; 07-May-2007 at 12:28 AM..
|