I want to address akirabakabaka's statements in this post.

Ashmore's "double Mossbauer effect" is non-sense physically, as should be clear from his abuse of the term.

Mossbauer effect occurs in gamma-photon emission by nuclei of atoms embedded in a crystal. The emission is recoil-less, because the recoil momentum is too small to excite vibrations (a.k.a. phonons) in the lattice.*

The scattering of a photon in the visible light range and a electron in a low density plasma is nowhere near the actual Mossbauer effect.
It is Compton effect, and if you look it up, you will see that if the photon does not change direction in the scattering event, the wavelength does not change, no matter what the initial momentum of the electron is.**

The plasma oscillations occur on length-scales that are much large than the wavelength of a visible-light photon, and would not have any effect on photon-electron scattering.
These plasma oscillations are oscillations in the charge density of the plasma, and are not the result of particles oscillating about some point.***



* The result is a very sharp and narrow emission line, which makes the Mossbauer effect useful for measurements of hyperfine fields and gravitational red-shifts on Earth, for example.

** This mean that Ashmore's idea of a "critical wavelength", dependent on the plasma temperature, does not work.

*** I repeatedly made the analogy between sound waves and motion of molecules in air.



You miss the point, again.
As I said:and previously:It should be an equality no matter what system of units is used.


It has been explained extensively why collisions of photons with electrons does not work.
If you go with well established physics, these collisions would be Compton scattering, which cannot account for the red-shift as observed (no distance dependent broadening, no effect of the atmosphere).
And Ashmore's attempt to propose a new "mechanism" for energy loss only betrays his deep and serious misunderstandings of physics.

It is not reasonable for him to cling to his misconceptions when they have been shown wrong.
It is not reasonable for him to selectively quote sources that do not agree with him, or are not relevant (see all those references to effects of high-power laser in high-density plasma).
He has never been able to provide proper physical arguments that the photon-electron scattering in a plasma is anything different from Compton scattering (he tried to weasel his way out with his "critical wavelength", but it was shown to be wrong).
He has no mechanism for energy loss of photons that yields a red-shift as it is observed.

__________________
papageno


"Why waste time learning, when ignorance is instantaneous?" - Hobbes (Calvin and Hobbes)

"It's all about context!" - Vince Noir (The Mighty Boosh)

"I've never heard of such a brutal and shocking injustice that I cared so little about!" - Zapp Brannigan (Futurama)

Why thank you Papageno, just like old times isn't it? Have you brought your sandwiches? You may need them.
I will answer your other points later (have a meeting soon - no time) in the meantime which of the photon/electron interactions (compton, inverse compton, rayleigh, raman, Thompson etc) do you say occurs when photons of light are absorbed and re-emitted as the pass through glass? ie what name do you give to this interaction which certainly takes place.
Chees,
Lyndon

What happens to photons going through a dielectric medium such as glass is irrelevant to your "theory".
You claim that photons going through intergalactic plasma lose energy due to scattering events.
IG plasma (free electrons) and glass (electrons bound to nuclei) have little to do with each other, despite your obvious misconceptions.
The fact that you are trying to tie the two together, already shows that you do not understand the issue.

As usual you are just trying to divert the attention from the fact that have nothing to support your idea.
The burden of proof is yours.

__________________
papageno


"Why waste time learning, when ignorance is instantaneous?" - Hobbes (Calvin and Hobbes)

"It's all about context!" - Vince Noir (The Mighty Boosh)

"I've never heard of such a brutal and shocking injustice that I cared so little about!" - Zapp Brannigan (Futurama)

If individual photons were absorbed and re-emitted, glass would not be transparent to them.

Objection over ruled.
In your post you complain about the name I give to this interaction. Well it is the same as happens in glass. If you say that 'my' effect is compton then are you saying that photons travel through glass by compton?
I think not. So come on Papageno stop avoiding the question, what is the name given to the interaction that enables photons to travel through glass.
Cheers,
Lyndon

Not true, this is exactly how photons travel through a piece of glass.
Try these.
French (French.A.P. 1968a Special relativity (p128. Nelson. London)) states “the propagation of light through a medium (even a transparent one) involves a continual process of absorption of the incident light and its reemission as secondary radiation by the medium.” Feynman (Feynman.R.”Q.E.D.- the strange story of light and matter”.P76.
Penguin.London.1990.) describes the transmission of light through a transparent medium simply as “photons do nothing but go from one electron to another, and reflection and transmission are really the result of an electron picking up a photon, ”scratching its head”, so to speak, and emitting a new photon.”
This is not in doubt.
Cheers,
Lyndon

Using that name only shows that you do not understand neither Mossbauer nor the electron-photon scattering.

As I and other people explained to you many times, what happens in glass is photons interacting with electric dipoles (electrons bound to nuclei).
What happens in IG plasma is photons interacting with electric monopoles (electrons).
The fact that you still cannot understand difference only proves that you are not willing to learn and correct your mistakes.

You are the only one claiming that your "tired light" effect has something to do with light traveling in glass.
You are supposed to provide evidence to support, but you have never done so.
I simply pointed out that you are wrong.
Do you actually know the difference between a electric dipole and single charge?

I have not avoided the question. I have shown that your question is misguided and misleading, and simply an attempt to divert the attention.
You are the only one avoiding the issue, and the burden of proof is still yours: show us that electron-photon scattering in IG plasma is not Compton scattering, but your badly-named "double Mossbauer".

__________________
papageno


"Why waste time learning, when ignorance is instantaneous?" - Hobbes (Calvin and Hobbes)

"It's all about context!" - Vince Noir (The Mighty Boosh)

"I've never heard of such a brutal and shocking injustice that I cared so little about!" - Zapp Brannigan (Futurama)

Still avoiding the question.
I agree that mossbauer is not the ideal name but it is the nearest thing to it. So, since it is the same as the interaction in glass, what name to you give to this interaction? It is a simple question. It is you that is nit picking over names, so tell us. What do you call this interaction between photons and electrons in glass that we surely know happens - I gave two references in the post above.
Cheers,
Lyndon

By the "medium", which is made of atoms.
These atoms interact with the photons as electric dipoles.


The usual quote, taken out of context from a book of popularized physics, where you forget to explain that this electron is bound to a nucleus.
Electronic transitions in atoms are always described as the electron changing state:

"electron picking up a photon": electron changes to a state at higher energy;

"scratching its head": electron spends some time in the higher energy state (ever heard of fluorescence and phosphorescence?);

"emitting a new photon": electron goes back to the initial state.

Quantum Mechanics 101: apparently you still do not understand that the (quantized) electronic states that allow for this absorption-emission of photons, occur when the electron is bound to a nucleus.
This is not the case for the electrons in a plasma.
The quote, as you present it, is misleading.

__________________
papageno


"Why waste time learning, when ignorance is instantaneous?" - Hobbes (Calvin and Hobbes)

"It's all about context!" - Vince Noir (The Mighty Boosh)

"I've never heard of such a brutal and shocking injustice that I cared so little about!" - Zapp Brannigan (Futurama)

I already explained what is wrong with your question.

No crystal, no gamma rays, no Mossbauer.
No, your effect is nowhere near Mossbauer.

You are obviously in denial at this point.
I explained unambiguously that your "tired light" effect has nothing to do with the propagation of light in glass.

You, instead of addressing the issue, repeat the same misconception.


Read my posts.
I explain why the names are wrong.

References you do not understand or willfully misrepresent.
What is described in those quotes has nothing to do with your "tired light" effect.

You are trying to equate the interaction of photons with electric dipoles, to the interaction of photons with free charges.
This is a fundamental mistake you keep repeating.
By insisting on it, you are just digging your hole deeper and deeper.

__________________
papageno


"Why waste time learning, when ignorance is instantaneous?" - Hobbes (Calvin and Hobbes)

"It's all about context!" - Vince Noir (The Mighty Boosh)

"I've never heard of such a brutal and shocking injustice that I cared so little about!" - Zapp Brannigan (Futurama)

But they are the same effect Papageno, only in glass the electrons don't recoil because they are fixed in a crystal lattice. In the plasma of space the electrons recoil on absorption and re-emission so energy is lost to the electron. Photon loses energy, frequency reduces wavelength increases. It is redshifted. easy.
So they are the same effect so they have the same name.
As for mono poles etc, plasma is neutral there is a positive charge for every negative one. in fact some treatments of plasma divide it into 'virtual atoms' - cubes containing equal quantites of positive and negative charge, and they oscillate!
Cheers,
Lyndon

Wrong. You still do not understand.
The electrons in glass are bound to nuclei, which have a positive charge. Nuclei and electron forms atoms, which in turn form the crystal.
Light in glass interacts with the atoms, not with free electrons.
Photons are absorbed by the system (electron+nucleus), not just by the electron.
Without the nucleus, the electron would not have quantized states to jump to, hence it would not be able to absorb a photon.
The description of absorption and emission is always presented in terms of electrons, because it is the electrons that change most noticeably (frame of reference where the nucleus is at rest).

In low-density plasma electrons are not bound to positive charges.
Photons in a plasma interact with single charges, not with atoms.

The two effects are different.


A photon scattering on an electron in plasma is Compton scattering.
If the direction of the photon is not changed during the scattering event, there is no loss of energy.
The electron alone cannot absorb a photon.
In order for absorption and emission to occur as you envision, you need to have an atom, electrons bound to a positive nucleus.


Except that energy is lost by the photon only if its direction changes.
In which case you have to explain how we get nice pictures of distant objects, without blurring and with red-shift.
The red-shift is the same in observations performed in different places and at different times.
Also, you would expect a change in the broadening of the spectral lines related to distance.

Your "broken record" tactic in all its glory!

You misunderstand: an electric charge is a monopole.
The plasma as a whole is neutral: the density of positive charge equals the density of negative charge.
But positively and negatively charged particles are separated from each other, and are not bound.


The charge densities oscillates, not the charge carriers.
You keep confusing the charge with charge carriers, which is why you still do not understand plasma oscillations.

Do you remember my analogy with sound?
Sound waves in air are oscillations in the density of air molecules.
However, single molecules do not oscillate back and forth.

__________________
papageno


"Why waste time learning, when ignorance is instantaneous?" - Hobbes (Calvin and Hobbes)

"It's all about context!" - Vince Noir (The Mighty Boosh)

"I've never heard of such a brutal and shocking injustice that I cared so little about!" - Zapp Brannigan (Futurama)

Its better to talk about energy bands than 'quantized states' otherwise absorption re-emission would only happen for certain frequencies. The point is Papageno, that when the frequencies are 'off resonance' in glass atoms the photon is re-emitted. There is a delay - thats why the speed of light is less in glass than in a vacum and this is what enables the electrons in plasma to recoil.


So are you saying that photons travelling through glass undergo compton scatter and thus take a 'random walk'?


not with the interaction I use, there is a double recoil in the forward direction - that is why this Tired Light theory works.
I worked this out on my website - its a FAQ on the Tired light page on my website The line broadening is less than that due to doppler.

But it is correct.


In order for charge density to oscillate the electrons themselves must oscilate.[/quote]

not the same.
Got to go out now (Wilbur phoned to say the thought police are on the way here)
Cheers
Lyndon