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  #61 (permalink)  
Old 12-April-2004, 04:06 AM
Sam5 Sam5 is online now
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Originally Posted by Tensor
Can't say that I blame you Russ.
Tensor, since you gave us the brilliant definition of “time” by saying it was the “duration” between “events”, now you can tell us the physical Doppler mechanics of why a moving observer on the rear of a moving train hears a normal pitch of the moving whistle.

And maybe Russ can give us the history of the “atomic clock” concept, starting with Maxwell’s statement about it, going through the Lorentz concept, the Einstein use of “atomic clocks” and the 1938 Ives paper about “atomic clocks”. He told me earlier they were only invented in the 1950s.
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Old 12-April-2004, 04:15 AM
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Well, Russ, tell us the history of “atomic clocks”. What did Maxwell say about them in 1873? Lorentz in 1895? Einstein in 1907 and 1911? Steinmetz in 1923? Ives in 1938?

You are an expert on this topic, so tell us about the history of the “atomic clock” concept.
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Old 12-April-2004, 04:23 AM
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Originally Posted by Sam5
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Originally Posted by Tensor

Are you saying the sound itself moves through the air
NO!

Geepers!

Do you know what an audible “tone” is? Do you know how radio stations can send out audio “tones”? Music is made up of audio tones, audio frequencies. Have you ever heard any music over a radio?

Maybe you call them something different today, but when I hear a 1,000 cycle tone over a radio (ie coming from the radio speaker), I call it a “tone”. It’s coded into the radio waves of the radio signal.

Why would you think that I would think that a spacecraft radio would send out “sound waves”??

Geez!

It can be any frequency of any kind of tone or signal. It can be the frequency of the radio transmitter itself.

You can use a light signal too. You can count the frequencies of the light signal, or you can have the light intermittent, such as 1,000 pulses a second. I used the number 1,000 because it was easy to type.

You might have to excuse me, but I read a lot of 19th Century and early 20th Century books, so if it’s no longer called a 1,000 Hz “tone” that is sent over a radio, then tell me what it is called today. If music is not called "music" anymore, then tell me what it is called.
'Tone' refers to sound. However, radio signals are not sent as sound waves. They're sent as radio waves which carry the information that your radio uses to tell the speakers how to reproduce the sound. Radio transmitters send electromagnetic waves - not tones.

Quote:
Originally Posted by Sam5
For beginners, I wanted to be sure that they understood the term to mean “cycles per second”. I almost said "cycles per second", but I figured you'd nitpick about that.
Actually, 'cycles per second' would have been correct. No nitpicks would have been needed.

Quote:
Originally Posted by Sam5
Do you nitpick when someone writes “$1 million dollars”? Do you complain because they write “dollars” twice?
Usually, yes. If one of my students wrote that on an assignment you're darned right I'd point it out - it's incorrect grammar and sloppy composition.

Quote:
Originally Posted by Sam5
Tensor, since you gave us the brilliant definition of “time” by saying it was the “duration” between “events”, now you can tell us the physical Doppler mechanics of why a moving observer on the rear of a moving train hears a normal pitch of the moving whistle.
Because the observer in the caboose is in the same reference frame as the whistle on the engine and are at rest relative to each other - or if you prefer they're both moving in the same direction at the same speed. The Doppler effect ONLY occurs when you have observers in two different references frames, one of which is in motion relative to the other. In other words, the listener in the caboose won't hear the whistle's pitch change, but the trainspotter sitting near the enbankment will.
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Old 12-April-2004, 04:48 AM
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Quote:
Originally Posted by Taibak
'Tone' refers to sound. However, radio signals are not sent as sound waves. They're sent as radio waves which carry the information that your radio uses to tell the speakers how to reproduce the sound. Radio transmitters send electromagnetic waves - not tones.
They send “tones” coded into the radio waves. I thought everybody knew that already. The radio waves carry the “tone” as a coded signal in the EM waves. The “tone” comes out your speaker on your radio. How difficult is this to understand?

In the radio and television business, a broadcast “tone” is what a test signal is called. It’s like the old CD test tone. Today the weather emergency tone is a kind of squeal. Maybe none of you have ever worked in radio or TV and don’t know the jargon. Maybe the jargon is changed, but what difference does that make. Your are just trying to distract from my description of how the classical Doppler effect works.

Call it “pulses” if you want. A 1,000 Hz pulse sent by radio.

Is the nitpicking night on the board?

And trust me. If I had said "cycles", someone would have complained because I did not say Hz.
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Old 12-April-2004, 04:55 AM
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Originally Posted by Taibak

Because the observer in the caboose is in the same reference frame as the whistle on the engine and are at rest relative to each other - or if you prefer they're both moving in the same direction at the same speed.

Oh Geez! I don’t believe this!

Tell me the PHYSICAL MECHANICAL DOPPLER MECHANISM. What happes in the air, with the waves and the observer. Forget about that “reference frame” Eisnteinian baloney.

You can’t do it, can you? Because you just don’t know how the classical Doppler effect works.

Quote:
Originally Posted by Taibak
The Doppler effect ONLY occurs when you have observers in two different references frames, one of which is in motion relative to the other

No! There are TWO DIFFERENT TYPES OF DOPPLER EFFECTS AT WORK in the train example. One cancels each other out. What are they? Describe them.

Didn't you learn this in your university physics classes?
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Old 12-April-2004, 11:12 AM
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I can tell you what a “relativistic” Doppler effect is if you want to know. It is when an atomic clock on board a spacecraft, that regulates the frequency of the radio signal tone or an electronic device that regulates the radio frequency, has its atomic oscillation rates altered, either by moving through a field (Lorentz theory) or as a result of more or less acceleration or stronger or weaker gravity field (GR theory).
What is the interaction then? The gravitational perturbation on the elctrons?

Is the field in question fixed with respect to the earth, or changing with respect to the earth?
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Old 12-April-2004, 11:21 AM
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For beginners, I wanted to be sure that they understood the term to mean “cycles per second”. I almost said "cycles per second", but I figured you'd nitpick about that.
You made a deliberate mistake, so that beginners would be sure to understand?

That's not the same thing as oversimplifying something so that beginners can understand difficult concepts.
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Old 12-April-2004, 11:22 AM
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This is what I mean by a light pulse clock. A moving observer will measure it to run slow.

An atomic clock has, as you say, atoms oscillating between two states.
I thought you were talking about a type of laser pulse clock.

If you are talking about an imaginary clock, you will get imaginary results.
Really? Aren't the "atomic clocks" of Maxwell and Lorentz et al imaginary? I mean, they didn't actually build the atomic clocks mentioned in their papers, did they?

Is there anything about the light pulse clock that violates any physical laws? It could, in principle be built, right? People usually do things this way - plan something using the laws of physics, etc. and then build it.
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Old 12-April-2004, 12:35 PM
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Tell me the PHYSICAL MECHANICAL DOPPLER MECHANISM. What happes in the air, with the waves and the observer. Forget about that “reference frame” Eisnteinian baloney.
The classical Doppler is purely kinematic in origin. Why are you talking about a "physical mechanism"?
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Old 12-April-2004, 02:02 PM
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Originally Posted by Sam5
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Originally Posted by swansont
This is what I mean by a light pulse clock. A moving observer will measure it to run slow.

An atomic clock has, as you say, atoms oscillating between two states.
I thought you were talking about a type of laser pulse clock.

If you are talking about an imaginary clock, you will get imaginary results.
Really? Aren't the "atomic clocks" of Maxwell and Lorentz et al imaginary? I mean, they didn't actually build the atomic clocks mentioned in their papers, did they?

They didn’t have to build them. They already existed in nature. They were talking about naturally oscillating and glowing atoms. They measured their wavelengths of light by means of a spectroscope and from the known frequency of the light they calculated the oscillation rates of the atoms. They were natural atomic clocks. Haven’t you read the Ives paper, or Maxwell’s treatises on electricity and magnetism?

In Einstein’s 1907 paper, “On the Relativity Principle and the Conclusions Drawn From It,” (“Collected Papers”, paperback Volume 2, page 307), he states,:

“There exist ‘clocks’ that are present at locations of different gravitational potentials and whose rates can be controlled with great precision; these are the producers of spectral lines. It can be concluded from the aforesaid that the wave length of light coming from the sun’s surface, which originates from such a producer, is larger by about one part in two millionth than that of light produced by the same substance on earth.”
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Old 12-April-2004, 02:08 PM
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Is there anything about the light pulse clock that violates any physical laws? It could, in principle be built, right? People usually do things this way - plan something using the laws of physics, etc. and then build it.
In the “light pulse” clock, if the clock is stationary on earth, and a guy drives by it, he is going to see the light pulse go up and down and hit the mirror and the receiver just as the guy on the ground does.

If the observer is stationary with the ground and a guy drives by with a “light pulse” clock, left to right, and if his laser is aimed straight “up”, the pulse will miss the mirror, so he will have to tilt the laser a little to the right so the pulse will hit the mirror. And both guys will see the light pulse travel the same distance, which will be a slightly longer distance than if the guy with the laser were stationary with the ground.
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Old 12-April-2004, 02:13 PM
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Quote:
Originally Posted by Sam5
Tell me the PHYSICAL MECHANICAL DOPPLER MECHANISM. What happes in the air, with the waves and the observer. Forget about that “reference frame” Eisnteinian baloney.
The classical Doppler is purely kinematic in origin. Why are you talking about a "physical mechanism"?
It helps to visualize the classical Doppler effects if you work the mechanics out on graph paper. When the whistle moves through the air, it emits a stretched out sound wave to the rear of the whistle. The wavelength is physically longer as it travels through the air, yet it still travels at the speed of sound in air, about 1,100 fps. So why does the guy riding on the rear of the moving train hear a normal pitch of the longer wave, rather than a redshifted lower pitch?
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Old 12-April-2004, 02:24 PM
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I can tell you what a “relativistic” Doppler effect is if you want to know. It is when an atomic clock on board a spacecraft, that regulates the frequency of the radio signal tone or an electronic device that regulates the radio frequency, has its atomic oscillation rates altered, either by moving through a field (Lorentz theory) or as a result of more or less acceleration or stronger or weaker gravity field (GR theory).
What is the interaction then? The gravitational perturbation on the elctrons?

Is the field in question fixed with respect to the earth, or changing with respect to the earth?

The rate of the atomic clock is affected by its motion through the earth’s gravity field (Lorentz theory), and it is also affected by its altitude (its distance from the center of the earth) (GR theory).

The classical Doppler effect is as I described it earlier. The “relativistic” Doppler effect is the classical effect plus any real effect on the rate of an atomic clock due to its motion through gravity fields and due to the gravitational potential where it is located.

Of course there are other environmental conditions that can make the rate of an atomic clock unstable, but these are generally not called “relativistic” effects.

I’ve read some papers that say the earth’s gravity field does not rotate with the earth but travels through space with the earth. When the spacecraft reaches a certain distance away from the earth, the sun’s gravity field has more influence on the Lorentz effect than the earth’s field.
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Old 12-April-2004, 02:28 PM
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Sam, with all this radio talk you're spouting, do you actually know how a radio works? I mean, the whole mechanism of the LRC circuit, resonance frequency, and the like?
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Old 12-April-2004, 02:28 PM
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Originally Posted by papageno
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Originally Posted by Sam5
Tell me the PHYSICAL MECHANICAL DOPPLER MECHANISM. What happes in the air, with the waves and the observer. Forget about that “reference frame” Eisnteinian baloney.
The classical Doppler is purely kinematic in origin. Why are you talking about a "physical mechanism"?
It helps to visualize the classical Doppler effects if you work the mechanics out on graph paper. When the whistle moves through the air, it emits a stretched out sound wave to the rear of the whistle. The wavelength is physically longer as it travels through the air, yet it still travels at the speed of sound in air, about 1,100 fps. So why does the guy riding on the rear of the moving train hear a normal pitch of the longer wave, rather than a redshifted lower pitch?
If the emitter and the receiver have the same velocity, there is no Doppler effect (the guy on the train is at rest with respect to the whistle, therefore he does not observe a "stretched out" wave).
By the way, one must be careful with Doppler effect: one has to take into account the relative velocity of emitter and receiver and their velocity with respect to the medium. You might get different results for an open train and a closed one.
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  #76 (permalink)  
Old 12-April-2004, 02:40 PM
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If the emitter and the receiver have the same velocity, there is no Doppler effect
There are two Doppler effects at work in my example. I am assuming an open car at the end of the train or an open window. The guy hears the whistle through the outside air. One Doppler effect cancels out the other Doppler effect. Describe the mechanics of both of them.
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Old 12-April-2004, 04:06 PM
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Originally Posted by swansont

Is there anything about the light pulse clock that violates any physical laws? It could, in principle be built, right? People usually do things this way - plan something using the laws of physics, etc. and then build it.
In the “light pulse” clock, if the clock is stationary on earth, and a guy drives by it, he is going to see the light pulse go up and down and hit the mirror and the receiver just as the guy on the ground does.

If the observer is stationary with the ground and a guy drives by with a “light pulse” clock, left to right, and if his laser is aimed straight “up”, the pulse will miss the mirror, so he will have to tilt the laser a little to the right so the pulse will hit the mirror. And both guys will see the light pulse travel the same distance, which will be a slightly longer distance than if the guy with the laser were stationary with the ground.
How do you know which one is moving? Two people, A and B, each with a light pulse clock, are moving relative to each other. No tilting of lasers or anything. No other interactions.


A sees the light pulse hit the mirror in his clock. B sees the light pulse hit the mirror in his clock. What happens when they look at the other's clock? According to your explanation above, it sounds like the light misses. How can one person see the pulse hit, and the other sees it miss?
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Old 12-April-2004, 07:21 PM
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Originally Posted by Taibak
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A classical Doppler shift regarding space and spacecraft is when a moving radio on a spacecraft that is moving away from the earth transmits, let’s say, a 1,000 Hz per second tone signal,
First, a nitpick. A 'Hz/s' is a meaningless unit. Frequency is measured in Hz. You also don't want to use tones - sound can't propagate througha vacuum - you want to use light.
Hz/s isn’t meaningless—it would measure a rate of change in frequency. That makes this particular misuse a bit worse, as a reader quickly skimming the thread (ie, me) might get confused for a while. It is a bit of a nitpick though.

Quote:
Originally Posted by Taibak
Dead wrong. The speed of the signal - which I assume is what you mean by rate - is not changing. The light sent by the spacecraft will still be travelling at 2.998 x 10^8 m/s. The sound coming out of my radio will still be travelling at 331.5 m/s. Both observers will agree on that. The wavelength and the frequency change.
So, am I right in thinking that classical Doppler does not work out with electromagnetic waves because the propagation speed is constant, c? In a physical system, the wave medium is actually in motion altering the relative propagation speed of the wave, whereas light has no physical medium to move.

Quote:
Originally Posted by Tensor
Are you saying the sound itself moves through the air? If so could you please explain why that thousand hz tone takes less than a second to travel from say New York to L.A. instead of the four hours that the sound(which travels at approximately 740 miles per second) should take? Or just perhaps the tone is just a modulated carrier wave moving at c.
The 1kHz tone is carried on a higher frequency carrier wave. If the frequency of the carrier wave changes due to redshifting, the 1kHz tone will be redshifted by the same ratio. So, it is reasonable to say you are transmitting a 1kHz tone, though it does needlessly distract (obviously) from the main argument.
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Old 12-April-2004, 08:20 PM
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So, am I right in thinking that classical Doppler does not work out with electromagnetic waves because the propagation speed is constant, c? In a physical system, the wave medium is actually in motion altering the relative propagation speed of the wave, whereas light has no physical medium to move.
Not entirely. The speed of any wave, including sound, is a property of the medium through which it travels and is independent of the motion of the source and receiver. In classical terms, one way of measuring motion through a medium is to compare the observed speed of a wave to the known propagation speed of that wave in the medium. An observer who is stationary with respect to the medium (again in classical terms) will see the same propagation speed regardless of the source's motion. An observer in front of a car going 60 mph will not measure the speed of sound from the car's horn as 850 mph (if the speed of sound is 790 mph) in front of the car and 730 mph behind it.

Now light doesn't require a physical medium. Rather its speed is determined by the electromagnetic properties of the vacuum, or of any physical medium it travels through. It differs from sound in that all observers observe it's speed as the same regardless of their motion. Thus you can't determine your motion in relation to some medium (call it aether if you want) by measuring the speed of light. This, in effect is what the null result of the MM experiment showed. This, together with the relativistic effects of time dilation and space contraction, complicate the relativitstic doppler effect although the basic idea is the same. Wavefronts are compressed in front of a moving source (blue shift) and lengthened behind it (red shift). You need relativity to determine the precise value correctly.
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Old 12-April-2004, 10:41 PM
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One of the things that causes confusion about the constancy of c is that light exhibits particle behavior as well as wave behavior. The parallel with sound waves, and the constancy of the speed of sound in air regadless of the motion of the source, works fine when you think of light as strictly a wave phenomenon (and ignore the issue of the observer's speed w/r/t the "ether").

However, the parallel doesn't work at all when you think of light as a stream of photons - or "little bullets". Our intuition, based on everyday experience, tells us those photons should go faster "in front of" a moving source, and slower "behind" it.
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Old 13-April-2004, 12:31 AM
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The parallel with sound waves, and the constancy of the speed of sound in air regadless of the motion of the source, works fine when you think of light as strictly a wave phenomenon (and ignore the issue of the observer's speed w/r/t the "ether").
That's not a parallel, is it? After all, for light, each observer would measure the same speed. That's not true for sound.
Quote:
However, the parallel doesn't work at all when you think of light as a stream of photons - or "little bullets". Our intuition, based on everyday experience, tells us those photons should go faster "in front of" a moving source, and slower "behind" it.
Maybe it doesn't work at all, period.
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Old 13-April-2004, 12:50 AM
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Quote:
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The parallel with sound waves, and the constancy of the speed of sound in air regadless of the motion of the source, works fine when you think of light as strictly a wave phenomenon (and ignore the issue of the observer's speed w/r/t the "ether").
That's not a parallel, is it? After all, for light, each observer would measure the same speed. That's not true for sound.
It is if you read EtaC's original scenario carefully. He's talking about an observer who is stationary with the medium (air), and comparing the speed of sound he measures from a source that's moving (i.e. approaching vs. receding). In that case, the observer would measure the same speed of sound in both cases, but a shift in frequency between the two cases.

However, the restriction that the observer must be stationary w/r/t the medium makes it a limited analogy, since that is not a requirement in SR or GR. Lightspeed is always measured the same, regardless of any motion of observer or source.
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Old 13-April-2004, 02:18 AM
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Quote:
Originally Posted by Sam5
Call it “pulses” if you want. A 1,000 Hz pulse sent by radio.

Is the nitpicking night on the board?
Are you kidding? Every night is nitpicking night, here at the BABB. 8)
Quote:
Originally Posted by Sam5
And trust me. If I had said "cycles", someone would have complained because I did not say Hz.
Yes and no. I'd complain, and will complain even now, that you said "cycles" instead of "cycles per second", when the post to which you were responding was clearly and unambiguously speaking of "cycles per second". You're the only one who wants to bring raw, unadorned "cycles" into it, after bringing up "Herz per second" before.
Quote:
Originally Posted by Sam5
What causes this type of Doppler shift is because the transmitter on the spacecraft is sending out 1,000 Hz, but the distance between the earth and the spacecraft increases constantly, so the signal has further and further to travel. This stretches out the wavelength of the signal in space, so that the frequency that is received on earth is only 999 Hz per second. If the spacecraft could stop in space, so that the distance between it and the earth does not increase, then the earth would receive the full 1,000 Hz per second.

If the spacecraft is moving toward the earth and is sending out a 1,000 Hz signal, then the radio wavelengths are compressed, because the distance between the radio and the earth is decreasing, and so the radio on earth receives something like a 1,001 Hz per second signal. This is called a “blueshifted” signal.
Quote:
Originally Posted by Sam5 then
As proof of this theory, we could also use a reflective mirror on a moving spacecraft, and we can have a light pulse signal sent from earth and reflected back from the moving mirror. This way we know that the 1,000 Hz signal never changes at the source, because the source is at the earth and is not moving.

But when the mirror moves away from the earth, and the signal is reflected back, the signal is redshifted and only a 999 Hz per second signal comes back to the earth. When the mirror starts back toward the earth, the reflected light signal becomes blueshifted and the earth receives 1,001 Hz per second.
You don't state that these mirror-bearing spacecraft are moving at the same rate as the transmitting spacecraft, but it would be a reasonable assumption for anyone attempting to learn anything here. So, for their benefit, I'd point out that if they were travelling at the same velocity, Earth would receive first approximately 998 Hz (not per second) as it travels away from Earth, then approximately 1002 Hz on the return trip.
Were it otherwise, you could try to argue your way out of your next speeding ticket by telling the judge that the radar gun manufacturers make radar guns that read twice your actual speed. :wink:
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Old 13-April-2004, 04:09 AM
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d 2022,
I'm working on it. He's got a couple of things within his equations that I have no idea why they are there. He has also referenced something near the end that I'm trying to track down. Bear with me.
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Old 13-April-2004, 02:47 PM
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milli360 milli360 is offline
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Quote:
Originally Posted by Donnie B.
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Originally Posted by milli360
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Originally Posted by Donnie B.
The parallel with sound waves, and the constancy of the speed of sound in air regadless of the motion of the source, works fine when you think of light as strictly a wave phenomenon (and ignore the issue of the observer's speed w/r/t the "ether").
That's not a parallel, is it? After all, for light, each observer would measure the same speed. That's not true for sound.
It is if you read EtaC's original scenario carefully.
I was responding to the "The parallel with sound waves, and the constancy of the speed of sound in air regadless of the motion of the source, works fine" part. It seems to me that the parallel doesn't work fine at all, there.
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Old 13-April-2004, 07:25 PM
d 2022 d 2022 is offline
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Originally Posted by Tensor
d 2022,
I'm working on it. He's got a couple of things within his equations that I have no idea why they are there. He has also referenced something near the end that I'm trying to track down. Bear with me.
Are you talking about this?
Quote:
They took the General Theory of Relativity which Einstein had devised and constructed a "bridge" or "creation tensor" to link the energy of nuclear fields with that of gravitational fields by co-variant matrices.see link
http://au.geocities.com/psyberplasmic/ccX-3-a4.html
The basic relationship of General Relativity which they used as a basis for their system is:

Ruv - .5guvR = 8(Pi)kTuv
Ruv = Ricci's ten-component sub-Riemannian space, curvature tensor
guv = the metric tensor
R = the selected Ricci scalar components
k = a universal constant: proportional to Newton's gravitational constant
Pi = the usual constant: 3.14...
Tuv = the components (potentials) of the energy-stress tensor

Although Deser and Arnowitt's proposed equations were quite difficult to work with, it is assumed that subsequent linear variations - allowing major leaps in human science to develop.

When the Unified Field Theory is finally released to the public, it will be recognized quite easily; for it will have explained why the proton is exactly 1836 times the gravitational mass of an electron,... why there is no neutral mu-meson of mass 200,... why (h) is a constant... and why hc/e2 is always equal to (137)...

The true "Unified Field Theory" will no longer be called a "theory"; it will be known as the "Law of Unity". (snip)
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Old 15-April-2004, 11:09 PM
Aldrin Aldrin is offline
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Default Re: Einstien's Relativity Error

Quote:
Originally Posted by d 2022
The claims of the author after a mathematical demonstration are:
http://au.geocities.com/psyberplasmic/ccX-5.html
Quote:
Looking at the assumption in (Eq. 19)...(ve) was the term used in the beginning to represent the ether wind velocity... This means Einstein used fluid space as a basis for Special Relativity. His failing was in declaring the velocity of light an observable limit to the velocity of any mass when it should only have been the limit to any observable electromagnetic wave velocity in the ether. The velocity of light is only a limit velocity in the fluid of space where it is being observed. If the energy-density of space is greater or less in another part of space, then the relativistic velocity of light will pass up and down through the reference light wave velocity limit - if such exists.
Do not fall into the trap of assuming that this fluid space cannot have varying energy-density. Perhaps, the reader is this very moment saying, an incompressible fluid space does not allow concentrations of energy - but he is wrong - dead wrong!
http://au.geocities.com/psyberplasmic/ccX-5.html

Comments?
edited
In the same link the author gives the reason why no ether was detected.
Because than "the test results cannot prove or disprove the existence of an ether... only whether or not the Earth is moving relative to such an ether."
quote:
In essence, what Michelson, Morley, Einstein, and many other scientists have said is that the M-M test showed the velocity of light was not affected by the Earth's orbital motion. "Therefore" they have said, "we have one of two conclusions to draw":

1) The Earth is orbiting the Sun and there is no ether, or,

2) The Earth is not orbiting the Sun and there is an ether but since the earth is not moving through the ether, the ether "wind" cannot be detected. Obviously, this conclusion is negated by Earth's observed helio-centric orbit.

However, their reasoning should also have incorporated a third option:

3) The Earth is orbiting Ihe Sun and so is the ether; therefore, no ether wind could be detected in the orbital vector immediately in the vicinity of Earth.

In other words, the test results cannot prove or disprove the existence of an ether... only whether or not the Earth is moving relative to such an ether.

RELATIVISTS DISCARD EVIDENCE

By the time the ether wind was proven to exist, Einstein's theories were already winning strong support on the merits of celestial observations which closely agreed with Einstein's predicted values. As a result, the scientific community decided to explain the ether wind phenomenon as a result of Earth's spinning in its own ether blanket which Earth was apparently dragging through space. No explanation was ever agreed upon as to the origin or extent of this ether blanket. It was simply a way to sweep a discrepancy under the carpet.

EINSTEIN ADMITS ERROR...
[quote]
In a biography written just before his death, Professor Einstein is quoted as admitting he had a fundamental error in Relativity. It was, he said, one which-when corrected-will explain how light - an obvious wave form - can be propagated across an apparently non-inertial space. Einstein also stated that the discovery of the solution to this error would probably be the result of some serendipitous discovery in the sixties. However, before he died, Einstein did manage to partially correct his error. With the help of the well-known Dr. Erwin Schrödinger, Dr. Einstein was able to construct a 'total theory' for existence. It was called the "Unified Field Theory". Although Dr. Einstein was able to lay the basic framework before his death, it is reasonably certain that a more readily-usable version of the "Unified Field Theory" was only completed by other physicists after Einstein had died.

One of the more promising contributions toward a usable unified field theory was offered by Dr. Stanley Deser and Dr. Richard Arnowitt (see Appendix 4 of The Gravities Situation in Appendix (3) of this book). They took the General Theory of Relativity which Einstein had devised and constructed a "bridge" or "creation tensor" to link the energy of nuclear fields with that of gravitational fields by co-variant matrices. The basic relationship of General Relativity which they used as a basis for their system is:

discuted in your last post above.
  #88 (permalink)  
Old 15-April-2004, 11:17 PM
russ_watters russ_watters is offline
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Default Re: Einstien's Relativity Error

Quote:
Originally Posted by Aldrin
1) The Earth is orbiting the Sun and there is no ether, or,

2) The Earth is not orbiting the Sun and there is an ether but since the earth is not moving through the ether, the ether "wind" cannot be detected. Obviously, this conclusion is negated by Earth's observed helio-centric orbit.

However, their reasoning should also have incorporated a third option:

3) The Earth is orbiting Ihe Sun and so is the ether; therefore, no ether wind could be detected in the orbital vector immediately in the vicinity of Earth.

In other words, the test results cannot prove or disprove the existence of an ether... only whether or not the Earth is moving relative to such an ether.
Problem: If the ether can't be detected by any experiment we do (we've done thousands, both on and off the surface of the earth), how is it ok to assume it exists? All I keep seeing is that as the various ether theories are proven wrong by new evidence, the theories get more and more convoluted to account for the new evidence. Never is there any positive evidence of an ether, just evidence that doesn't quite rule it out. Its epicycles all over again.
Quote:
RELATIVISTS DISCARD EVIDENCE

By the time the ether wind was proven to exist...
What exactly is the evidence that there is an ether?

Remember again: evidence must be positive, ie, if it can be explained without resorting to an ether, it is not evidence for an ether. That's the way science works.
  #89 (permalink)  
Old 15-April-2004, 11:26 PM
daver daver is offline
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Default Re: Einstien's Relativity Error

Quote:
Originally Posted by Aldrin
3) The Earth is orbiting Ihe Sun and so is the ether; therefore, no ether wind could be detected in the orbital vector immediately in the vicinity of Earth.
Presumably this ether is also spinning with the earth (so that all spots on the earth surface, whether on the day side or the night side) are motionless with respect to the ether--this is fairly peculiar, as this means that the ether near the earth's surface is moving at much less than earth orbital velocity.

This ether is peculiar stuff. It is apparently orbiting the sun in the plane of the ecliptic in the direction of motion of the planets, so, presumably, as long as the planet had a zero inclination zero eccentricity orbit it would be motionless with respect to the ether (well, provided it was rotating in the same direction as the rest of the planets). It's not too clear what happens outside the ecliptic--is there no ether there? Regardless, planets with measurable eccentricities (such as Mercury) should never be motionless with regard to the ether wind, so MM experiments there should show a positive result. Similarly, interplanetary probes on elliptical orbits (and especially those with highly inclined orbits) should show unexpected shifts in frequency due to their having a non-zero velocity with respect to the ether wind. I haven't worked through the numbers here, but it might be that some of these results would be measurable.
  #90 (permalink)  
Old 15-April-2004, 11:26 PM
Aldrin Aldrin is offline
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Default Re: Einstien's Relativity Error

Quote:
Originally Posted by russ_watters
Quote:
Originally Posted by Aldrin
1) The Earth is orbiting the Sun and there is no ether, or,

2) The Earth is not orbiting the Sun and there is an ether but since the earth is not moving through the ether, the ether "wind" cannot be detected. Obviously, this conclusion is negated by Earth's observed helio-centric orbit.

However, their reasoning should also have incorporated a third option:

3) The Earth is orbiting Ihe Sun and so is the ether; therefore, no ether wind could be detected in the orbital vector immediately in the vicinity of Earth.

In other words, the test results cannot prove or disprove the existence of an ether... only whether or not the Earth is moving relative to such an ether.
Problem: If the ether can't be detected by any experiment we do (we've done thousands, both on and off the surface of the earth)snip
But the ultimate test must be done far away of the vinicity of the Earth based on option 3
3) The Earth is orbiting Ihe Sun and so is the ether; therefore, no ether wind could be detected in the orbital vector immediately in the vicinity of Earth.
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