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  #331 (permalink)  
Old 23-May-2005, 09:53 AM
lyndonashmore lyndonashmore is offline
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Originally Posted by Fram
Quote:
Originally Posted by lyndonashmore
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As you say that your paper has been accepted for publication in a peer reviewed journal, I would assume that they would have spotted this, so perhaps I have misunderstood why you are calling it the Mossbauer effect. :)
All I can say is that the paper has been peer reviewed several times - including by journals that even Sylas would not libel, and whilst they have whinged at this or that, no one has ever complained about the use of Mosssbauer.
That said, we seem to spend so much time arguing over the name, I am coming to the conclusion that it may be prudent to drop it to concentrate peoples attention on the real issues.
Cheers,
Lyndon

It has been peer reviewed and rejected several times, I assume. Can you give us the reasons they did? That may be interesting.
And when has it been published? I've only seen the mention that it has been accepted (in september, I believe), but no mention of the actual publication yet.
Finally, what Sylas said was not libel, it was an opinion (and an informed opinion at that, as it was based on articles actually published by the magazine).
Not as intersting as you might think because no matter what some people say about me I do listen. As a consequence whenever a peer reviewer complained about some aspect I did more research and corrected it. For instance, at the beginning I knew that the collision cross section had to be 2r(lamda) for the whole thing to work. I came up with a logical argument as to why this had to be so but the paper was quite rightly rejected "until I had published cross sections". I carried on researching the literature and then I found the Lawrence Bragg labs had published it ... and so on. towards the end, I would submit it there would be a long wait (up to six months) and then a sorry but with no reason and then it was finally accepted.
Proof copies have been done, end of this year beginning of next.
Got to go and earn some money now, see yah!
Cheers,
Lyndon
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Old 23-May-2005, 10:40 AM
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So it has been peer reviewed by journals 'even Sylas would not libel', but the final version will not appear in one of those.
I'm sceptical of this explanation.
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  #333 (permalink)  
Old 23-May-2005, 10:41 AM
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Quote:
Originally Posted by Grey
Quote:
Originally Posted by Sylas
Yes... I considered this also, in this post. There are some other conservation laws and principles that may apply, and I'm not good enough at quantum physics to identify them.
Tobin's right, you'll run into problems with spin. A photon has a spin of 1, so there's no way to conserve spin in an interaction that starts with one photon and one electron and ends up with two photons and one electron.
I think that the idea came up already, and it involved three outgoing photons.
My issue with this idea was its likelihood.
Somebody explained that these probabilities go like (1/alpha)^N, where N is the number of photons and alpha is the coupling constant for \coulomb interaction.
So, an interaction involving three photons is (1/alpha)^2 ~ 5*10^(-5) times less likely than a process with only one photon.

Quote:
Originally Posted by Sylas
Does anyone have a physically sensible model for the forces that will be felt on a particle from its neighbours within the Debye sphere? It should be a continuously changing force as nearby particles are moving with the termal energy, a bit like a Brownian motion, but from electrical interactions.
Considering that the electrons are distributed nearly uniformly, the net force tend to cancel out (which is why the electrons in a plasma can be considered free).
The potential energy of an electron is nearly constant, and usually the potential is substituted by its average value (you could look up Hartree and Hartree-Fock approximation).
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  #334 (permalink)  
Old 23-May-2005, 10:42 AM
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Hi Lyndon
I thought about your Tired Light. Every Neutron Star or Black Hole produce electron-positron pairs. They use a transformation of the energy into matter.
It could be possible that in enormous Cosmic space are many AGN, magnetars and they absorb matter and energy, transform energy into ejected matter and make a kind of the redshift.
I do not think , the whole redshift is caused by this energy-matter transformation, but may be a part of it ?
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Old 23-May-2005, 10:42 AM
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Quote:
Originally Posted by lyndonashmore
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Originally Posted by Fram
What makes the cubic metre of space so special? Why not a cubic kilometre? After all, the Hubble constant is only a number per second, so cubic metres have nothing to do with it anymore than cubic inches or cubic lightyears.
Then use the full form of "why is H = 2nhr/m", it is fine by me.
Cheers,
lyndon
Thanks for not answering.
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  #336 (permalink)  
Old 23-May-2005, 10:49 AM
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Originally Posted by lyndonashmore
I would suggest that you edit your last post Sylas. To refer to a named third party in such a way is unfair to them and sounds like sour grapes on your part, rather than informed discussion. This said, I will not address any points of this nature again.
Sylas expressed the same opinion I have expressed before.
The reviewers working for Galilean Electrodynamics are incompetent for not spotting the obvious errors, misapplied formulae and unsubstantiated claims in your paper.
Publishers of a journal with a stated bias against well established theories, should at least bother to have proper scientific standards for the papers they accept.
Unfortunately they do not and seem to prefer style over substance, and make a mockery of proper scientific journals, hence calling them "clowns" is appropriate and justified.
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  #337 (permalink)  
Old 23-May-2005, 11:05 AM
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Originally Posted by lyndonashmore
Not as intersting as you might think because no matter what some people say about me I do listen.
Your actions on this board (and this very post) contradict your words.

Quote:
Originally Posted by lyndonashmore
As a consequence whenever a peer reviewer complained about some aspect I did more research and corrected it. For instance, at the beginning I knew that the collision cross section had to be 2r(lamda) for the whole thing to work. I came up with a logical argument as to why this had to be so but the paper was quite rightly rejected "until I had published cross sections". I carried on researching the literature and then I found the Lawrence Bragg labs had published it ... and so on.
Following the link in the references of your paper we find:
Quote:
These (semi-empirical) atomic scattering factors are based upon photoabsorption measurements of elements in their elemental state. The basic assumption is that condensed matter may be modeled as a collection of non-interacting atoms. This assumption is in general a good one for energies sufficiently far from absorption thresholds. In the threshold regions, the specific chemical state is important and direct experimental measurements must be made. Note also that the inelastic Compton scattering cross section (from ref. 2) has been included in the transmission calculations of a solid and of a gas but not in the others. The Compton cross section is significant for the light elements (Z < 10) at the higher energies considered here (10 keV to 30 keV).
Ashmore was never able to justify the use of these formulae for a rarified plasma and the interaction between a free electron and a photon.
It is the same error he comits when he equates plasma with glass.


Quote:
Originally Posted by lyndonashmore
towards the end, I would submit it there would be a long wait (up to six months) and then a sorry but with no reason and then it was finally accepted.
Proof copies have been done, end of this year beginning of next.
Wasn't your paper accepted at the beginning of 2004? (This was the reason for starting the other thread.)
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  #338 (permalink)  
Old 23-May-2005, 11:13 AM
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Originally Posted by papageno
Quote:
Originally Posted by lyndonashmore
I would suggest that you edit your last post Sylas. To refer to a named third party in such a way is unfair to them and sounds like sour grapes on your part, rather than informed discussion. This said, I will not address any points of this nature again.
Sylas expressed the same opinion I have expressed before.
The reviewers working for Galilean Electrodynamics are incompetent for not spotting the obvious errors, misapplied formulae and unsubstantiated claims in your paper.
Publishers of a journal with a stated bias against well established theories, should at least bother to have proper scientific standards for the papers they accept.
Unfortunately they do not and seem to prefer style over substance, and make a mockery of proper scientific journals, hence calling them "clowns" is appropriate and justified.
Well, why not lead by example and give everyone here a link to one of your published papers - so we can all see how it is done - one where you are the sole author would be best.
That would be a great help.
Thanks
Lyndon
  #339 (permalink)  
Old 23-May-2005, 11:27 AM
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Quote:
Originally Posted by lyndonashmore
Back of the envelope calculations are fine if the estimates used have some meaning. I have pointed out such areas in Sylas' calculations already - time of impact for one.
But you do not give quantitative estimates of your own, and besides hand-waving you do nothing to show he was wrong.

Quote:
Originally Posted by lyndonashmore
Remember, there are 'sticky' patches on the back of every envelope and this is one for Sylas. As a result, one can't do that here until one has a good physical reason for coming up with a ball park figure.
So, that's why you never give quantitative estimates for your "mechanism".

Quote:
Originally Posted by lyndonashmore
What to do then if back of envelopes are out?
Simple, suck it and see!
That is try it and see what you get. If your final answer is way out then you know the effect does not work.
So, your "effect" does not work.

Quote:
Originally Posted by lyndonashmore
So, lets do a "proof of the pudding is in the eating" analysis.
I say the effect works, Sylas says it does not so lets assume it does for a moment and try it.
Increase in wavelength on each absorption and re-emission is h/mc - the compton constant.
You keep cliaming that it is not Compton effect.
Why do use this constant?

Quote:
Originally Posted by lyndonashmore
The published result for the photoabsorption collision cross section is 2rλ.
You still have not justified using this formula for electrons in a plasma.

Quote:
Originally Posted by lyndonashmore
Putting this into our calculation the total shift in the wavelength for a photon travelling a distance, d, can be found and hence the redshift.
For astronomically 'small' distances (z less than 0.2) we get H = 2nhr/m.
We know h, r and m for the electron already so we will look up what other scientists are using for n and that is 0.1 to 10 electrons per cubic metre. For H = 72 km/s per Mpc, n should be about 0.6 per cubic metre. This result is certainly consistent if not even pretty good. Notice that the only thing we have assumed is that the electron oscillates and tales up the energy - everything else is 'known' physics and published by scientists other than I. Once you accept that it works everything falls into place.
Except that your " the electron oscillates and tales up the energy" is an unphysical process in the case of a free electron in a plasma.


Quote:
Originally Posted by lyndonashmore
The proof of the pudding is in the eating.
But cry the cynics, it could be a coincidence? Maybe, so what to do?
The proof of the pudding is in the eating.
We tried it, and it did not taste very good.


Quote:
Originally Posted by lyndonashmore
What about large distances? Well since the wavelength of the photon redshifts as it travels, the collision cross section increases as it travels and this gives us an exponential hubble diagram. That is, accept the electron takes up the energy and one not only get a good match with the value of H but one gets the exponential nature of the Hubble diagram too. I had this long before it was 'accepted' that the Hubble diagram has an exponential nature - the Bb had to drag in inflation.
The proof of the pudding is in the eating.
But, Cry the cynics, that could be coincidence too.
What do we do?
The proof of the pudding .....
You still use the "broken record" tactic.


Quote:
Originally Posted by lyndonashmore
Lets have a look at the energy transferred to the recoiling electron. How much energy is transferred there. The plasma will reach thermal equilibrium eventually and re radiate this. What will the wavelength of the photons be?
I see that you do not give any numbers.


Quote:
Originally Posted by lyndonashmore
Shock horror, its in the microwave and here we have all this CMB. That is, accept the electron takes up the energy and one not only get a good match with the value of H and the exponential nature of the Hubble diagram but one gets the CMB too!
and on and on till we are totally sickof pudding.
This is the difference. Sylas trumps up 'estimates' with no physical meaning, does a calculation and says the theory is wrong. But is he generating random numbers?
Sylas justified his quantitative estimates.
You, on the other hand, have not justified any of your hand-waving.


Quote:
Originally Posted by lyndonashmore
I try it and find it works excedingly well.
The proof of the pudding is in the eating.

Quote:
And do you really still think it's meaningful to compare H and hr/m directly, even though they do not have the same dimensions?
Yes, because I compare H and 'hr/m in each cubic metre of space'
That is, just why is the measured value of the Hubble constant equal to 'this much (hr/m) of an electron in each cubic metre of space? This statement reaks of Tired Light. I say that redshift is due to photons interacting with electrons in IG space as they travel and then we find
"the measured value of the Hubble constant is equal to 'this much (hr/m) of an electron in each cubic metre of space".
So, an equation that "works" only with specific units.
Sounds like numerology, not physics.


Quote:
Originally Posted by lyndonashmore
The question you should be asking is
"If the hubble constant has nothing to do with the electron why is the measured value of the Hubble constant equal to 'this much (hr/m) of an electron in each cubic metre of space?"
The answer is: Ashmore played around with constants until he got that result. As I sadi, numerology, not physics.
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  #340 (permalink)  
Old 23-May-2005, 11:30 AM
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Quote:
Originally Posted by lyndonashmore
Quote:
Originally Posted by papageno
Quote:
Originally Posted by lyndonashmore
I would suggest that you edit your last post Sylas. To refer to a named third party in such a way is unfair to them and sounds like sour grapes on your part, rather than informed discussion. This said, I will not address any points of this nature again.
Sylas expressed the same opinion I have expressed before.
The reviewers working for Galilean Electrodynamics are incompetent for not spotting the obvious errors, misapplied formulae and unsubstantiated claims in your paper.
Publishers of a journal with a stated bias against well established theories, should at least bother to have proper scientific standards for the papers they accept.
Unfortunately they do not and seem to prefer style over substance, and make a mockery of proper scientific journals, hence calling them "clowns" is appropriate and justified.
Well, why not lead by example and give everyone here a link to one of your published papers - so we can all see how it is done - one where you are the sole author would be best.
That would be a great help.
I see that you do not shy away from ad hominem attacks.
I have explained on this board what is wrong with your "theory".
I justified my low opinion about that journal.
Whether I am author of a paper published in a proper peer-reviewed journal is irrelevant.

The burden of proving your "theory" right is yours.
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"...because the logic of the lines traced from reality is as poor of aesthetic value as it is strict in consistency. " - Paolo Bozzi (Naive Physics - free translation)
  #341 (permalink)  
Old 23-May-2005, 02:36 PM
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Quote:
Originally Posted by Fram
What makes the cubic metre of space so special? Why not a cubic kilometre? After all, the Hubble constant is only a number per second, so cubic metres have nothing to do with it anymore than cubic inches or cubic lightyears.
Quote:
Originally Posted by lyndonashmore
Then use the full form of "why is H = 2nhr/m", it is fine by me.
I believe papageno has properly addressed your other points (and this one as well), but I'll ask again. Since you acknowledge that it's completely arbitrary without the 2n (since the similarity of the two numbers depends on the system of units chosen), why do you still maintain (as you seem to) that it's meaningful to compare H with hr/m?
  #342 (permalink)  
Old 23-May-2005, 02:50 PM
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Originally Posted by MrObvious
Sorry to interrupt here, but, I've been following these threads for some time now and though I'm no physisist I know as an engineer that if a formula doesn't work with different units then there is a problem with the formula no matter how much evidence seems to point to it being correct. AFAIK Ashmores theory fails on that front. Till it can pass that test it can't be considered anything more than coincidence. If it passed that test it would be worthy of serious concideration. I doubt that anyone would dismiss it so lightly if it did. Till we can agree on at least that part then it will be an never ending circle of speculation IMHO.

Just my 2 cents worth, back to lurking mode now......
I'm an engineer, too. And, what is said here is correct. For a formula - any formula - to be correct, it must hold true in all internally consisent systems of units. (I had a professor who made us understand this by solving problems set on Mars and using units of furlongs per fortnight. Danged if it didn't work!)

So, lyndon, would you please translate H = 2nhr/m into another internally consistent system of units? (You can use English units if you want; the furlongs thing was Dr. Schechter's idea.)

Also, as an engineer, I am used to approximations. ("Ten percent is close enough for engineering.") But, your margin is 100x; isn't that a bit large to claim success?

And I'll rejoin MrO on the sidelines for awhile.

(fixed a spelling error... hey, speling dusn't count in enjuneering!)
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  #343 (permalink)  
Old 23-May-2005, 02:55 PM
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Quote:
Originally Posted by Grey
Quote:
Originally Posted by Fram
What makes the cubic metre of space so special? Why not a cubic kilometre? After all, the Hubble constant is only a number per second, so cubic metres have nothing to do with it anymore than cubic inches or cubic lightyears.
Quote:
Originally Posted by lyndonashmore
Then use the full form of "why is H = 2nhr/m", it is fine by me.
I believe papageno has properly addressed your other points (and this one as well), but I'll ask again. Since you acknowledge that it's completely arbitrary without the 2n (since the similarity of the two numbers depends on the system of units chosen), why do you still maintain (as you seem to) that it's meaningful to compare H with hr/m?
Hi Grey, I was just about to post an answer to this to Fram as i was a bit rushed earlier - so this is for both of you.
Numerical coincidences are important. They really are because they can point you to a relationship.
Both Weber and Kirchoff independently measured the speed of an electrical pulse down a wire and found it to be 3x10^8 m/s. They said, "Ah! its just a coincidence" and forgot about it. Both of them. It was left to Maxwell to realise the relationship.
One cannot discount a 'coincidence' numerical or otherwise, as a 'coincidence' without making absolutely sure that there is nothing in it.
In the BB, H and the electron are not supposed be related and yet H and hr/m ane numerically the same. Supporters of the Bb must make sure that there is nothing in it before they discount it. Some Followers of the BB on this board have done just that - discounted it without further thought. And yet they have used the electron and h in their determination of the Hubble constant. Before followers of the Bb discount something like this they must work out the probability of it happening, and it is a very small probability of it happening by chance.
In Tired Light I show H = 2nhr/m so we ask what is the probability of H = hr/m by chance? And its is fairly likely because they are related.
So, if it is fairly likely for this coincidence to happen in tired light and very unlikely for it to happen in the Bb - And it does happen, then which theory is more likely to be right? Answer is Tired Light.
So, yes, it is a result to quote. Even though it is units based the probabilities show that Tired Light is more likely to be correct than the Bb
Does that answer your question?
Cheers,
Lyndon
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Old 23-May-2005, 03:15 PM
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Quote:
Originally Posted by Jim
Quote:
Originally Posted by MrObvious
Sorry to interrupt here, but, I've been following these threads for some time now and though I'm no physisist I know as an engineer that if a formula doesn't work with different units then there is a problem with the formula no matter how much evidence seems to point to it being correct. AFAIK Ashmores theory fails on that front. Till it can pass that test it can't be considered anything more than coincidence. If it passed that test it would be worthy of serious concideration. I doubt that anyone would dismiss it so lightly if it did. Till we can agree on at least that part then it will be an never ending circle of speculation IMHO.

Just my 2 cents worth, back to lurking mode now......
I'm an engineer, too. And, what is said here is correct. For a formula - any formula - to be correct, it must hold true in all internally consisent systems of units. (I had a professor who made us understand this by solving problems set on Mars and using units of furlongs per fortnight. Danged if it didn't work!)

So, lyndon, would you please translate H = 2nhr/m into another internally consistent system of units? (You can use English units if you want; the furlongs thing was Dr. Schechter's idea.)

Also, as an engineer, I am used to approximations. ("Ten percent is close enough for engineering.") But, your margin is 100x; isn't that a bit large to claim success?

And I'll rejoin MrO on the sidelines for awhile.

(fixed a spelling error... hey, speling dusn't count in enjuneering!)
Hi Jim,
I am very strict on units too. I have explained above the importance of the 'numerical coincidence' H = hr/m in magnitude.
I could if you really insisted,
Quote:
So, lyndon, would you please translate H = 2nhr/m into another internally consistent system of units?
but it could take a while so try this first.
In 2nhr/m, n has dimensions (L^-3), h is energy multiplied by time (h = E/f)
and so has dimensions (ML^2T^-1) r has dimensions of (L) and Mass has dimensions of M
so 2nhr/m is dimensionally T^-1 or 'per sec'.
On the other hand, H is km/s per Mpc. Both km and Mpc are lengths so this too has dimensions of T^-1 or per sec.
So you see Jim H = 2nhr/m is perfectly correct in units.
What is strange is the Bb interpretation, 'km/s per Mpc'.
Why use two different units for distance in the same relation. Why not km/s per km? Or Mpc/sec per Mpc?
You see H is not a 'velocity' at all, it is a rate - a 'per sec'
I believe they use these units (which would have your professor tearing his hair out) to confuse people - to con them into thinking that distant galaxies are moving away from us. The units of H have nothing to do with 'velocity' at all. It is not km/s per Mpc, not km/s per km nor is it Mpc/s per Mpc it is 'per sec'. There is no velocity in it at all.
So you see Jim, it is not I who has my units wrong it is the BB.
Cheers,
Lyndon
PS if you still want the formula H = 2nhr/m in imperial let me know - it still works.
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Old 23-May-2005, 03:21 PM
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Originally Posted by lyndonashmore
So, yes, it is a result to quote. Even though it is units based the probabilities show that Tired Light is more likely to be correct than the Bb
Does that answer your question?
I still don't see how this follows. Suppose the metric system had never been invented and the yard was an unpopular unit, so that we used the foot as our primary distance measurement. In that case, hr/m and H wouldn't be anywhere close, right? So how can this possibly indicate something fundamental about the universe?
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Old 23-May-2005, 04:47 PM
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Quote:
Originally Posted by Grey
Quote:
Originally Posted by lyndonashmore
So, yes, it is a result to quote. Even though it is units based the probabilities show that Tired Light is more likely to be correct than the Bb
Does that answer your question?
I still don't see how this follows. Suppose the metric system had never been invented and the yard was an unpopular unit, so that we used the foot as our primary distance measurement. In that case, hr/m and H wouldn't be anywhere close, right? So how can this possibly indicate something fundamental about the universe?
Depends how you look at it. The paradox - H has the same magnitude to hr/m is not, by itself, fundamental to the universe. It is a 'quirk' of nature that is a 'nice' coincidence. It is when one takes the whole thing together that it becomes 'fundamental'.
The Bb is based largely on redshifts and the CMB and here we have a theory that not only explains them but calculates their value. There is no need for the BB anymore.
The paradox is a 'result' a 'quirk' but the whole thing ( H = 2nhr/m, the CMB ) is what one has to look at,
Cheers,
Lyndon
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Old 23-May-2005, 05:08 PM
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This may be just me, but... We wouldn't have known to look for a CMB w/o GR and QM... right? :-?
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Old 23-May-2005, 05:13 PM
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Originally Posted by Grey
Suppose the metric system had never been invented and the yard was an unpopular unit, so that we used the foot as our primary distance measurement. In that case, hr/m and H wouldn't be anywhere close, right?
While hr/m and H wouldn't be close in that case, hr/m per cubic metre and H would still be the same because both have units of 1/s. Lyndon seems to use hr/m per cubic metre in his paradox, not hr/m, at least according to his website.
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Old 23-May-2005, 05:17 PM
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This may be just me, but... We wouldn't have known to look for a CMB w/o GR and QM... right? :-?
No, McKellar 'prediscovered' the CMB in 1945 (ish) at 2.73K and published it. The followers of the Bb ignored this and claimed the 1968 rediscovery because it suited them.
Cheers,
Lyndon
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Old 23-May-2005, 05:19 PM
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Originally Posted by lyndonashmore
The paradox - H has the same magnitude to hr/m is not, by itself, fundamental to the universe. It is a 'quirk' of nature that is a 'nice' coincidence.
So you agree then that it is in fact just a coincidence of no particular significance, which perhaps sent you off in the direction you went with your ideas, but is of no importance by itself?
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Old 23-May-2005, 05:23 PM
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Originally Posted by lyndonashmore
The paradox - H has the same magnitude to hr/m is not, by itself, fundamental to the universe.
It is a numerical coincidence, because the equality does not hold in any system of units.
Hence it is not a physical relation (let alone fundamental).

Quote:
Originally Posted by lyndonashmore
It is a 'quirk' of nature that is a 'nice' coincidence. It is when one takes the whole thing together that it becomes 'fundamental'.
The Bb is based largely on redshifts and the CMB and here we have a theory that not only explains them but calculates their value. There is no need for the BB anymore.
Where is your calculated spectrum of the CMB? (Peak wavelength is not the spectrum.)
Without it you cannot claim that your "theory" is better.

Quote:
Originally Posted by lyndonashmore
The paradox is a 'result' a 'quirk' but the whole thing ( H = 2nhr/m, the CMB ) is what one has to look at.
The whole thing is based on a mechanism which has been proven to be unphysical, hence it is unsupported and unfounded.
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Old 23-May-2005, 05:27 PM
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Originally Posted by lyndonashmore
Quote:
Originally Posted by TravisM
This may be just me, but... We wouldn't have known to look for a CMB w/o GR and QM... right? :-?
No, McKellar 'prediscovered' the CMB in 1945 (ish) at 2.73K and published it. The followers of the Bb ignored this and claimed the 1968 rediscovery because it suited them.
Cheers,
Lyndon
McKellar he determined a "rotational" temperature of 2.3 K for the gas of interstellar space where CN absorption takes place. http://www.badastronomy.com/phpBB/vi...ht=1941#461762
Later, George Gamow and his colleagues Ralph Alpher and Robert Herman predicted the CMB temperature at around 5K.

Still beggs me to ask how your theory comes up with the spectrum? Or even the need to look for one, other than the fact that the BB already predicted it for yas...
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Old 23-May-2005, 05:52 PM
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Quote:
Originally Posted by lyndonashmore
Hi Jim,
I am very strict on units too. I have explained above the importance of the 'numerical coincidence' H = hr/m in magnitude.
I could if you really insisted,
Quote:
So, lyndon, would you please translate H = 2nhr/m into another internally consistent system of units?
Oh, I insist.

Quote:
... so try this first. ...
Smoke and mirrors, lyndon. Added: It's not that you can get any form to reduce to 1/sec, you need to show that the Hubble Constant in any given set of units will give the same numerical value as 2nhr/m in those same units.

Quote:
PS if you still want the formula H = 2nhr/m in imperial let me know - it still works.
Please show us. And please show all your work.

Start with the value for H in Imperial units.
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Old 23-May-2005, 08:39 PM
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Originally Posted by Jim
Quote:
PS if you still want the formula H = 2nhr/m in imperial let me know - it still works.
Please show us. And please show all your work.

Start with the value for H in Imperial units.
What is the basic unit of time in Imperial?
Also, Lyndon, please state what base units you are using for your calculations so we can follow along.
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Old 23-May-2005, 09:33 PM
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Originally Posted by Tobin Dax
What is the basic unit of time in Imperial?
I thought I already stated that... fortnights. :wink:
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Old 23-May-2005, 09:55 PM
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How about cubic cubits? its not a problem, once one has seen the dimensional analysis the whole thing works. But it takes time and this software, whilst extremely good, does not lend itself to mathematical notation.
The relation H = 2nhr/m holds true in any units. its a fact and true. The Bb cannot predict H, I do.
end of story.
Cheers,
lyndon.
might take a day or two (invigilating all day tomorrow)
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Old 23-May-2005, 10:02 PM
lyndonashmore lyndonashmore is offline
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Originally Posted by TravisM
Quote:
Originally Posted by lyndonashmore
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Originally Posted by TravisM
This may be just me, but... We wouldn't have known to look for a CMB w/o GR and QM... right? :-?
No, McKellar 'prediscovered' the CMB in 1945 (ish) at 2.73K and published it. The followers of the Bb ignored this and claimed the 1968 rediscovery because it suited them.
Cheers,
Lyndon
McKellar he determined a "rotational" temperature of 2.3 K for the gas of interstellar space where CN absorption takes place. http://www.badastronomy.com/phpBB/vi...ht=1941#461762
Later, George Gamow and his colleagues Ralph Alpher and Robert Herman predicted the CMB temperature at around 5K.

Still beggs me to ask how your theory comes up with the spectrum? Or even the need to look for one, other than the fact that the BB already predicted it for yas... :D
No way,
Gamow knew of McKellar 's work. Hence the prediction of around '5K', so it was predicted for the Bb and me . In his last prediction, before Penzias and wilson discovered what we had all already seen on our T/V sets after the epilogue, (you see I discovered the cmb too) Gamow had the CMB at over 50 K.
I lost a dime and found a quarter as george said to me.
Don't be taken in by them!
Cheers,
lyndon
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Old 23-May-2005, 10:03 PM
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Quote:
Originally Posted by lyndonashmore
How about cubic cubits? its not a problem, once one has seen the dimensional analysis the whole thing works. But it takes time and this software, whilst extremely good, does not lend itself to mathematical notation.
The relation H = 2nhr/m holds true in any units. its a fact and true. The Bb cannot predict H, I do.
end of story.
Cheers,
lyndon.
might take a day or two (invigilating all day tomorrow)
Well, hr/m per cubic meter is not the same as nhr/m for two reasons. One is that n is not always in cubic meters (or cubits or whatever). The second is that you're not specifying that hr/m per cubic meter is mulitplied by the number of electrons in that volume. So your units still don't match.

Do Jim's exercise and show us that hr/m (or nhr/m, or both) is equal to H in Imperial units.
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Old 23-May-2005, 10:04 PM
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Originally Posted by lyndonashmore
The relation H = 2nhr/m holds true in any units.
It's at least a valid relationship, which won't change with a change of units, though it's truth would depend on the values of the constants in question (especially H and n). Do you agree, though, that H = hr/m is not a valid relationship, and has no particular significance, since the units don't balance?

Quote:
Originally Posted by lyndonashmore
The Bb cannot predict H, I do.
Remember, though, that since your estimate of n is 0.1 to 10 particles (out of curiosity, where is that figure from?) per cubic meter, your estimate of H is anywhere from roughly 10 km/s/Mpc to 1000 km/s/Mpc. That's hardly an impressive constraint, even if the physics you invoked to come to that conclusion were valid.
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Old 23-May-2005, 10:06 PM
lyndonashmore lyndonashmore is offline
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Quote:
Originally Posted by Grey
Quote:
Originally Posted by lyndonashmore
The paradox - H has the same magnitude to hr/m is not, by itself, fundamental to the universe. It is a 'quirk' of nature that is a 'nice' coincidence.
So you agree then that it is in fact just a coincidence of no particular significance, which perhaps sent you off in the direction you went with your ideas, but is of no importance by itself?
No way!
I derived the relationship and the Tired Light theory predicted this result.
Tut Tut Grey,don't mistake wishful thinking with scientific results.
remeber, My theory is the only one that can predict the value of the Hubble constant.
Cheers,
lyndon
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