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![]() ... just lookin', wondering how much extra G would it need to account for redshift as we know it, and would that higher gravitational proportionality for deep space account for 'dark matter?.. and how would that affect our current notions of redshifted expansion, or BB? Of course, that would put in question the notion of a universal constant for gravity, I suppose. :-? Any way to work this neo-Zwicky idea on gravity into your hypothesis, Lyndon? Cheers.
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Caveat Lector. Experimentum summus judex... |
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By cons. Of momentum h/λ = mv tells us v = h/mλ KE transferred to recoiling electron id mv^2/2 = h^2/(2mλ^2) C = f λ so KE lost to recoiling electron = h^2f^2/2mc^2 This energy is radiated as a CMB photon. Light has a frequency of 6x10^14 Hz So energy lost to recoiling electron when a photon of light is absorbed is 9.7x10^-25J. A photon of this energy has a wavelength of 21 cm. ie microwave. Photons at the peak of the CMB curve are produced by incident photon originally in the UV. All this is in my paper and is not ‘new.’. Cheers, Lyndon |
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What is strange (or maybe not) is that if something goes against the BB then it is said to be "a little problem" - the horizon problem, the flatness problem, the relic particle problem , the where did inflation come from problem..... But when it comes to ATM theories any "little problem" becomes, well this rules out this theory. Just a thought! Cheers, Lyndon |
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But there are two things going on here. One is the normal transmission of light in a transparent medium. Photon comes along and the oscillating electric field drives the electron into vibration. This sets the nearby ones vibrating also. When the driving force stops the oscillations of the system of electrons continue untill all the energy has been re-radiated (due to damping). In glass etc, the electrons are 'fixed' and so they do not recoil. All the incoming energy is re-radiated as a new photon with the same frequency as before - it is not redshifted. In IG space, The electrons are able to recoil and do so. Some energy of the incoming photon is transferred to the electron on both absorption and re-emission so the energy of the new photon emitted is less than before - it is redshifted. Now the recoiling electron also sets up oscillations along the original direction of the photon and these also cause a secondary photon to be emitted - the CMB photon. We get one of these on absorption and a second one on re-emission ie two CMB photons. Cheers. Lyndon |
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The only reason some doubt the conservation of energy and momentum laws is that they have neglected to include these oscillations. Cheers, Lyndon |
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As I said before in alternating currents the electrons have a rapid random thermal motion and yet they perform SHM. Cheers, Lyndon |
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Knowledge is a curse, but ignorance is worse |
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and then in the maths which I also post above and re quoted by yourself. Cheers, Lyndon |
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The initial state is an incoming photon, properly quantified here and in the paper. Initial photon: Energy hc/λ Momentum h/λ But what about the final state? This is not well defined. Is it the state after an alleged photo-absorption? Is it the state after "re-emission"? Is it the state after the CMB photon(s) have gone? We get energy balanced in some states, and momentum balanced in other states, but never a quantified balanced energy and momentum budget at a well defined point in the process. Let's press on with the figures given above. Absorbing electron: Energy h^2/(2mλ^2) Momentum h/λ If we try to quantify the energy at this point, we end up with 99.99976% of the energy still unaccounted for. If the particle was an atom, this would be taken up as a jump in energy level, but electrons don't have energy levels unless bound to an atom, so this first bit fails in the energy balance. We can't make it up with CMB photons either, they are not energetic enough. Lyndon has in some posts (but not in his paper!) accepted that the electron cannot "hold on" to the photon, and re-emits it straight away. See, for example, this post and the novel interpretation of the f2 form factor as probability of "retaining" an absorbed photon. So could Lyndon give a balanced energy momentum budget by incorporating emission of the redshifted photon into his analysis? Perhaps. He's never tried. If he does, then there is almost no momentum left over for the electron, and the electron figures above are useless. It has way too much momentum. A truly balanced analysis will need to include the CMB photons as well, because the electron can't make up the energy difference on its own unless the redshifted photon is scatted as in the usual Compton interaction. Try it and see. The direction of the CMB photons is not specified. The maximum energy transfer to the electron occurs if they are both backscattered, and in this case the electron can get a maximum energy of boost from the interaction of around 1e-34 J, which corresponds to an electron with a velocity of just under 1.5 cm/sec. Don't believe me? Then give the numbers, for a fully balanced energy/momentum budget, clearly stating all contributions to energy and momentum, at any well defined point you like in the interaction. Lyndon has never done this, either in the thread or in his paper. Cheers -- Sylas PS. A string of the usual errors appear in the thread since the the post I am responding to, but there is one point on which Lyndon is quite correct. His paper does have two CMB photons. But there is no possibility of a properly balanced energy momentum budget until they are emitted; which means that they can't be called bremsstrahlung. Bremsstrahlung would mean that there was a consistent state in which the electron has a non-trivial velocity, and the radiation arises from deceleration interactions. In real Bremsstrahlung there are usually a number of photons as an electron decelerates in a series of quantum jumps; but for Lyndon's proposed interaction there is no valid state with balanced energy momentum budgets in which the electron has been accelerated to any velocity above 1.5 cm/sec. The CMB photons have to be emitted right in the initial collision in order to balance the books. |
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And your page is not down, it's one of the five or six links on your main page, and it has been last revised in october 2004, i.e. after your reprint paper was made. And it has nothing to do with diagrams either. But allright, you somehow seem to admit that that page (the CMB page) is wrong. Let's move on to the other mistakes!
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Knowledge is a curse, but ignorance is worse |
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Since billiard balls tend to move around a table at about 10 m/s or so, this is something like 500,000 times faster that the gravitational escape velocity. Now consider electrons in the IGM, a meter apart. The force is about 2.3e-28 N, and the potential energy is 2.3e-28 J. The corresponding velocity for an electron is 22 m/s. Electrons in the IGM are at temperatures of around million degrees or even more, and hence have velocities of something like 6e6 m/s; about 300,000 times faster than the escape velocity. That's not a bad comparison at all. It's plenty good enough for a rough comparison of the significance of the forces for the particle. You can't just compare the magnitude of accelerations, without also looking at differences in mass and velocity. An acceleration of 253 m/s^2 (you got a power of ten wrong there somewhere Lyndon) is negligible for an electron, given the speeds at which they normally move. In fact, TheAtomium has given a rough comparison that gets quite close to the same ratio for natural velocities to escape velocities. Quote:
TheAtomium is correct about restoring forces in the IGM being inadequate to give SHM to an individual electron. Just like AC currents, plasma oscillations only show up as density waves from the combined effect of huge numbers of particles. Cheers -- Sylas |
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Cheers, Lyndon |
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Sylas wrote
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Show up where? How do these density waves come about then if the elctrons don't move? Cheers, Lyndon Cheers -- Sylas[/quote] |
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Nobody said the electrons in a plasma do not move (Sylas says "have velocities of something like 6e6 m/s", in the part you quoted): the point is that they move so fast that their Coulomb interaction is negligible compared to their kinetic energy, which is why they are considered free.
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papageno "Why waste time learning, when ignorance is instantaneous?" - Hobbes (Calvin and Hobbes) "It's all about context!" - Vince Noir (The Mighty Boosh) "I've never heard of such a brutal and shocking injustice that I cared so little about!" - Zapp Brannigan (Futurama) "...because the logic of the lines traced from reality is as poor of aesthetic value as it is strict in consistency. " - Paolo Bozzi (Naive Physics - free translation) |
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I see that you edited your post. If what you say is true then you too should have quoted the original post and then put the edited version on too. What you suggest is hardly practical is it. Cheers, Lyndon PS 3 minutes to reply is fairly rapid, is it a record? I wonder what the record is? |
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Cheers, Lyndon Who is now going to do some work. |
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The mistake was obvious (and not new for you), and it took me just the time to finish reading the first few sentences to realize that. Let me turn your accusation around: you had two minutes to read my very short reply. That's plenty of time to realize your mistake. Quote:
You did not explain that you confused macroscopic EM waves with single photons, and retracted the post because it was wrong. Quote:
My edit consist in adding a few lines: I did not alter the original content. But don't worry, in future I will quote your posts, so you won't be tempted to rewrite history. Quote:
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papageno "Why waste time learning, when ignorance is instantaneous?" - Hobbes (Calvin and Hobbes) "It's all about context!" - Vince Noir (The Mighty Boosh) "I've never heard of such a brutal and shocking injustice that I cared so little about!" - Zapp Brannigan (Futurama) "...because the logic of the lines traced from reality is as poor of aesthetic value as it is strict in consistency. " - Paolo Bozzi (Naive Physics - free translation) |
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What you did was much more than an edit, it was a delete of the original post. What Papageno did was add to the bottom of his post an afterthought, which he clearly indicated as an edit, even though it wasn't even visible in the post history that he had edited it. Nothing of the original post was lost. In your case, we have a reply to a post, and then you edit it out, making it impossible to judge what you did or what Papageno responded to. The two are not comparable at all, and you are just trying to divert the attention.
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Knowledge is a curse, but ignorance is worse |
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Electrons interact by long range coulomb forces and perform SHM since the magnitude of the forces are distant dependent. Air molecules as I understood it are neutral so there are no forces until they 'bump' into each other. One cannot cpmpare density waves in a plasma of charged particles to sound waves in a gas consisting of neutral atoms. Cheers, Lyndon |
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Fram,
There were no posts there when I did My 'five minute edit'. The other '3 minute reply' appeared during the processing time. I put an explanation of the changes at the bottom in case such an event happened. Cheers, lyndon |
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Papageno wrote
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Cheers, Lyndon |
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And that still doesn't make it correct to accuse Papageno of replying without reading it, as you did in your post. If you would have made the explanation you make now instead of (as I said) trying to divert the attention), we wouldn't have this discussion.
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Knowledge is a curse, but ignorance is worse |
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And your "explanation of the changes" is "post removed", which does not explain why you removed it.
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papageno "Why waste time learning, when ignorance is instantaneous?" - Hobbes (Calvin and Hobbes) "It's all about context!" - Vince Noir (The Mighty Boosh) "I've never heard of such a brutal and shocking injustice that I cared so little about!" - Zapp Brannigan (Futurama) "...because the logic of the lines traced from reality is as poor of aesthetic value as it is strict in consistency. " - Paolo Bozzi (Naive Physics - free translation) |
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__________________
Knowledge is a curse, but ignorance is worse |
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I think we have covered everything on this point now, so how do free electrons with random thermal motion generate 'density waves?"
I say it is because the individual electrons perform SHM and there is a phase lag between them so we get the 'density waves'. What do you say? Cheers, Lyndon With profound appologies to Papageno. |
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You deleted all of the original content of your post. I pointed out the main mistake of the original post, and no amount of changes could have corrected it. You decided to revise history instead of admitting that you were wrong (which is not surprising, actually). You behaved dishonestly.
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papageno "Why waste time learning, when ignorance is instantaneous?" - Hobbes (Calvin and Hobbes) "It's all about context!" - Vince Noir (The Mighty Boosh) "I've never heard of such a brutal and shocking injustice that I cared so little about!" - Zapp Brannigan (Futurama) "...because the logic of the lines traced from reality is as poor of aesthetic value as it is strict in consistency. " - Paolo Bozzi (Naive Physics - free translation) |
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