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Some try to tell me, thoughts they cannot defend,... - Moody Blues. Neptune- The original Dark Matter. The author feels that this technique of deliberately lying will actually make it easier for you to learn the ideas. - Donald Knuth |
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t' = t / gamma where "v" is not differentiated as to vector, hence is red and blue shifted blind. I do not object to your formulisim, I do object to the publication and claims that t' = t / (1 - v^2/c^2)^1/2. "v" has vector but "v" is just "v" and speed does not change with vector. Relative velocity does not change with vector. The basic formula of SR as presented are physically invalid. It would seem that "v" should have some other symbol or notation to differentiate it in the gamma formula such that vector and doppler is imposed and not state t' is merely a function of relative velocity. Mere relative velocity IS NOT consistant with time dilation. Unless others have further comment I am satisfied with the conclusions of this thread and hope it is of service to others. |
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Some try to tell me, thoughts they cannot defend,... - Moody Blues. Neptune- The original Dark Matter. The author feels that this technique of deliberately lying will actually make it easier for you to learn the ideas. - Donald Knuth |
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Go to post 79. And stay there. |
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And stay there. |
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1. Go to post 79 2. Loop on 1 |
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By the way, you are correct that time dilation is only a part of Doppler shifts. Perhaps understanding this may help you: A Doppler shift is what you get when you correct simple time-of-flight effects to account for time dilation. This is why the relativistic formula is different from the formula used for the Doppler shifts of sound-- the latter is not corrected for time dilation. As to the role of vectors, the direction of v does affect the time-of-flight piece of the calculation, but not the time dilation piece. The former can give red or blueshifting, the latter is always a redshifted correction. How do you intend to make that correction without time dilation? |
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MacM:
Forget about post #79. Go to posts #74, 75 and 76. Read and re-read until you understand. I made them as entertaining and enlightening as I possibly could. And also read the book recommended by Tensor. ![]()
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Microsoft is over if you want it. The bar has been lowered for the promotion of ATM ideas; the bar for the acceptance of ATM ideas must remain high. |
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The data I correct as errors used doppler shifted "Observed" velocities and not "Source" velocities. As I stated several times in this thread doppler and simultaneity are illusions of motion measurements. My thread and calculations are based on "Source" velocity and the claim for t' as stated above and the fact that only two issues determine the accumulated time of a clock. 1 - Tick rate and, 2 - Duration of test. |
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MacM it is you who do not understand Relativity, not the other posters in this argument. You don't just get to take out the part of Relativity you don't like and substitute in your own version. Synchronization is very important and if not done, you will end up with incorrect results. Celestial Mechanic's #74, #75, and #76 posts are exactly what you need to learn how to do this correctly.
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DOOM Master |
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MacM:
I hope that the following exposition might put an end to your confusion. Let A and B be two bodies in relative motion with another and velocity v. Consider the inertial reference frame K in which A is at rest and B is moving with velocity +v in the x direction. The world-lines of the two bodies are then: A(c*t, x) = (c*t, 0) B(c*t, x) = (c*t, v*t). Let K' be the inertial reference frame in which B is at rest. Let the coordinates in K' be denoted x' and t'. Let K and K' have the same origin. Then these coordinates are related to t and x of K via a Lorentz transformation: c*t' = g*c*t - b*g*x x' = g*x - b*g*c*t. Here I'm being lazy and writing b for beta and g for gamma. The world-line in K' where B is at rest must have x' = 0 and thus x = b*c*t. Comparison with x=v*t yields v=b*c so that b=v/c. Now consider this: c*t' = g*c*t-b*g*x everywhere, and x=b*c*t along the world-line of B, so along the world-line of B: c*t' = g*c*t-g*b2*c*t so c*t' = (1/g)*c*t. This is true, but only on the world-line of B. What is the world-line of A in K'? Along the world-line of A we have x=0 and using the Lorentz transformation we find c*t' = g*c*t x' = -b*g*c*t = -b*c*t' = -v*t'. Thus the world-line of A in K' is A(c*t', x') = (c*t', -v*t'), just as we would expect since we can consider B at rest and A to be moving at -v. But wait a minute! Here we have c*t' = g*c*t, and before we had c*t' = (1/g)*c*t. What gives? The expression c*t' = g*c*t is only valid along the world-line of A. c*t' = (1/g)*c*t is only valid along the world-line of B. The only way they can both be valid is if g*c*t = (1/g)*c*t which implies (g - 1/g)*c*t = 0 which means either t (and thus t') equals zero (the intersection of A and B) or g = 1, in which case A and B coincide. There is no contradiction.
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Microsoft is over if you want it. The bar has been lowered for the promotion of ATM ideas; the bar for the acceptance of ATM ideas must remain high. |
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I refuse to get into an abusive verbal contest even if some post here have been borderline insults. Most have not so I will continue.
At this juncture I simply want to point out that there has been absolutely no basis to alter the terms of the test or thread. It was designed specifically to KISS (Keep It Simple St....). I specifically pointed out it omitted doppler and simultaneity. If relative velocity alters time, then it alters time in a one way test as I have laid it out. There was no basis to add confusion of turn arounds and return trips and to change from "Source" velocities to Doppler "Observed" velocities. All clocks in the test accumulate time in the redshifted mode. Now if you like post the accumulated times for these clocks using your doppler shifted data. If you choose to not do so that is fine, I will. At best using measurements altered by illusions of motion will shift the absolute values of the inconsistancies. Arguements that you cannot break the test into such an increment is to argue that physics do not exist over that part of the relative motion frames. It is a ludricrus and unsupportable position to take. I have not claimed doppler shift does not occur. I have not claimed relativity of simultaneity does not exist. I have claimed, and do claim, that if you reduce this issue to simple physics, the failure (and it is a failure) becomes apparent. What you in effect are attempting to do is to alter the arguement to claim that to disprove SR you must use all of SR's manipulations. That is no longer a proper challenge. That would be no different than me claiming that 10 x 10 = 1,000 instead of 100 because you MUST multiply by k = 10. I am saying this k = 10 is bogus physics. The only valid arguement to the contrary would be for relativists to actually post emperical data to support the reciprocity asserted by the relative velocity view. Not to regurgitate the theory as its own proof. At least they should not post in a manner suggesting I have overlooked something or do not understand something, when infact I have pointed out the conditions are irrelevant to the test. Once again. Please demonstrate that to show (or test) time dilation due to relative velocity requires more than two clocks accumulating time over an equal test period. Or that physics only function if you make a round trip or use one form of velocity over another. It is your arguement that my test does not demonstrate a conflict. Since you choose to work in "Observed" doppler shifted terms due to measurements in motion post your data for the test as described for the following clocks. Am = 36,000 Abp = Acp = Bm = Bap = Bcp = Bac = Cm = Cap = Cac = Cbp = I don't think you dare. |
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It follows, then, that your Gedankenexperiment has little to do with SR. It follows that your Gedankenexperiment is a test of "MacM physics". Perhaps you could lay out for us what the key components of this physics are? That way we can mount challenges that make sense (in terms of what the test you propose is, in fact, a test of). Quote:
If the test you describe cannot be conducted, with today's technology, then we will need to find another way to test SR or MacM physics, won't we? SR has been subject to many tests, in the lab, and it has passed all with flying colours. Can we test MacM physics in the lab too? What experimental setup can you describe for us that is, in principle, feasible with today's technology, that would test MacM physics? But let me start with the MacM Gedankenexperiment. If A, B, and C all send out, in all directions, a signal, using light, every second by their own clocks, what will each record (between the MacM start and MacM finish, each according to her own determination of these events)? For clarity, let's require that each signal each of A, B, and C sends be a faithful image of the dial of the clock (A, B, and C have only one clock each). What will be the time encoded in the last signal A sends? B? C? What will be the time encoded in the last signal that A receives from B and C? that B receives from A and C? that C receives from A and B? (for avoidance of doubt, this may serve as the 'videolink' I mentioned in my earlier posts). |
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MacM, we realize that you are trying to distinguish Doppler shifts and synchronization issues from the time dilation effect. You think that when you only consider time dilation by itself, you reach a contradiction, and these other issues are just distractors. What we have tried to show you is that they are all intimately related, such that if you don't understand one, you can't understand any. For example, you cannot understand the formula for Doppler shifts unless you include time dilation. You keep saying you are not denying that Doppler shifts occur, but the issue is, is the formula correct? If it is, you will find that there is no way to derive it without time dilation.
But how is the reciprocity issue answered? You have an important gedankenexperiment there, and in it lies the ability to understand special relativity. It is true that the station clock will read 36,000 seconds when the shuttle clock reads 18,000 seconds, according to the way the people in the space station define simultaneity. But this is different from the way the people in the shuttle define simultaneity, and that's why they think the station clock only reads 9,000 seconds when their clock reads 18,000 seconds. This apparent paradox is all about the meaning of simultaneity, despite your oft repeated claim to the contrary. The issue is, when clocks are separated by distance, the way time and distance are interrelated in special relativity means you must pay very close attention to how simultaneity, or synchronization, is being defined in the various different frames. The equation is, separation in distance, plus a difference in velocity, equals a difference in simultaneity/synchronization. End of story. Until you understand this, you will keep thinking that there is a contradiction, when no one who understands it does. Let me explain the twin paradox to you from this perspective (I know you think this has nothing to do with the twin paradox, but again, until you understand that you won't understand anything). When the shuttle is flying away, it thinks that very little time is elapsing on the station. When it gets to its turnaround point, it thinks this moment is simultaneous with a time very early on for the station. But when it suddenly changes velocity to return, it concludes in that very instant that its moment is now suddenly simultaneous with a moment much later in the life of the station-- a huge amount of time has passed on the station in the blink of an eye for the shuttle. For its return trip, very little time passes in the station, just as it did on the way out, so the aging of the space station crew will mostly have happened in the change in simultaneity during the turnaround. So you see, you can never understand the twin paradox, or the remote passage of time, by time dilation alone. The role of simultaneity is huge-- time dilation by itself is very incomplete, and leads to these kinds of paradoxes if you think time dilation can do all the heavy lifting. |
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MacM,
I just read throught this whole thread (I can't believe I read the whole thing......where's my Alka-Seltzer ), and I'm trying to figure out just what is the brick wall you're hitting in understanding what's going on. I'm not going to try to argue with you about all the details others are making, mainly because my SR math is so rusty, I'd have dig out my EM textbooks just to get back in the game. The others here can do that better.Your brick wall is this business about "reciprocity" or how A thinks B's clock is running slow compared to his, while B thinks A's clock is running slow, and A think B's yardstick is shorter and vice-versa, and how that must be impossible. To get through that wall, you've got to understand that time and space are not distinct things, but become "mixed" into one thing, generally called "space-time". One observer's time is a "mixture" of the distance and time of another observer in relative motion. You will balk at that statement I'm sure, but this is the brick wall to your understanding of SR. Your trouble is you want to think of time as something distinct from distance (and possibly absolute). That is a big hurdle, but that's the way the universe works. Many others banged their heads about this, so you're not alone. We have three dimensions of distance and you can easily how different coordinate systems basis vectors become "mixed" with other coordinate systems basis vectors. Now, you just have to accept that time has to be thrown in this same mix. Imagine a 2D coordinate system, the familiar x-y plane. Now image a second coordinate system, the x'-y' plane, sharing the origin, but rotated at a 45 degree angle with respect to the x-y axes. Consider 1 unit of lenght alone the x' axis. That reflects to 1/sqrt(2) units along the x axis (and the same along the y-axis). Now consider one unit of length along the x axis. That corresponds to 1/sqrt(2) units along the x' axis, (and the same along the -y' direction). Now, imagine that in that plane, we somehow want to think of x and y coordinates as being two different, distinct measures, say "time" or something. Well, as you can easily see from the geometry, 1 unit of time in the x-y frame is just 1/sqrt(2) units of x'-y's "time", and "reciprically", 1 unit of time in the x'-y' frame is just 1/sqrt(2) units of "time" in the x-y frame. x-y thinks x'-y' clock is slow, but x'-y' sees x-y's clock as slow, "at the same time" (sorry, I couldn't help that) If you read the links about Dingle, you'll recognize this rotated 2D system. 4D space-time is a little different, because it is *non-Euclidian*. There is a minus sign on the time coordinate in the norm, and "distances" in 4D can be either positive (space-like), negative (time-like), and zero (light-like). This is usually called Minkowski space, and there are countless textbooks with various ways of geometrically visualizing it (using 1 space coordinate with time, the x-t plane) and how two frames are related with respect to gamma. It is different from the orthogonal 2D system above because of the non-Euclidian nature, but you will still see that the t' axis is at an angle to the t axis in a similiar way, and one unit along either has a shorter projection along the other. -Richard |
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We simply disagree. I agree that I am not following your mathematical manipulations used in SR but then to restrict ones challenge to finding a formula error or derivation error is a completely different subject than understanding a physical flaw or contradiction. The later requires looking outside the formal structure and considering the physics issues, not some theoretical mathematical issue. Quote:
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That purportedly is due to relative velocity, not doppler shift or relativity of simultaneity. That is not to say these things do not occur but that they are illusions of motion measurements and do not permanently change the accumulated time by any clock and hence merely add complexiety to any analysis. Quote:
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Will you agree that the 9,000 seconds is bogus and that clock Am will never record less time than clock Bm in my scenario? If so we have no disagreement because that is the physical reality; which isn't what SR predicts. Quote:
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That doesn't make me right (or wrong) but it is a different issue. Quote:
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You are mixing up "denying to death" with "making valid arguments".
You are right on one thing: the first approach makes peoples not to want to talk to you after a while. So you end up arguing with yourself. "If two people tell you you are drunk, then you should go to bed" (old Aussie proverb) MacM's Closure to a Length Contraction Thread Quote:
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A calculation of relative velocity between a clock at the equator on the surface of the earth due to earths rotational speed and an orbiting GPS clock results in a -5.8us/day value. Incorrect. The correct value is -7.2us/day due to orbit velocity with the center of the earth as a common local preferred frame. Ouch! Relative velocity (SR) is not used in GPS. Only the one way gamma based on an absolute velocity to a preferred frame. Preferred frame? Wash my mouth with soap. |
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Whatever.I would give you a link to a very good paper on SR/GR effects (not GR "affects") on GPS but I know it would be a waste. You will end up arguing with yourself about it. Right on, "space-time" does not exist. Because you say so. |
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KenG has hit the nail on the head several times over, MacM (and others have made very good points too). You can't just ignore the relativity of simultaneity if you want to understand what SR actually predicts, let alone if you want to have a feel for SR "means".
What you believe about 4D spacetime is completely irrelevant to your claim that SR is inconsistent. When you claim that dilation is just the maths and not physical reality you demonstrate a complete lack of understanding about what science is. SR is a mathematical model; or, two postulates and their necessary implications. The model makes predictions. Those predictions have been tested. Those tests have all been passed. The data for the test you ask for could never been done because you won't allow the clocks to turn around and you won't accept that time dilation is real unless the clocks are brought back side by side. Nevertheless, the model predicts time dilation and all the experimental evidence supports that model and thus transitively supports that prediction. The real problem with your thought experiment is that you are claiming that you are measuring physical time dilation and reaching a contradiction while all that is actually being measured is the passage of time in each frame. Your extra clocks really are just calculations in one frame of how time is progressing in another according to SR. The supposed contradiction you reach is to then insist that the relativity of simultaneity is not relevant when resolving the supposed paradox you pose. So you use SR to predict time dilation for each observer according the other but won't allow SR to be used to resolve your paradox! If you want to acutally measure something physical between the observers then you need to have them observe each other and take into account doppler effects as well, just as CM was kind enough to spell out for you. Your stop time is defined in A's frame. You then compare all clocks from As frame and conclude that time dilation is one way - but that's just cos you're only doing it one way. The other way is to see what happens in B's and C's frames. Whether you believe time dilation is symmetric or not, doing the calculations only from one frame of reference and then claiming that that demonstrates that it only happens that way is completely circular logic. As KenG has said repeatedly, to understand the problem you need to think about the relativity of simultaneity. As A and B seperate their notion of what is now both "here" and "there" diverges and that is the resolution to the supposed paradox of reciprical time dilation. You can deny it all you want, but you can't show that it leads to any inconsistencies within the theory and you haven't shown any evidence showing that the theory might be wrong (where we can ignore gravitional effects, that is).
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There are 10 types of people in the world. Those who understand ternary, those who don't, and those waiting for a bus. If logic doesn't work, then surely it does. |
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Indeed, Worzel makes good points.
IMHO what MacM does is exactly what my Relativistic Professor warned for. MacM is looking from the God perspective, a frame (where A may be at rest) in which he can observe all spacecraft at the same time (simultaneously). However, this frame does not exist. After said 36000 time units, all clocks are read off by the timonauts, and probably will show in their own frame 36000 and 18000, but they have no way of knowing what the other spacecraft have as a value UNLESS they communicate with eachother, and then we need a definition of simulteneity and we need doppler. Otherwise, there is no way this experiment can be done, there is no God frame. Thus MacM's results are a paradox (used in its true meaning, not the popular one).
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Any comments in glorious red are to be considered in ModeratorMode. 善數, 不用籌策 (shàn shù, bù yòng chóu cè) He who is good at counting, uses no counting tools “A good scientist has freed himself of concepts and keeps his mind open to what is” 道德經, 二十七 (dào dé jīng, 27) |
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All that can be said about test data is that it is not entirely "Inconsistant" with SR, not that it supports SR because it also supports the absolute view and suggests the relative velocity view is incorrect in that recorded permanent differential times by a clock violates the reciprocity advocated by SR. i.e. - Where is the data that shows the pilots view in H&K atomic clock tests, that the earth bound clocks ran slower (were time dilated) vs the airborne clocks. Quote:
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This is not a calaculation it is physical test. You must address the issue that ONLY the accelerated frame has ever demonstrated time dilation. Never the resting frame which defies the SR reciprocity (equality of frames) arguement. Quote:
If you can show that they ultimately permanently change time recorded such that it agrees with ALL predictions of SR and not merely one half of the prediction then I will gladly conceed. Failing to do that I will steadfastedly maintain that SR is invalid and that data suggests an absolute view rather than the relative velocity view. Yours was a good post as well. Last edited by MacM; 29-March-2006 at 02:25 PM.. |
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