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  #91 (permalink)  
Old 12-May-2005, 05:15 PM
PatKelley PatKelley is offline
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Biggest problem I have with this and many ATM theories is this: they go backwards.

Let me explain:
Theory attempts to explain unusual data. Fine.
Theory argues with existing data and interpretations... well, okay....
Theory says everyone else is wrong and nothing can ever be predicted. Well, hold on there partner. The reason one is developing a theory is so that one can make predictions, not to explain why they can't be made ever. Allow me to expound on a few heavyweights and regulars:

Ashmore and his paradox: No distances can be known, nor can anything be ascertained from spectra, luminosity, or parallax. The conclusion based on refusing to accept the concept of an expanding universe, rather than on new prediction or attempts at better prediction. No conclusions can be drawn, therefore the theory cannot be refuted or falsified. There is no difference in appearance between Ashmore's universe and the one we're observing, other than in his universe attempts at prediction based on physical experiment and extrapoloation fail.

Halton Arp: No hard and fast rules exist for what one should see near any given galaxy, other than x number of galaxies look like they support it, and it gives no predictions. It also reduces the ability of any other cosmological theories to make predictions. No conclusions can be drawn, and most data has to be thrown away, as redshift is arbitrary, and "looks like" trumps empirical measurement and statistical analysis.
By the way, a recent study done has come up with a reason why one would see more quasars around galaxies- gosh, it's because of gravitational lensing. Link here:Lensing of quasars based on large scale survey
Arp may have been right about quasars appearing disproportionally around galaxies, but his explanations and further extrapolation were pure blue sky.

Other even more esoteric theories such as electric universe theories and the like also suffer from this. If gravity is electric, why doesn't my toaster float? Without an explanation for even that simple thought experiment, it flows down the tubes of arbitrary plumbing faster than most. This whole rigamarole of denial and misdirection gives ATM ideas a bad name.

Predict. Dammit, I'd better repeat that. Predict, make testable and useful differentiations between current theory and your expected results, and admit when you are wrong.

My own theory is in its fifth incarnation after simple attempts at prediction through basic thought expeirment failed, and I was forced to conclude that the theory was therefore wrong, and useless in its then current form.

That should be the watchword of any ATM attempts: Predict! Don't just make up a reason why everyone else is wrong about current data interpretations. It really enhances the perception that ATM is all cranks and kookoo, and vice-versa...

And the next time I see someone martyring themselves on the cross of Galileo just because a flaw was pointed out in their theory...

(His grave, by the way, is a perfect hollowed cylinder at this point from all the spinning he's done. I've seen it!)

This unwarrented rant brought to you by a sick child and too much time spent up helping said sick child play "ToonTown" to help him feel better.
  #92 (permalink)  
Old 12-May-2005, 05:24 PM
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Quote:
Originally Posted by lyndonashmore
Basically, in the same way as the frog in my post to Sylas above. Electrons in plasma can oscillate. Th incoming photon sets an electron into oscillation. It is absorbed. The oscillating electron then re-emits a new photon. This is what happens in all transparent medium and the way light travels through them. But in plasma the electrons recoil on absorption and re-emission so some energy is transferred from the photon to the electron. The frequency of the photon reduces, the wavelength increases - it is redshifted. This does not happen in glass because the elctrons are 'fixed' and so cannot recoil.
Is this correct: an electron sits still in equilibrium, but a southwards flying photon strikes. The electron absorbs the photon and inherits it's momentum, so it rebounds moving southwards. The electron now experiences a force as it comes closer to other electrons, and bounces back, performing SHM as you say. Some time later, the electron decides to spit the electron back out. The photon is fired southwards (with a little less energy, redshifted), causing the electron to recoil again, but this time moving northwards. Again it moves out of equilibrium, experiences repulsive force from other electrons, and performs SHM about it's equilibrium. Is that what happens in your model?
  #93 (permalink)  
Old 12-May-2005, 05:33 PM
akirabakabaka akirabakabaka is offline
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Quote:
Originally Posted by TheAtomium
Is this correct: an electron sits still in equilibrium, but a southwards flying photon strikes. The electron absorbs the photon and inherits it's momentum, so it rebounds moving southwards. The electron now experiences a force as it comes closer to other electrons, and bounces back, performing SHM as you say. Some time later, the electron decides to spit the electron back out. The photon is fired southwards (with a little less energy, redshifted), causing the electron to recoil again, but this time moving northwards. Again it moves out of equilibrium, experiences repulsive force from other electrons, and performs SHM about it's equilibrium. Is that what happens in your model?
*waits for papageno to deny SHM of electrons in plasma*

This appears to be a fair description of the mechanism Ashmore is trying to describe, but Ashmore's electrons are in intergalactic plasma, so they aren't ever 'sitting still', they are very hot. We know from observation that electrons in both cold and hot plasmas perform SHM.
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  #94 (permalink)  
Old 12-May-2005, 05:42 PM
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Quote:
Originally Posted by akirabakabaka
Quote:
Originally Posted by TheAtomium
Is this correct: an electron sits still in equilibrium, but a southwards flying photon strikes. The electron absorbs the photon and inherits it's momentum, so it rebounds moving southwards. The electron now experiences a force as it comes closer to other electrons, and bounces back, performing SHM as you say. Some time later, the electron decides to spit the electron back out. The photon is fired southwards (with a little less energy, redshifted), causing the electron to recoil again, but this time moving northwards. Again it moves out of equilibrium, experiences repulsive force from other electrons, and performs SHM about it's equilibrium. Is that what happens in your model?
*waits for papageno to deny SHM of electrons in plasma*

This appears to be a fair description of the mechanism Ashmore is trying to describe, but Ashmore's electrons are in intergalactic plasma, so they aren't ever 'sitting still', they are very hot. We know from observation that electrons in both cold and hot plasmas perform SHM.
Why don't you address this post?
It's where I address your misconception about this "SHM".
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  #95 (permalink)  
Old 12-May-2005, 05:43 PM
PatKelley PatKelley is offline
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Quote:
Originally Posted by akirabakabaka
*waits for papageno to deny SHM of electrons in plasma*

This appears to be a fair description of the mechanism Ashmore is trying to describe, but Ashmore's electrons are in intergalactic plasma, so they aren't ever 'sitting still', they are very hot. We know from observation that electrons in both cold and hot plasmas perform SHM.
Okay, since physics of atoms and subatomic particles is a little hard, let's do ping-pong balls.

I have a ping pong ball in a pipe (electron bound in an atom)
If I hit that ball, it is likely that it will hit a ball on the other end of the pipe at the same angle.

Now, take a free-rolling ping pong ball. I hit that ball- it is much less constrained, so it is likely to hit at a not perfect angle. Hence, scattering.

It's that simple.


That's the difference that Ashmore is denying. If plasmas behaved like Ashmore wants, many things around us would be observably different. And no, physics does not suddenly change outside of earth just because Ashmore wants it to. For instance, fire would be able to refract images like a lens, not based on refractive differences due to air temperature. Fire and plasma balls and other plasma phenomena would behave like glass, complete with refractive indicies and the like. I could focus a beam of light with an electron gun (free electrons in a plasma state) - which you really can't do.
  #96 (permalink)  
Old 12-May-2005, 05:47 PM
Ari Jokimaki Ari Jokimaki is offline
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Quote:
Originally Posted by Fram
Take this quote from his press release:
Quote:
If we convert the Hubble constant into SI units, 64 km/s per Mpc becomes 2.1exp(-18 ) per sec.
Where have all the units gone? Only the seconds are left!
It's a simple case of transforming the 64 km/s/Mpc to SI-units. It goes like this:

64 km/s/Mpc = 64 km/(s Mpc)

1 km = 1000 m and 1 Mpc = 3.08568025 x 10^22 m.

=> 64 km/(s Mpc) = 64 * 1000 m/(s * 3.08568025 x 10^22 m)

Metres cancel out.

=> 64 * 1000 * 1/(s * 3.08568025 x 10^22) = 2.07 x 10^-18 1/s
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  #97 (permalink)  
Old 12-May-2005, 05:54 PM
akirabakabaka akirabakabaka is offline
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Quote:
Originally Posted by PatKelley
Ashmore and his paradox: No distances can be known, nor can anything be ascertained from spectra, luminosity, or parallax. The conclusion based on refusing to accept the concept of an expanding universe, rather than on new prediction or attempts at better prediction. No conclusions can be drawn, therefore the theory cannot be refuted or falsified.
Ashmore is not 'refusing to accept' expanding space. There simply isn't proof of it yet. It is sometimes claimed that BB nucleosynthesis 'proves' expanding space, but it has expanding space as one of it's assumptions so this is not possible.

The largest crutch of expanding-space is Hubble's redshift=distance relation, which can be interpreted in many ways (none of which entirely fit observation). Ashmore's tired-light is one of the many alternatives to expanding space.

Good point about Arp, nothing solid can come out of his work yet unfortunately. I think he is on the right track though, looking for strange objects that defy explanation is a great way to probe the limits of theory.

Quote:
Originally Posted by PatKelley
Predict. Dammit, I'd better repeat that. Predict, make testable and useful differentiations between current theory and your expected results, and admit when you are wrong.
Agreed, predictions are probably the most important part of ATM theories.
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  #98 (permalink)  
Old 12-May-2005, 06:08 PM
akirabakabaka akirabakabaka is offline
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Default Re: Ashmore's "paradox" Reloaded.

Quote:
Originally Posted by papageno
Quote:
Originally Posted by Wikipedia's first line from the link
In physics, plasma oscillations, often referred to as "Langmuir waves" or "plasma waves," are periodic oscillations of charge density in conducting media such as plasmas or metals.
How does the charge density oscillate if you don't take into account the motions of individual electrons? The charges can't be seperated from the particles that provide the charge.

Quote:
Originally Posted by papageno
Let me point out "collective electron displacement".
It means that the whole lot of electrons are displaced at the same time.
This is nowhere near Ashmore's "effect", where a photon interacts with a single electron at a time.
Are the electrons doing the oscillating or aren't they? You've got to pick one or the other...

Quote:
Originally Posted by papageno
Let me point out "If one displaces by a tiny amount all of the electrons with respect to the ions".
This appears to be poor wording on the wiki. Are you going to claim that you know a way to displace all of the electrons in the plasma cloud stretching from the Milky Way to Andromeda at the same time? It should say 'a group of electrons' instead of 'all', as most references do.

Quote:
Originally Posted by papageno
Quote:
Originally Posted by W. S. Kurth
Plasma is a very hot gas in which the electrons have been stripped from atoms to form a gas of negatively charged electrons and positively charged ions.
Let me point out "to form a gas".
How do particles in a gas oscillate about an equilibrium position?
Particles are not bound to fixed position as in a crystal lattice.
It doesn't matter how particles in a gas do anything, we are dealing with a plasma. The particles are not fixed, nor are they entirely free.

Quote:
Originally Posted by papageno
Are you sure Kurth is not referring to the overall charge densities when he says
Quote:
Originally Posted by W. S. Kurth
In a fully thermalized, equilibrium state, these electrons and ions would oscillate about their equilibrium positions.
where these "equilibrium positions" refer to the barycenter of positive and negative charge (which is what you find in textbooks).
If the charge density is oscillating, aren't the charged particles oscillating too?

Quote:
Originally Posted by papageno
Quote:
Originally Posted by akirabakabaka
Also note the reference at the end to SHM in a 'cold plasma', where the initial velocities of the electrons can be ignored. I believe lyndonashmore has already cited several experiments which show SHM of electrons in lasers, or 'relativistic hot plasma'.
As I already explained, the experiments that involve high-powered laser in high-density plasma are completely irrelevant to Ashmore's "theory", because he deal low-power light in low-density plasmas.
Quote:
Originally Posted by papageno
The IG plasma is nowhere near of being relativistic., hence you cannot expect to act the same way.
If you think it does, provide evidence.
If electrons in plasma with extremely low temperatute perform SHM, and electrons in plasma with extremely high temerature (lasers) perform SHM, then we can probably assume that electrons in a plasma somewhere in between these temperatures also perform SHM, instead of dismissing such a possibility out of hand.
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  #99 (permalink)  
Old 12-May-2005, 06:34 PM
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Default Re: Ashmore's "paradox" Reloaded.

Quote:
Originally Posted by akirabakabaka
Quote:
Originally Posted by papageno
Quote:
Originally Posted by Wikipedia's first line from the link
In physics, plasma oscillations, often referred to as "Langmuir waves" or "plasma waves," are periodic oscillations of charge density in conducting media such as plasmas or metals.
How does the charge density oscillate if you don't take into account the motions of individual electrons? The charges can't be separated from the particles that provide the charge.
If you study electromagnetism, you see that hydrodynamic analogies can be used for the charge in a conductor.
These analogies do not work when you consider the motion of charge carriers, and analogies with gases are used.
So, yes the behavior of charge density can be separated from the microscopic motion of the charge carriers.
That was the point of my analogy with sound waves in air.

If you like, you could use water: under the microscope you can observe directly Brownian motion, and sound waves do not affect the Brownian motion of single water molecule.

Quote:
Originally Posted by akirabakabaka
Quote:
Originally Posted by papageno
Let me point out "collective electron displacement".
It means that the whole lot of electrons are displaced at the same time.
This is nowhere near Ashmore's "effect", where a photon interacts with a single electron at a time.
Are the electrons doing the oscillating or aren't they? You've got to pick one or the other...
You missed the "collective" part, apparently: that's why I can say that the charge density oscillates, but the electrons do not.

Quote:
Originally Posted by akirabakabaka
Quote:
Originally Posted by papageno
Let me point out "If one displaces by a tiny amount all of the electrons with respect to the ions".
This appears to be poor wording on the wiki.
So, if it agrees with me, it is poor wording.
But if I explain why Mursula's wording is misleading, then I am wrong.

Quote:
Originally Posted by akirabakabaka
Are you going to claim that you know a way to displace all of the electrons in the plasma cloud stretching from the Milky Way to Andromeda at the same time? It should say 'a group of electrons' instead of 'all', as most references do.
That's why the references use the density.
But in principle, yes the basic plasma oscillation would the whole big honkin' volume.
(Conceptually, this is no more exotic than the polarizability of atoms.)

Quote:
Originally Posted by akirabakabaka
Quote:
Originally Posted by papageno
Quote:
Originally Posted by W. S. Kurth
Plasma is a very hot gas in which the electrons have been stripped from atoms to form a gas of negatively charged electrons and positively charged ions.
Let me point out "to form a gas".
How do particles in a gas oscillate about an equilibrium position?
Particles are not bound to fixed position as in a crystal lattice.
It doesn't matter how particles in a gas do anything, we are dealing with a plasma.
Did you miss the definition of plasma?*

Quote:
Originally Posted by akirabakabaka
The particles are not fixed, nor are they entirely free.
So, how do they oscillate about an equilibrium position.

Quote:
Originally Posted by akirabakabaka
Quote:
Originally Posted by papageno
Are you sure Kurth is not referring to the overall charge densities when he says
Quote:
Originally Posted by W. S. Kurth
In a fully thermalized, equilibrium state, these electrons and ions would oscillate about their equilibrium positions.
where these "equilibrium positions" refer to the barycenter of positive and negative charge (which is what you find in textbooks).
If the charge density is oscillating, aren't the charged particles oscillating too?
Not necessarily.
The charge carriers are indistinguishable from each other.
Sop it is possible to separate the behavior of the charge density from the motion of charge carriers.

Quote:
Originally Posted by akirabakabaka
Quote:
Originally Posted by papageno
Quote:
Originally Posted by akirabakabaka
Also note the reference at the end to SHM in a 'cold plasma', where the initial velocities of the electrons can be ignored. I believe lyndonashmore has already cited several experiments which show SHM of electrons in lasers, or 'relativistic hot plasma'.
As I already explained, the experiments that involve high-powered laser in high-density plasma are completely irrelevant to Ashmore's "theory", because he deal low-power light in low-density plasmas.
Quote:
Originally Posted by papageno
The IG plasma is nowhere near of being relativistic., hence you cannot expect to act the same way.
If you think it does, provide evidence.
If electrons in plasma with extremely low temperature perform SHM, and electrons in plasma with extremely high temperature (lasers) perform SHM, then we can probably assume that electrons in a plasma somewhere in between these temperatures also perform SHM, instead of dismissing such a possibility out of hand.
Except that your assumption that electrons at low temperature perform SHM is wrong.
Also, thanks to Ashmore's references, the SHM at high temperature occurs when they shoot the plasma with a big honkin' laser: it is a forced oscillation.

EDIT to add: it is a forced oscillation because the electric field from the high-power laser light makes them oscillate. The electrons would not oscillate on their own.




*We can get plasma-like behavior in condensed matter.
Debye worked on electrolytic solutions, electrons in metals have plasma-like behavior.
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  #100 (permalink)  
Old 12-May-2005, 06:40 PM
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Quote:
Originally Posted by akirabakabaka
...predictions are probably the most important part of ATM theories.
They are the biggest problem.

Quote:
Originally Posted by PatKelley
...and admit when you are wrong.
That is the most important part of any new theory...being able to admit your own wrongness. I see that in real science. I don't see it from the ATM'ers.
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  #101 (permalink)  
Old 12-May-2005, 07:14 PM
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Quote:
Originally Posted by akirabakabaka
Quote:
Originally Posted by TheAtomium
Is this correct: an electron sits still in equilibrium, but a southwards flying photon strikes. The electron absorbs the photon and inherits it's momentum, so it rebounds moving southwards. The electron now experiences a force as it comes closer to other electrons, and bounces back, performing SHM as you say. Some time later, the electron decides to spit the electron back out. The photon is fired southwards (with a little less energy, redshifted), causing the electron to recoil again, but this time moving northwards. Again it moves out of equilibrium, experiences repulsive force from other electrons, and performs SHM about it's equilibrium. Is that what happens in your model?
*waits for papageno to deny SHM of electrons in plasma*

This appears to be a fair description of the mechanism Ashmore is trying to describe, but Ashmore's electrons are in intergalactic plasma, so they aren't ever 'sitting still', they are very hot. We know from observation that electrons in both cold and hot plasmas perform SHM.
Ok, the SHM part is not so important to my problem. As PatKelley points out, you are very unlikely to get a direct collision where the resulting rebound direction is the same as the incoming photon. This means two things: either you get scattering of the photon on re-imission, or the electron 'remembers' the angle the photon came in at, and launches it in that direction when it decides it's time to emit.

It can't be the first, for obvious reasons. It can't be the second either, because in that case the photon would also inherit some of the electron's momentum (afterall, the electron wouldn't be still, would it?), and that would also cause scattering, as below.



So how does a moving electron emit a photon so that the photon keeps going in exactly the same direction, taking it's own momentum into account?

Edited to add diagram
Edited again to add: I just realised the diagram does not show the effect of the second 'emission rebound' on the electron's velocity, but still the effect on the photon is the same.
  #102 (permalink)  
Old 12-May-2005, 07:14 PM
PatKelley PatKelley is offline
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Quote:
Originally Posted by akirabakabaka
The largest crutch of expanding-space is Hubble's redshift=distance relation, which can be interpreted in many ways (none of which entirely fit observation). Ashmore's tired-light is one of the many alternatives to expanding space.
It is not, not as Ashmore explains it. It is not his proposal, that there is another explanation for redshift, but his mechanism. It does not work. His version of tired light does not work. And, in case you didn't get it with the ping-pong analogy and the flame-focused light analogy, it does not work.

If you or he could come up with an explanation for redshift that didn't require that we either ignore what we see in everyday life, or require that the rest of the universe is "different" than earth and required its own arduously rewritten laws to account for every difference needed to support Ashmore's theory, it might work.

And, well, redshift is not a crutch. It is an observation, one of many, for which expanding space theory makes useful predictions, which are oddly enough borne out by supernova durations (in other words, it is a relativistic effect whatever the mechanism, not just a light phenomenon). Arp, Ashmore, and others don't predict relativistic effects, or allow for them for that matter.
  #103 (permalink)  
Old 12-May-2005, 08:09 PM
akirabakabaka akirabakabaka is offline
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Default Re: Ashmore's "paradox" Reloaded.

Quote:
Originally Posted by papageno
Quote:
Originally Posted by akirabakabaka

Quote:
Originally Posted by papageno
Quote:
Originally Posted by W. S. Kurth
Plasma is a very hot gas in which the electrons have been stripped from atoms to form a gas of negatively charged electrons and positively charged ions.
Let me point out "to form a gas".
How do particles in a gas oscillate about an equilibrium position?
Particles are not bound to fixed position as in a crystal lattice.
It doesn't matter how particles in a gas do anything, we are dealing with a plasma.
Did you miss the definition of plasma?*

*We can get plasma-like behavior in condensed matter.
Debye worked on electrolytic solutions, electrons in metals have plasma-like behavior.
It is the solid or gas which is exhibiting 'plasma-like behavior', not a plasma exhibiting a 'gas-like behavior'. I don't see your point.

Quote:
Originally Posted by papageno
Quote:
Originally Posted by akirabakabaka
Quote:
Originally Posted by papageno
Quote:
Originally Posted by Wikipedia's first line from the link
In physics, plasma oscillations, often referred to as "Langmuir waves" or "plasma waves," are periodic oscillations of charge density in conducting media such as plasmas or metals.
How does the charge density oscillate if you don't take into account the motions of individual electrons? The charges can't be separated from the particles that provide the charge.
If you study electromagnetism, you see that hydrodynamic analogies can be used for the charge in a conductor.
These analogies do not work when you consider the motion of charge carriers, and analogies with gases are used.
So, yes the behavior of charge density can be separated from the microscopic motion of the charge carriers.
That was the point of my analogy with sound waves in air.
OK, I see how you're logically seperating the charge carriers and density, but I don't think this is the case with IG plasma in equilibrium. Plasma frequency is consistently described in terms of electron displacement. BTW, how is an analogy between gas and plasma any different than Ashmore making an analogy between IG plasma and transparent mediums?

Quote:
Originally Posted by papageno
Quote:
Originally Posted by akirabakabaka
Are you going to claim that you know a way to displace all of the electrons in the plasma cloud stretching from the Milky Way to Andromeda at the same time? It should say 'a group of electrons' instead of 'all', as most references do.
That's why the references use the density.
But in principle, yes the basic plasma oscillation would the whole big honkin' volume.
(Conceptually, this is no more exotic than the polarizability of atoms.)
The equilibrium oscillations will be on the scale of the entire plasma, but not oscillations caused by local disturbances. These return to equilibrium very quickly after the disturbance stops and only effect local areas of the plasma.

Quote:
Originally Posted by papageno
Quote:
Originally Posted by akirabakabaka
If electrons in plasma with extremely low temperature perform SHM, and electrons in plasma with extremely high temperature (lasers) perform SHM, then we can probably assume that electrons in a plasma somewhere in between these temperatures also perform SHM, instead of dismissing such a possibility out of hand.
Except that your assumption that electrons at low temperature perform SHM is wrong.
This wasn't an assumption. I provided several citations which support this, so where do you base your claim?

Quote:
Originally Posted by [url
http://www-pw.physics.uiowa.edu/plasma-wave/tutorial/waves.html[/url]]In a fully thermalized, equilibrium state, these electrons and ions would oscillate about their equilibrium positions. However, any perturbation to this equilibrium would displace the charged particles in such a way as to set up electric and magnetic fields which act as restoring forces to the displaced particles. In the simplest example of such a perturbation, the electrons might be offset from the less mobile (because of their mass) ions. The electrons, then, would execute simple harmonic motion about their equilibrium positions.
Thus we have SHM in a cold plasma. I think the Mursula paper says this too
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  #104 (permalink)  
Old 12-May-2005, 08:15 PM
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Quote:
Originally Posted by PatKelley
And, well, redshift is not a crutch. It is an observation, one of many, for which expanding space theory makes useful predictions, which are oddly enough borne out by supernova durations (in other words, it is a relativistic effect whatever the mechanism, not just a light phenomenon). Arp, Ashmore, and others don't predict relativistic effects, or allow for them for that matter.
Redshifts are an observation. Expanding space is an interpretation of the redshift=distance relation, and has not ever been directly observered. This is an important distinction that maintains the credibility of non-BB cosmologies until better observations are made.

I don't believe that Arp or Ashmore say anything about relativity at all. Their theories do not apply to relativity anymore than Darwin's.
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  #105 (permalink)  
Old 12-May-2005, 08:42 PM
PatKelley PatKelley is offline
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Quote:
Originally Posted by akirabakabaka
Quote:
Originally Posted by PatKelley
And, well, redshift is not a crutch. It is an observation, one of many, for which expanding space theory makes useful predictions, which are oddly enough borne out by supernova durations (in other words, it is a relativistic effect whatever the mechanism, not just a light phenomenon). Arp, Ashmore, and others don't predict relativistic effects, or allow for them for that matter.
Redshifts are an observation. Expanding space is an interpretation of the redshift=distance relation, and has not ever been directly observered. This is an important distinction that maintains the credibility of non-BB cosmologies until better observations are made.

I don't believe that Arp or Ashmore say anything about relativity at all. Their theories do not apply to relativity anymore than Darwin's.
Precisely my point.

Delays in the rise and fall of brightness of supernova with redshift are indicative of a relativistic cause. Neither Arp nor Ashmore account for an increasing delay in rise and fall of supernova brightness with distance.

They do not address ALL of the observations, just the ones they think they can pick at.

The Arp and Ashmore redshift theories fail to account for observation, in critical ways. While expanding space does not account for all observation (accelerating expansion, for instance) it does *predict* crucial observations, such as time dilation in supernova brightness (it appears to take longer for a supernova to brighten then dim).

To add to this, Ashmore's disagrees with local observation of plasma, light, and diffraction/diffusion. That is much more fundamental than a disagreement with mechanism of redshift; his disagrees with basic look-out-the-window observation of everyday phenomena.

Arp's disagrees with itself, and makes no valuable predictions.

In the end, it is Ashmore's and Arp's theories that have a single crutch upon which to stand: interpretation of redshift. Their mechanisms don't work unless all of physics up until now is wrong. And I mean ALL: you can't rely on shift in volume of an approaching then receeding object without calculating its intrinsic shift, based on some arbitrary and incalculable supposition. Also, your TV no longer works, fire turns into a disco-ball lightshow, and our eyes need to be corrected to see the sun as it appears rather than how Ashmore says we should see it.
  #106 (permalink)  
Old 12-May-2005, 09:27 PM
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Quote:
Originally Posted by Ari Jokimaki
Quote:
Originally Posted by Fram
Take this quote from his press release:
Quote:
If we convert the Hubble constant into SI units, 64 km/s per Mpc becomes 2.1exp(-18 ) per sec.
Where have all the units gone? Only the seconds are left!
It's a simple case of transforming the 64 km/s/Mpc to SI-units. It goes like this:

64 km/s/Mpc = 64 km/(s Mpc)

1 km = 1000 m and 1 Mpc = 3.08568025 x 10^22 m.

=> 64 km/(s Mpc) = 64 * 1000 m/(s * 3.08568025 x 10^22 m)

Metres cancel out.

=> 64 * 1000 * 1/(s * 3.08568025 x 10^22) = 2.07 x 10^-18 1/s
Yes, I know that, but you are comparing two meaningless entities (this is one of them) to reach a conclusion. That's why I asked where the units have gone. A change in speed over distance isn't the same as a number per second. A number per second is meaningless. If one meaningless number is the same as another meaningless number, you still don't have anything meaningful in the end.
I didn't dispute the numbers, but the method of seeing importance where there is none.
For every 3 dollars I have, you give me 1 dollar a year.
Is that the same as: you give me 1/3 a year? I don't think so.
And if for every kg weight I have now, I'll gain a kilo every three year, that gives me 1/3 a year as well. Does that mean you can compare them? I guess you can, but I wouldn't try to find any significance in it, and this example (while of course fiction) is of two entities that have more to do with one another than Lyndon's.
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Old 12-May-2005, 09:50 PM
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Quote:
Originally Posted by Fram
Yes, I know that, but you are comparing two meaningless entities (this is one of them) to reach a conclusion. That's why I asked where the units have gone. A change in speed over distance isn't the same as a number per second. A number per second is meaningless. If one meaningless number is the same as another meaningless number, you still don't have anything meaningful in the end.
I didn't dispute the numbers, but the method of seeing importance where there is none.
For every 3 dollars I have, you give me 1 dollar a year.
Is that the same as: you give me 1/3 a year? I don't think so.
And if for every kg weight I have now, I'll gain a kilo every three year, that gives me 1/3 a year as well. Does that mean you can compare them? I guess you can, but I wouldn't try to find any significance in it, and this example (while of course fiction) is of two entities that have more to do with one another than Lyndon's.
Units are soooo Fascist!! They limit discussion!! [-(

Oh... sorry... as you were... :-s
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Old 13-May-2005, 03:40 AM
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Can anyone tell me why Lyndon is calling all of this a paradox?
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Old 13-May-2005, 04:46 AM
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Here is the correct proof of the theorem that Compton scattering of a photon without changing the direction results in no change in energy for the photon, that is, no redshift. We use a metric with signature +--- and units in which c=1 throughout.

Let k be the four-momentum of the photon and p be the four-momentum of the electron after scattering. Let k' and p' be the four-momenta of the photon and electron before scattering. Conservation of four-momentum (which means both energy and momentum conservation) implies:

k + p = k' + p', or

k - k' = p' - p .

Square both sides, remembering that k^2 = k'^2 = 0 since they are photons and p^2 = p'^2 = m^2 where m is the mass of the electron and find:

-2*k*k' = 2*m^2 - 2*p*p' .

Now k may be decomposed into its time-like and space-like parts as k=k*(1, n), where is a unit vector in the direction of motion of the photon, and likewise p may be decomposed as p=m*gamma*(1, beta) where beta is v/c, that is, the velocity vector of the electron in units of c, and gamma = sqrt(1-beta^2). k' and p' may be expressed similarly. Written out this way the previous equation becomes:

-2*k*k'*(1-n*n') = 2*m^2*(1 - gamma*gamma'*(1- beta*beta')).

Without loss of generality we can work in the frame where the initial electron is at rest, that is beta' = 0 and gamma' = 1. We then have:

-2*k*k'*(1-n*n') = 2*m^2*(1 - gamma).

Now what happens if we make the assumption that there is no scattering of the photon, that is, that its direction remains unchanged? This means that n = n' and the left hand side of the equation is zero:

0 = 2*m^2*(1 - gamma),

therefore gamma = 1 and beta = 0 for the scattered electron as well. In this frame that we have chosen this means that the four-momenta p and p' obey p = p' = m*(1, 0) so that p' - p = k - k' = 0. A four-vector that is zero in one frame is zero in all frames. The momentum and energy of the photon is thus unchanged by the scattering, therefore no redshift. QED.
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Old 13-May-2005, 06:20 AM
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Quote:
Originally Posted by Celestial Mechanic
The momentum and energy of the photon is thus unchanged by the scattering, therefore no redshift. QED.
Quite so. Just to anticipate; Lyndon's usual response to this is "but it isn't Compton scattering".

This misses the point. Call it what you like; when you have an interaction between a photon and an isolated electron, you cannot get any energy transferred to the electron unless the photon changes direction. This follows from conservation of energy and momentum, just as Celestial Mechanic has shown.

If the electron was bound to a nucleus, then you could have inelastic collisions with the electron jumping an energy level. But electrons by themselves don't have energy levels. In a thick plasma, you might involve other particles as well. But in the IGM, the electron is around about a meter away from any other particles.

Cheers -- Sylas
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Old 13-May-2005, 06:55 AM
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Quote:
Originally Posted by Fram
Yes, I know that, but you are comparing two meaningless entities (this is one of them) to reach a conclusion. That's why I asked where the units have gone. A change in speed over distance isn't the same as a number per second.
It is, I just showed you that.

You might be interested in what Ned Wright has to say about this:

Quote:
Originally Posted by Ned Wright
Since both kilometers and Megaparsecs [...] are units of distance, the simplified units of Ho are 1/time
Quote:
Originally Posted by Fram
A number per second is meaningless.
Unit of frequency is 1/s (also called Hertz).

Quote:
Originally Posted by Fram
If one meaningless number is the same as another meaningless number, you still don't have anything meaningful in the end.
I didn't dispute the numbers, but the method of seeing importance where there is none.
I'm not taking any position regarding how meaningful Lyndon's comparison is, but you were complaining only about the units of Hubble constant. If units of Lyndon's other number are also 1/s, then the units agree, and in that sense the comparison is valid.
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Old 13-May-2005, 08:25 AM
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Quote:
Originally Posted by Ari Jokimaki
Quote:
Originally Posted by Fram
Yes, I know that, but you are comparing two meaningless entities (this is one of them) to reach a conclusion. That's why I asked where the units have gone. A change in speed over distance isn't the same as a number per second.
It is, I just showed you that.

You might be interested in what Ned Wright has to say about this:

Quote:
Originally Posted by Ned Wright
Since both kilometers and Megaparsecs [...] are units of distance, the simplified units of Ho are 1/time
Quote:
Originally Posted by Fram
A number per second is meaningless.
Unit of frequency is 1/s (also called Hertz).

Quote:
Originally Posted by Fram
If one meaningless number is the same as another meaningless number, you still don't have anything meaningful in the end.
I didn't dispute the numbers, but the method of seeing importance where there is none.
I'm not taking any position regarding how meaningful Lyndon's comparison is, but you were complaining only about the units of Hubble constant. If units of Lyndon's other number are also 1/s, then the units agree, and in that sense the comparison is valid.
Then I wasn't clear about my objections (that shall teach me to complain about other people's unclarity #-o ).
You can remove the units, but you cannot compare the two equations apart from the abstract (numerological) sense. In my example in my previous post, I gain 1/3 a year two times, but I don't gain 2/3 a year. Even though you can strip the units, you cannot do as if they don't exist or are meaningless. They limit you severely in what you can do with the results. I expressed my problems with his comparison of the two equations in the wrong way, but that doesn't change my fundamental problems with it. Thanks for the explanation though and the patience, as your attitude is a lot more helpful.
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Old 13-May-2005, 10:45 AM
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Quote:
PatKelley
It is not, not as Ashmore explains it. It is not his proposal, that there is another explanation for redshift, but his mechanism. It does not work. His version of tired light does not work. And, in case you didn't get it with the ping-pong analogy and the flame-focused light analogy, it does not work. If you or he could come up with an explanation for redshift that didn't require that we either ignore what we see in everyday life, or require that the rest of the universe is "different" than earth and required its own arduously rewritten laws to account for every difference needed to support Ashmore's theory, it might work.
Of course it works, we see it every day when light goes through glass. the only difference is that in IG space the electrons recoil and so the photons lose energy and redshift.
Being able to derive the accepted value for the Hubble constant confirms this.



Quote:
And, well, redshift is not a crutch. It is an observation, one of many, for which expanding space theory makes useful predictions, which are oddly enough borne out by supernova durations (in other words, it is a relativistic effect whatever the mechanism, not just a light phenomenon). Arp, Ashmore, and others don't predict relativistic effects, or allow for them for that matter.
We do - we just haven't published it yet.
Cheers,
Lyndon
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Old 13-May-2005, 11:26 AM
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Quote:
Originally Posted by lyndonashmore
Quote:
And, well, redshift is not a crutch. It is an observation, one of many, for which expanding space theory makes useful predictions, which are oddly enough borne out by supernova durations (in other words, it is a relativistic effect whatever the mechanism, not just a light phenomenon). Arp, Ashmore, and others don't predict relativistic effects, or allow for them for that matter.
We do - we just haven't published it yet.
Cheers,
Lyndon
Well, Narlikar & Arp have published how their hypothesis works for supernova time dilation. (I have no idea if it's valid.)
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Old 13-May-2005, 11:28 AM
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Default Re: Ashmore's "paradox" Reloaded.

Quote:
Originally Posted by akirabakabaka
Quote:
Originally Posted by papageno
Quote:
Originally Posted by akirabakabaka
Quote:
Originally Posted by papageno
Quote:
Originally Posted by W. S. Kurth
Plasma is a very hot gas in which the electrons have been stripped from atoms to form a gas of negatively charged electrons and positively charged ions.
Let me point out "to form a gas".
How do particles in a gas oscillate about an equilibrium position?
Particles are not bound to fixed position as in a crystal lattice.
It doesn't matter how particles in a gas do anything, we are dealing with a plasma.
Did you miss the definition of plasma?*

*We can get plasma-like behavior in condensed matter.
Debye worked on electrolytic solutions, electrons in metals have plasma-like behavior.
It is the solid or gas which is exhibiting 'plasma-like behavior', not a plasma exhibiting a 'gas-like behavior'. I don't see your point.
Let's have a look at the definition of plasma:
Quote:
Originally Posted by [url=http://en.wikipedia.org/wiki/Plasma
Wikipedia[/url]]
In physics and chemistry, plasma (also called an ionized gas) is an energetic gas-phase state of matter, often referred to as "the fourth state of matter", in which some or all of the electrons in the outer atomic orbitals have become separated from the atom or molecule.
Let me emphasize "ionized gas".
Do you see my point now?
So, how do particles in a (ionized) gas oscillate about an equilibrium position?


Quote:
Originally Posted by akirabakabaka
Quote:
Originally Posted by papageno
Quote:
Originally Posted by akirabakabaka
Quote:
Originally Posted by papageno
Quote:
Originally Posted by Wikipedia's first line from the link
In physics, plasma oscillations, often referred to as "Langmuir waves" or "plasma waves," are periodic oscillations of charge density in conducting media such as plasmas or metals.
How does the charge density oscillate if you don't take into account the motions of individual electrons? The charges can't be separated from the particles that provide the charge.
If you study electromagnetism, you see that hydrodynamic analogies can be used for the charge in a conductor.
These analogies do not work when you consider the motion of charge carriers, and analogies with gases are used.
So, yes the behavior of charge density can be separated from the microscopic motion of the charge carriers.
That was the point of my analogy with sound waves in air.
OK, I see how you're logically separating the charge carriers and density, but I don't think this is the case with IG plasma in equilibrium.
You don't think based on what? Experimental evidence?


Quote:
Originally Posted by akirabakabaka
Plasma frequency is consistently described in terms of electron displacement.
"Described consistently" by whom?
Have you read proper textbooks, like the references given by Mursula himself at the beginning of his lecture notes?


Quote:
Originally Posted by akirabakabaka
BTW, how is an analogy between gas and plasma any different than Ashmore making an analogy between IG plasma and transparent mediums?
Transparent medium: light interacts with atoms, which react to the electric field of the light as electric dipole.
Plasma: light interacts with free electrons, which are charges (electric monopoles).
In the former case, the electron is bound to a positive charge; in the latter, it is not.
Ashmore's "analogy" is wrong because he equates atoms with free electrons.


Quote:
Originally Posted by akirabakabaka
Quote:
Originally Posted by papageno
Quote:
Originally Posted by akirabakabaka
Are you going to claim that you know a way to displace all of the electrons in the plasma cloud stretching from the Milky Way to Andromeda at the same time? It should say 'a group of electrons' instead of 'all', as most references do.
That's why the references use the density.
But in principle, yes the basic plasma oscillation would the whole big honkin' volume.
(Conceptually, this is no more exotic than the polarizability of atoms.)
The equilibrium oscillations will be on the scale of the entire plasma, but not oscillations caused by local disturbances. These return to equilibrium very quickly after the disturbance stops and only effect local areas of the plasma.
If you are referring to screening (or shielding), then you can still have oscillations of charge density without charge carriers oscillating about a position.

Why don't you work out the average energy for Coulomb interaction in a typical IG plasma, and compare it to the average kinetic energy of an electron in that plasma?

Quote:
Originally Posted by akirabakabaka
Quote:
Originally Posted by papageno
Quote:
Originally Posted by akirabakabaka
If electrons in plasma with extremely low temperature perform SHM, and electrons in plasma with extremely high temperature (lasers) perform SHM, then we can probably assume that electrons in a plasma somewhere in between these temperatures also perform SHM, instead of dismissing such a possibility out of hand.
Except that your assumption that electrons at low temperature perform SHM is wrong.
This wasn't an assumption. I provided several citations which support this, so where do you base your claim?
What citations?
Ashmore's out-of-context quotes? Have you read proper textbooks?

My claim is based on my understanding of physics*, and I explained it extensively in this and the other thread.


Quote:
Originally Posted by akirabakabaka
Quote:
Originally Posted by [url
http://www-pw.physics.uiowa.edu/plasma-wave/tutorial/waves.html[/url]]In a fully thermalized, equilibrium state, these electrons and ions would oscillate about their equilibrium positions. However, any perturbation to this equilibrium would displace the charged particles in such a way as to set up electric and magnetic fields which act as restoring forces to the displaced particles. In the simplest example of such a perturbation, the electrons might be offset from the less mobile (because of their mass) ions. The electrons, then, would execute simple harmonic motion about their equilibrium positions.
Thus we have SHM in a cold plasma. I think the Mursula paper says this too
That's the best citation you can come up with? A short web-page?
20-page-long lecture notes? Did you read the textbooks Mursula references?

Let's see what Feynman has to say:
Quote:
Originally Posted by Feynman's Lectures on Physics, Vol. 2
Waves in metals
In metals some of the electrons have no binding force holding them to any particular atom; it is these "free electrons" which are responsible for the conductivity.
[...]
You could also have a look at some introductory books on Solid State Physics, where you can see some pictures of this "displacement" you cite.

If you did, you would realize that the harmonic motion you talk about is the result of the electric forces that keep an electron from flying away from the volume containing the plasma.

Let's assume that your plasma is contained in a volume with well defined boundaries.
What happens if an electron crosses those boundaries, leaving the volume.
This volume would now have a net positive charge, which attracts the electron back into the volume.
Imagine that the electron has enough momentum to overshoot the volume of the plasma, and crosses the boundary on the opposite side.
Again the net positive charge would attract the electron back into the volume.
This is the "simple harmonic motion" your citations talk about, and it is described in terms of macroscopic parameters such a the electron density.
It occurs over length-scales comparable to the size of the volume occupied by the plasma, not on a microscopic scale.

(I explained this in the other thread already.)




*(which includes having studied and being tested on plasma-like behavior of electrons in metals, and a nice experiment in a teaching lab where we observed the effects of exciting plasmon in piece of metals)
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  #116 (permalink)  
Old 13-May-2005, 12:48 PM
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Quote:
Originally Posted by Ari Jokimaki
Quote:
Originally Posted by lyndonashmore
Quote:
And, well, redshift is not a crutch. It is an observation, one of many, for which expanding space theory makes useful predictions, which are oddly enough borne out by supernova durations (in other words, it is a relativistic effect whatever the mechanism, not just a light phenomenon). Arp, Ashmore, and others don't predict relativistic effects, or allow for them for that matter.
We do - we just haven't published it yet.
Cheers,
Lyndon
Well, Narlikar & Arp have published how their hypothesis works for supernova time dilation. (I have no idea if it's valid.)
Thanks Ari.
Hadn't seen that one. I will have a look.
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Old 13-May-2005, 12:58 PM
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Quote:
Originally Posted by Sylas
Quote:
Originally Posted by Celestial Mechanic
The momentum and energy of the photon is thus unchanged by the scattering, therefore no redshift. QED.
Quite so. Just to anticipate; Lyndon's usual response to this is "but it isn't Compton scattering".

This misses the point. Call it what you like; when you have an interaction between a photon and an isolated electron, you cannot get any energy transferred to the electron unless the photon changes direction. This follows from conservation of energy and momentum, just as Celestial Mechanic has shown.

If the electron was bound to a nucleus, then you could have inelastic collisions with the electron jumping an energy level. But electrons by themselves don't have energy levels. In a thick plasma, you might involve other particles as well. But in the IGM, the electron is around about a meter away from any other particles.

Cheers -- Sylas
As I said before, Sylas and Celestial mechanics are forgetting that this is a ‘two interaction’ process. Firstly absorption, with the electron recoiling in the forward direction and then re-emission with the electron recoiling in the opposite direction. Looking at the ‘whole thing’ as Sylas and CM do misses out the detail. Sylas seems to be happy even though using Newtonian mechanics, he gets possible outcomes of zero and 2c, whilst in a relativistic treatment he appears to find the v = 0 scenario. Both treatments must give the same solution set otherwise there is something wrong with the mathematics. Unfortunately Sylas’ solution is not all there so we cannot check his sums. Perhaps he would like to show us the whole thing here so we can check them.
In the meantime let’s have a proper look at the situation.
For absorption.
By Newtonian mechanics.
Photon frequency, f, wavelength λ, comes in and is absorbed by an electron initially at rest.
Momentum, p = h/ λ = mv where m is the mass of the electron and v the recoil velocity.
V = h/m λ .
KE = mv^2/2 = h^2/2m λ^2.
The plasma is in a state of thermal equilibrium where the rate at which it receives energy from the photons is equal to the rate at which it is given off as CMB (by bremstrahhlung). So lets work out the wavelength of a CMB photon produced by a redshifted photon of light (λ = 5x10-7 m).
Energy = h^2/2m λ^2 = 9.6x10^-25J = hc/ λ tells us that the wavelength would be 0.21m ie in the microwave. To get CMb photons of wavelength 2.1mm we need the incoming photon to be in the UV.
After the delay, the original photon is then re-emitted so let’s work out the energy lost on re-emission. Sylas feels that he has a monopoly on relativity so let’s work it out that way here – just for him.
Consider our stationary electron of mass M(0), emitting a photon of energy Q (=hf). Let the recoiling electron have M’ (and rest mass M(0)’) and velocity v
E = M(0)c^2 = M’c^2 + Q =E’ + Q
p = 0 = M’v – Q/c = p’ – Q/c
ie
E’ = M(0)c^2 – Q
cp’ = Q
So
(M(0)’c^2)^2 = (E’)^2 – (cp’)^2
= (M(0)c^2 – Q)^2 – Q^2
Or (M(0)’c^2)^2 = (M(0)c^2)^2 – 2M(0)c^2Q …………….(1)
We can write M(0)’c^2 = M(0)c^2 - Q(0) where Q(0) is the total energy release.
So (M(0)’c^2)^2 = (M(0)c^2)^2 – 2M(0)c^2Q(0) + Q(0)^2
Combining this with equation (1) gives
Q = Q(0)(1 – Q(0)/2M(0)c^2)
When we multiply out the bracket we can clearly see that the energy lost in recoil is Q(0)^2/2M(0)c^2 where Q(0) is the total energy available and approximately hf for the incoming photon (we can do it exactly but this is sufficient for here – the difference is that lost in absorption)
Energy lost on re-emission = Q(0)^2/2M(0)c^2 = (hf)^2/2M(0)c^2 = h^2c^2/2M(0)c^2 λ^2
Or energy lost = h^2/2M(0) λ^2
Note that this is the same answer that we got with Newtonian mechanics and results in a second CMB photon being emitted on re-emission.
So I don’t see how Sylas and CM feel it is impossible, it is just accepted physics.
As a consequence, this Tired light theory not only explains the Hubble constant but also the CMB – plasma can emit Black body radiation.
Cheers,
Lyndon
PS let me of any typos.
  #118 (permalink)  
Old 13-May-2005, 02:20 PM
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Quote:
Originally Posted by lyndonashmore
As I said before, Sylas and Celestial mechanics are forgetting that this is a ‘two interaction’ process. Firstly absorption, with the electron recoiling in the forward direction and then re-emission with the electron recoiling in the opposite direction.
What Sylas showed is that there are no two processes: a free electron cannot absorb a photon, it can only scatter.
This is a consequence of the conservation of energy and momentum.


Quote:
Originally Posted by lyndonashmore
Looking at the ‘whole thing’ as Sylas and CM do misses out the detail. Sylas seems to be happy even though using Newtonian mechanics, he gets possible outcomes of zero and 2c, whilst in a relativistic treatment he appears to find the v = 0 scenario. Both treatments must give the same solution set otherwise there is something wrong with the mathematics.
You obviously do not understand the difference between Classical and Relativistic Mechanics.


Quote:
Originally Posted by lyndonashmore
Unfortunately Sylas’ solution is not all there so we cannot check his sums. Perhaps he would like to show us the whole thing here so we can check them.
Sylas posted all you need in order to check.
If you really had a clue about the physics you are talking about, you would not need this excuse to avoid the issue.


Quote:
Originally Posted by lyndonashmore
[SNIP!]

So I don’t see how Sylas and CM feel it is impossible, it is just accepted physics.
Wrong. Accepted physics explain that a free electron cannot absorb a photon.


Quote:
Originally Posted by lyndonashmore
As a consequence, this Tired light theory not only explains the Hubble constant but also the CMB – plasma can emit Black body radiation.
So, where is your calculated spectrum?
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  #119 (permalink)  
Old 13-May-2005, 02:55 PM
PatKelley PatKelley is offline
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Quote:
Originally Posted by lyndonashmore
Quote:
PatKelley
It is not, not as Ashmore explains it. It is not his proposal, that there is another explanation for redshift, but his mechanism. It does not work. ... If you or he could come up with an explanation for redshift that didn't require that we either ignore what we see in everyday life, or require that the rest of the universe is "different" than earth and required its own arduously rewritten laws to account for every difference needed to support Ashmore's theory, it might work.
Of course it works, we see it every day when light goes through glass. the only difference is that in IG space the electrons recoil and so the photons lose energy and redshift.
Being able to derive the accepted value for the Hubble constant confirms this.
Wait, we've been through this. Many many times.
See, that's the problem. Your idea would have DISTINCT effects on what we see currently. I.e.:

According to your own summation of your postulated effect:

I should be able to use an electron gun to focus a light beam.

I can't do that.

Please explain. Or get out of the pool.




Quote:
Originally Posted by lyndonashmore
Quote:
And, well, redshift is not a crutch. It is an observation, one of many, for which expanding space theory makes useful predictions, which are oddly enough borne out by supernova durations (in other words, it is a relativistic effect whatever the mechanism, not just a light phenomenon). Arp, Ashmore, and others don't predict relativistic effects, or allow for them for that matter.
We do - we just haven't published it yet.
Cheers,
Lyndon
Well, as the first tenets of your theory are very unlikely, I don't think more fuel will add much to this fire other than chaos and entropy.
  #120 (permalink)  
Old 13-May-2005, 02:58 PM
PatKelley PatKelley is offline
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Quote:
Originally Posted by lyndonashmore
Quote:
Originally Posted by Ari Jokimaki
Quote:
Originally Posted by lyndonashmore
Quote:
And, well, redshift is not a crutch. It is an observation, one of many, for which expanding space theory makes useful predictions, which are oddly enough borne out by supernova durations (in other words, it is a relativistic effect whatever the mechanism, not just a light phenomenon). Arp, Ashmore, and others don't predict relativistic effects, or allow for them for that matter.
We do - we just haven't published it yet.
Cheers,
Lyndon
Well, Narlikar & Arp have published how their hypothesis works for supernova time dilation. (I have no idea if it's valid.)
Thanks Ari.
Hadn't seen that one. I will have a look.
Don't bother. It is exactly as I predicted: to support the theory, the universe has to be rewritten to work differently than it does on earth, as to explain the light-curves of supernova they invoke the "...variable mass hypothesis which accounts for the redshift phenomenon in the above static universe model..."
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