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  #151 (permalink)  
Old 28-June-2008, 06:33 PM
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Quote:
Originally Posted by Jim Mash View Post
When I said that I had not found a mathematical explanation for the gravitational collapse of a gas cloud I actually meant an account that was believable. There are some examples given but these are not realistic. Take for example the account given by Thayer Watkins. You can find this easily by searching the web via his name.
I can just take my book and read all about it from there I don't need to get my "knowledge" from the web.

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He goes through the process of calculating the acceleration due to gravity for the atoms at the edge of a gas cloud that has a diameter of 10^13m and a mass of 2x10^33g. He uses over 20 equations and eventually derives a figure of 1.4x10^ 6m/s. With FET I used FET to first calculate the speed of gravitational energy flowing into the cloud at its surface, i.e. its escape velocity from the equation

k x N / Ed x SA

Where
k is the rate at which energy is drawn into a single nucleon,
N is the number of nucleons in the gas cloud,
Ed is the density of continuum energy and
SA is the surface area of the gas cloud.

For this example
k = 3.2x10^-18
N = 10^57
Ed = 2x10^15 and
SA = 1.2^27

Which gives a speed of 1.33x10^-3m/s.

I then calculated that this flow rate of gravitational energy would accelerate an atom at the same rate as he calculated.
KEWL, first we have no ideas about where the numbers that you put in come from, secondly I had a question why one has to divide by the energy density of the continuum (other than for getting your units correct), thirdly you get an "escape velocity" of millimeters per second, where a quick calculation shows it is 5 km/s (or I must have made a very bad mistake) and then TATATATAAAAAAAAAAA you stop and then you CLAIM you find the same acceleration, yeah RIGHT!

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My method is quite unlike that used by Watkins, is much simpler and arose because I used a completely different model for an atom. If you mention the word atom to someone then some sort of picture usually springs into their mind. For most people it will be the often used symbol of a planetary system with individual electrons orbiting a central nucleus. Now scientists know that this is not what an atom really looks like but at the moment they have no better way of visualising it. Maybe a mathematician will dismiss this picture from his mind and instead picture a set of equations but then this does not help him to explain it to others. I bet if you said the word horse to a mathematician he would picture a horse in his mind, not a set of equations. So pictures of things are very useful, that is if they are the correct ones.
In first year physics you get the Bohr model, which is rather good at explaining the energy levels of hydrogen, but fails as soon as you get to Helium. So, it is a nice way to visualize stuff, but we know it is not the real stuff. (Just like my explanation of the uncertainty principle using a car and a camera is totally unreal, but it gets the point across).

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Now when I think of an atom I picture it quite differently from that of a solar system. FET tells me that a nucleon is a spinning disc or sphere of solid energy throwing out fluid energy and sucking it back. The easiest way to imagine this is to consider a nucleon to be a pump that is shooting water out as a fountain. The water rises high into the air and then descends back to the pump where it is collected and then pumped out in a continuous cycle. Now imagine a number of pumps tied together in a bundle and shooting out water jets in many directions and this is how I picture an atom.
Could you be going back to Descartes with his vortices?
I can visualize your model, but is there any reason to it, now these are nucleons you say that are spinning, later that seems to change below.

Quote:
Originally Posted by Jim Mash View Post
This picture of an atom allowed me to work out how atoms combine chemically to form molecules, along with many other new ideas. Imagine two fountains aligned facing each other with their water jets just overlapping at their tops. Energy is energy just as water is water and therefore the water from one fountain does not belong exclusively to the one pump. So where the two jets overlap there can be an exchange of water so that whereas most of the water returns to its original pump, some moves between pumps. If the fountains were moved apart then each would take with it the same amount of water although it would not necessarily be the same water molecules that they started with. It is this exchange of energy between nucleons that binds them together. The more energy that is exchanged the stronger the bond.
Sorry old chap, but you have a model of nucleons not of atoms, there is a VERY BIG DIFFERENCE BETWEEN THE TWO. So, maybe you mean that this is the way that nucleons (protons and neutrons) bind together in the nucleus? There are the electrons that seem to pop-up below.

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Originally Posted by Jim Mash View Post
It is the way that nucleons are combined within a nucleus that determines the directions of the jets of energy and also their length. Some of the fluid electron energy cycles around many nucleons within the nucleus and binds them together. Different arrangements require different amounts of fluid energy to bind the nucleons together and therefore some jets have less energy available than others meaning that some electrons are longer than others. The longest electrons will be able to exchange energy with other atoms before the remaining electrons can even reach each other and therefore some provide the bonding energy whilst others do not. So I picture an atom as having a specific number of electron jets in a specific pattern and lengths that are defined by the way that the nucleons are bound together in the nucleus.
So, now suddenly it is nucleanos in the nucleus. Do you write your book like this too, just mixing up stuff? And now suddenly the interaction between atoms is by the outer electrons.

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Originally Posted by Jim Mash View Post
In the lowest energy state where only electron energy is circulating around the nucleons the cores of solid energy are spinning around on the spot and all of the electron energy is circulating around them and therefore there is no overall motion in a particular direction so the atom can be considered to be stationary. But now if extra energy is absorbed from a specific direction then all the energy of the atom plus that absorbed will move in the opposite direction from where it came. The speed of the atom will be determined by the conservation of momentum (but using energy instead of mass in the equation) so that the absorption of a small amount of energy moving at light speed will impart a small speed to a large amount of energy.
Ahh so you have also a "planetary system" like the Bohr model? Or what is spinning around?
This is rather confusing.

Quote:
Originally Posted by Jim Mash View Post
Now think of an atom as being a sailing boat. The body of the boat is the nucleus and the electron is the sail. The solid energy of the nucleons is confined within a radius of around 10^-15m whereas the electron energy extends to over 10^-10m. Hence it is the electron that captures energy that is flowing past it whether that energy is moving at light speed as a photon or as a much slower movement of energy as in the flow of gravitational energy. Now once we have the correct picture of an atom in our minds we can use maths to work out how fast an atom will be accelerated by the flow of gravitational energy. All we need to know is how big is the sail, how fast is the flow of energy and how much energy is there in that flow, i.e. the energy density of the continuum.

The area of the electron that collects energy is equal to 1.43x10^-18m^2 and therefore it collects gravitational energy at a rate equal to 2.86x10^-6eV/s. This accelerates a nucleon at a rate of 0.91x10^-6m/s, which is very close to the Watkins value. Because the flow of gravitational energy is constant, as soon as some is absorbed it starts to move the atom. As more energy continues to be absorbed the speed increases at a linear rate. Therefore an atom will accelerate for as long as it continues to absorb energy. So with FET we now we have a way that shows how gravity accelerates objects that is easily visualised and understood.
The area is a circle of 10-10 (π R2) or is it that of a sphere (4 π R2) of this radius, or is it the half-surface of a sphere (2 π R2)? 1.43 is none of the three possibilities, but maybe the orbit is different from the value given?

At the moment I have no time to go further with this stuff, maybe later, it's saturday evening and now I am going to watch "the Tudors" first.
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  #152 (permalink)  
Old 28-June-2008, 06:40 PM
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hi,



Quote:
I have already shown how it explains why photons move at light speed,
I was wondering if you or someone could point to the thread where ^^^ this is shown.
there is so much information in the thread that I seemed to have missed this idea which could actually answer so many questions and tie up many loose ends.
thanks.
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  #153 (permalink)  
Old 30-June-2008, 09:46 AM
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The curiosity virus got to me and I decided that I needed to know the source for discussion.

A quick search on the web for Thayer Watkins gave me this web page where a very simplified model of gravitational collapse is presented. I must thank Jim Mash "for revealing his sources" on what he assumes is the final word on gravitational collapse of a cloud, although I had to search for it myself, and a link would have been appreciated. (Watkins has a number of webpages dealing with all kinds of stuff, all rather "nutshell" views.

I sure hope that Jim Mash does not believe this is the final word, because if I look at Bowers & Deeming, chapter 23.4 "Collapse of an isolated cloud" it clearly begins with:

Quote:
Again only the simplest model will be considered in detail. Imagine a large cloud of density ρ' and temperature T', in which a sperical cloud of radius R and density ρ and temperature T is embedded. The cloud is isothermal, nonrotating and nonmagnetic. We assume further that ρ' << ρ and T' >> T, the surrounding matter is hot and dilute, but the spherical cloud is cool and "dense."
etc. etc.
So, it seems that (even in this very simplistic model which is used for showing the basics and a more real world (or should I say universe) model would be too difficult to compute analytically and can only be solved numerically), the temperature of the cloud is taken into account. Also in later sections the magnetic field comes into play (23.5) and effects of rotation of the cloud are discussed (23.3). So, really, we cannot take the "debunking of the Watkins model" by Jim Mash seriously, because he obviously has not spend any time really looking into the mainstream model from a good source, like introductory astrophysics books.
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  #154 (permalink)  
Old 01-July-2008, 01:53 PM
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Sabiang.

Earlier I said that a nucleon spins at 10^23rps and therefore its surface speed is equal to c when its diameter is around 10^15m. Hence the electron energy is moving around the nucleon at c. Photons are packets of fluid energy circulating along with the electron energy (as kinetic energy but completely integrated with it and not as a separate entity) and therefore when these are flung away from the electron they also move at speed c.

Now you might think that I chose the spin rate of 10^23rps just to make the surface speed equal to c but in fact I chose this speed for a good reason and it was the very first rate that I tried. FET really started when I considered what a photon would be like if it was a particle and not a wave. This is what led me to consider energy to be a real substance that was extremely compressible because it had to have a very wide range of diameters if what is currently considered to be wavelength is really the diameter of a photon.

Looking at the photon spectrum revealed that photons reached a limit where the maximum energy they could carry was equal to that of a nuclear particle. This suggested to me that as we moved along the photon spectrum and the size of the photon decreased and its energy content increased there came a point where the energy density could no longer change. This suggested that some sort of transition must be occurring at this point and that is when I realised that if energy was a real fluid substance it could reach a point where it could no longer be compressed and hence formed a solid.

I then considered what would be observed if a photon particle was to pass me by. If a photon is considered to be a spherical particle then I would register a pulse of energy that started at zero just as it reached me, went to a maximum as the centre passed by and then dropped to zero again at the trailing edge. Hence it would register as a half wave of energy with a wave height inversely proportional to the amount of energy and a frequency for the highest possible photon energy of 10^23 waves per second, i.e. the upper limit of the electromagnetic spectrum. So I chose to use this as my first calculation for spin rate of a growing neutron particle and naturally it gave a surface speed of c when the diameter of the particle was equal to that of a neutron.

I hop this answers your question,

Jim
  #155 (permalink)  
Old 01-July-2008, 01:54 PM
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Tusenfem,

You accuse me of being confused but you are certainly not grasping the basics of FET. I described how an FET atom consists of nucleons made of solid energy that spin at 10^23rps and have fluid energy circulating around them like a fountain of water. So why on earth do you consider this to be anything like the Bohr model of an atom? In his model, electrons are point size particles whizzing around and kept in orbit by goodness knows what whereas in FET an electron is a stream of fluid energy that is attached to the spinning nucleon and extending away from it and returning back to it as a continuous band of energy that is driven around by the spinning action of the nucleon. The energy density of the electron energy varies with distance from the nucleon according to the inverse square law. Thus an FET atom looks more like a flower with petals radiating in all 3 dimensional and at the end of this posting this picture will clarify another point you have raised.

FET electrons do not change orbits when energy is absorbed or emitted but simply extend or shrink in length. Until the basic points of FET are understood it is not possible to go into details of why each atom absorbs specific amounts of energy. For example, before then you have to understand how fluid energy is stored as kinetic energy, how electricity and magnetism are generated, how the tick rate of an atomic clock changes with speed and gravitational fields and how the speed of light varies with the source atoms etc.

You can see why it is said that an electron has a probability of being found in a certain location if it is considered to be a point like particle moving around the nucleus but if you plot the probability against location you find that it does not resemble a series of specific orbits that an electron can jump between. An FET electron has energy dispersed over a specific region of space and because it is always attached to a nucleon it gives this impression of having a strong attractive force to it. It is possible to tap into electron energy at any point along its path from the surface of the nucleon to as far away as the electron energy extends. For a normal atom that is stationary upon the Earth the extent of an electron is around 10^10m but if extra energy is added there is really no limit to its extent just as long as that extra energy is trapped on a stationary atom and the atom is not moving at a speed commensurate with the amount of added energy. If this was the case then the electron energy would be only extended a fraction of its possible distance.

In FET the notion of the electromagnetic force is replaced by the flow rate of energy. For an electron flowing around a nucleon the flow rate is around 10^39 times the flow rate of energy that a spinning nucleon accumulates and gives rise to the gravitational force. Hence electron energy can be exchanged much faster than it can be gleaned from the flow of continuum energy as gravity. The gravitational force acts over very large distances when a large number of nucleons are packed together because they generate a flow in the continuum that only decreases in strength according to the inverse square law. This flow of continuum energy is translated into a force of acceleration when an electron captures the energy flowing past it and absorbs it as kinetic energy.

One way that the electron flow rate is translated into a force is because a circular flow of fluid energy generates a centripetal force (because energy is a continuous substance which is something you obviously cannot get to grips with). So a hydrogen atom is nothing more than a neutron particle that has grown to its critical size where the centrifugal force equals the centripetal force and some of the solid energy of the core becomes fluidised. Hence a hydrogen atom is a single entity and is not composed of separate proton and electron or even quarks and gluons or any other sort of particle that has to be invented as more and experiments fail to agree with the current model of an atom. Two hydrogen atoms combine to form a single hydrogen molecule by sharing some of their electron energy. Because a certain amount of fluid energy passes around both nuclei it generates a centripetal force (a real one and not a fictitious one) that binds them together. The apparent isolation of a proton and an electron is also a bit too advanced for you yet.

A repulsive force can arise when two flows of fluid energy are circulating in different directions. This can be envisaged as being like two water jets aimed at each other. But electron energy does not always repulse other electron energy. A beam of electrons does not spread out as rapidly as it should do if they are assumed to be point like particles. This is because FET electrons are streams of fluid energy that can flow along together quite happily, although they do repel each other slightly as they expand with distance unless pushed back into alignment by the flow of more fluid energy from say a magnetic field. Likewise, two like magnetic poles can repel each other because they are forcing energy outwards which cannot be combined into a single flow.

And what is wrong with going back to the ideas of Descarte. The ancient Greeks knew about the Earth being a spherical body that orbited the Sun thousands of years ago but that did not stop numerous people after that believing something quite different because it suited them. If Descarte had considered the aether to be a continuous substance and worked out its properties he might have come up with FET all those years ago and by now people like you would be quite happy to believe it.

It is interesting that we arrived at different values for the escape velocity of a giant molecular cloud. I believe that both of the calculations are correct and that there must be a reason for the discrepancy between the two results. A clue can be found in that for the planets, the FET calculations yield flow rates of continuum energy into them which does agree with current values for the escape velocities. Furthermore I believe that the FET value for what I said was its escape velocity of the molecular cloud is also correct because it allows the correct value for the acceleration of an object into the cloud, just as it does for the planets.

I believe that the difference between the FET and the usual method for calculating escape velocities is that the FET method only generates the same value as methods using the gravitational constant when an object is gravitationally bound. Because the Sun and the planets are gravitationally bound objects that are compact enough to generate a flow at their surfaces that is greater than their escape velocities the two methods agree. However, when the matter in the sun is spread over a sphere with the radius equal to the orbit of Pluto (which is what is assumed in the giant molecular cloud example I cited), then the gravitational force is so thinly spread that its pull at the edge of the cloud is not strong enough to overcome the natural speed of atoms. Thus I am correct in equating the flow rate to the escape velocity but only when everything inside that radius is gravitationally bound. If this is correct then the FET method can be used to test whether or not a specific body of matter is gravitationally bound or not. I am continuing with such calculations.


As for the area of an electron being equal to 1.43x10^-18m^2, which I quoted in order to calculate the rate of acceleration of a body into the cloud, this is not the area of a circle or sphere because an electron does not circulate around a nucleon in a complete circle or sphere. I have stated that an electron is a jet of fluid energy that starts out with a diameter equal to that of the nucleon and then spreads out so think of them as I suggested above as being more like the petals of a flower.

In my postings I do not explain everything because that would mean putting over a thousand pages of information here and you have already said that you are not prepared to invest that much time reading my work. So I try to keep it short each time and then if you asked in a civilised way I might be prepared to offer more. However, I have already said that the content of book 1 is available for anyone to read and I am willing to discuss its content where things are not clear. But as for book 2, this is not yet finished and therefore I will tend to restrict what I say about it.

It has proved very useful to discuss the gravitational collapse or not of a gas cloud because it has set me upon a line of thought where I had a potential problem with a particular subject. FET kept on throwing up unexpected answers but I now believe that I can see why it does and moreover why they are correct. So thanks for that.

Jim.
  #156 (permalink)  
Old 01-July-2008, 02:01 PM
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[Snip!]And what is wrong with going back to the ideas of Descartes? The ancient Greeks knew about the Earth being a spherical body that orbited the Sun thousands of years ago but that did not stop numerous people after that believing something quite different because it suited them. [Snip!]
The ancient Greeks did figure out that the Earth is a sphere. One or two did speculate on the Earth orbiting the Sun, but educated opinion of that time settled on a fixed Earth at the center of the Universe, and we are still trying to correct this fundamental error, as the many threads on Geocentricity started by The Poster of a Thousand Sock Puppets will attest.
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  #157 (permalink)  
Old 01-July-2008, 07:53 PM
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Originally Posted by Jim Mash View Post
Sabiang.

Earlier I said that a nucleon spins at 10^23rps and therefore its surface speed is equal to c when its diameter is around 10^15m. Hence the electron energy is moving around the nucleon at c. Photons are packets of fluid energy circulating along with the electron energy (as kinetic energy but completely integrated with it and not as a separate entity) and therefore when these are flung away from the electron they also move at speed c.
first, I think you mean that a proton or neutron has a diameter of 10e-15 meters, otherwise your particle would be very big. I am sure this is a typo.
second, i thought that when we take apart a nucleon, we end up with pairs and packets of quarks.
I completely agree with your assessment (from a previous post) that the atom actually looks like a "turkey leg", this is not a new concept, but has been known for decades, I learned about the structure of the atom and electron shells in my high school chemistry class




but it is well known that a photon does not come off of the nucleon rather the electron shell. the electron is placed in a higher energy shell and drops back to it ground state and the resulting photon that is emitted has a wavelength that is equal to the drop in energy level of the electron.
if this were not the case, then lasers would be impossible to build and if they were, then the resulting wavelength would be random.



Quote:

Now you might think that I chose the spin rate of 10^23rps just to make the surface speed equal to c but in fact I chose this speed for a good reason and it was the very first rate that I tried. FET really started when I considered what a photon would be like if it was a particle and not a wave. This is what led me to consider energy to be a real substance that was extremely compressible because it had to have a very wide range of diameters if what is currently considered to be wavelength is really the diameter of a photon.
yes, energy is a real substance and is infinity compressible, as a matter of fact, matter and energy are the same. and I think that mainstream physics agrees. however, the energy is compressed into Hadrons (fermions, baryons, mesons) and Leptons (electrons, muons and tau) Hadrons are built from quarks while leptons are, well, actually leptons. These particles do not have a diameter, they are "point" particles and are only denoted at a charge. usually in Mega electron volts.

A photon is the carrier of electromagnetic energy, It is a wave first and foremost with particle like qualities. I disagree with the suggestion that a photon is a particle and has a diameter and here is why:

Photons act exactly like acoustic energy and can be described with the same math. They have a wave front that spreads out from the source which is inversely proportional to the square of the distance.
according to your idea, there is no room for the observable effect of entanglement, I have my own idea that actually described how entanglement would happen which from what i have read so far is more plausible. I see the entanglement issues as the simple fact that one photon has a continuous wavefront just like an impulse from an acoustical source. as it spreads out, in a very shot time, the wave front becomes very large and can encompass a huge distance spanning several light years. since it is the same wavefront that carries the same information, it is not unreasonable to have correlations between states of the photon happen at exactly the same time regardless of the distance that the photon is spread out over.


Quote:
Looking at the photon spectrum revealed that photons reached a limit where the maximum energy they could carry was equal to that of a nuclear particle. This suggested to me that as we moved along the photon spectrum and the size of the photon decreased and its energy content increased there came a point where the energy density could no longer change. This suggested that some sort of transition must be occurring at this point and that is when I realised [sic] that if energy was a real fluid substance it could reach a point where it could no longer be compressed and hence formed a solid.
Honestly, there really is no solid anything in matter. matter is demonstratively made of nothing but energy from force fields. hadrons only have diameter because two or more point particles are zooming around each other.

It would seem that you should see if your math would allow for the photon to collapse into a lepton or quark. then work backwards to see if the energy level is the same.


and I dont think the wavelength (frequency) of a photon has no theoretical limit as to the frequency or energy level..


lets look at this thought experiment below.

Quote:

I then considered what would be observed if a photon particle was to pass me by. If a photon is considered to be a spherical particle then I would register a pulse of energy that started at zero just as it reached me, went to a maximum as the centre passed by and then dropped to zero again at the trailing edge.
I really don't think photons are spherical or have any diameter, They are wave function and this is demonstrated every day in any high school lab with a 17 year old, a laser and a razor blade.


Quote:
Hence it would register as a half wave of energy with a wave height inversely proportional to the amount of energy and a frequency for the highest possible photon energy of 10^23 waves per second, i.e. the upper limit of the electromagnetic spectrum.
I am not really a math person but it seems to me that you just said that if you could measure a photon passing buy you, it would have an energy that is a function of of the highest possible frequency that can be obtained by a photon.

you stated that a photons highest possible energy is "10^23 waves per second"

nasa disagrees with you:

Quote:
Originally Posted by nasa
The highest energy measurements of gamma-rays are accomplished using ground-based instrumentation which also measure cosmic rays. Reliable detections of very high energy gamma-ray radiation from individual astrophysical sources, specifically from a couple of active galaxies and from the Crab Nebula, have extended up to about 10^27 Hz (5 x 1012 eV)


http://imagine.gsfc.nasa.gov/docs/as...s/970412e.html
which is several orders of magnitude larger that your figure.

Quote:
Originally Posted by nasa
This diffuse gamma-ray emission is well measured below around 1024 Hz (109 eV) or so, and is expected to extend up to at least 1030 Hz (1015 eV). There have been reports of measurements of diffuse gamma-ray emission above 1029 Hz,
but i have to wonder how you came to the conclusion that the upper energy level would be so low.

Thank you for suggesting an answer, I really appreciate the time you spent chatting.


However, i must say that it still does not answer how electromagnetic waves propagate in space and why EM radiation would follow the same math as acoustic energy.

Thank You again.
Cheers
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  #158 (permalink)  
Old 02-July-2008, 10:35 AM
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Originally Posted by Jim Mash View Post
You accuse me of being confused but you are certainly not grasping the basics of FET. I described how an FET atom consists of nucleons made of solid energy that spin at 10^23rps and have fluid energy circulating around them like a fountain of water. So why on earth do you consider this to be anything like the Bohr model of an atom?
Well maybe your expression:
electron energy is circulating around the nucleons the cores of solid energy are spinning around on the spot and all of the electron energy is circulating around them
got me thinking that the electrons were orbiting.

And the 1023 just happened to come to you (from your reply to sabianq):

Now you might think that I chose the spin rate of 10^23rps just to make the surface speed equal to c but in fact I chose this speed for a good reason and it was the very first rate that I tried.

Just accidentally you "chose" a number and KAHBANG, the surface velocity of a nucleon is c, wow, you must play the lottery!

Quote:
Originally Posted by Jim Mash View Post
You can see why it is said that an electron has a probability of being found in a certain location if it is considered to be a point like particle moving around the nucleus but if you plot the probability against location you find that it does not resemble a series of specific orbits that an electron can jump between. [snip]
Lots of text again disguising the fact that the problem of obfuscation of scientific knowledge is present. This totally goes past the fact that first you say "nucleons" and then you talk about "atoms" in your "chemical bonding to make molecules"

Quote:
Originally Posted by Jim Mash View Post
In FET the notion of the electromagnetic force is replaced by the flow rate of energy. For an electron flowing around a nucleon the flow rate is around 10^39 times the flow rate of energy that a spinning nucleon accumulates and gives rise to the gravitational force.
And what made you chose 1039? This would not, maybe, possibly, accidently come from the "fact that the gravitational force is 1039 times smaller than the electric force" as lots of EU proponents claim constantly? Or what and why?


Quote:
Originally Posted by Jim Mash View Post
One way that the electron flow rate is translated into a force is because a circular flow of fluid energy generates a centripetal force (because energy is a continuous substance which is something you obviously cannot get to grips with). So a hydrogen atom is nothing more than a neutron particle that has grown to its critical size where the centrifugal force equals the centripetal force and some of the solid energy of the core becomes fluidised.
Oh, I can get my head around energy and the centripital force. However, as I commented to Daffyduck, you do not seem to realize what a centripital force is. To you it is a real force in the same list as I gave to Daffy.

So, now hydrogen consists of a neutron and an electron???????????
You are really rewriting physics here.

What force is acting as the centripital force?

Quote:
Originally Posted by Jim Mash View Post
And what is wrong with going back to the ideas of Descarte.
Nothing wrong with Descartes, just making historic parallels here. Although his idea of vortices was not one of his better ideas.

Quote:
Originally Posted by Jim Mash View Post
It is interesting that we arrived at different values for the escape velocity of a giant molecular cloud. I believe that both of the calculations are correct and that there must be a reason for the discrepancy between the two results. A clue can be found in that for the planets, the FET calculations yield flow rates of continuum energy into them which does agree with current values for the escape velocities. Furthermore I believe that the FET value for what I said was its escape velocity of the molecular cloud is also correct because it allows the correct value for the acceleration of an object into the cloud, just as it does for the planets.
Uhhh, both maths are correct and still we get numbers that are 106 apart? I don't think so.

As you refuse to show you calculation of the "acceleration" that you got, I will not believe that you get the same number.

Quote:
Originally Posted by Jim Mash View Post
I believe that the difference between the FET and the usual method for calculating escape velocities is that the FET method only generates the same value as methods using the gravitational constant when an object is gravitationally bound. Because the Sun and the planets are gravitationally bound objects that are compact enough to generate a flow at their surfaces that is greater than their escape velocities the two methods agree.
The nice thing of "Newtonian physics" is that is does not matter actually if the "cloud is gravitationally bound" (if it collapses it NEEDS to be gravitationally bound, but that as an aside). The gravitational pull is not diluted or anything, just all the mass that is in the sphere acts in the gravitational force. But if your FET does not even get something simple like this correct, well.......

Quote:
Originally Posted by Jim Mash View Post
As for the area of an electron being equal to 1.43x10^-18m^2, which I quoted in order to calculate the rate of acceleration of a body into the cloud, this is not the area of a circle or sphere because an electron does not circulate around a nucleon in a complete circle or sphere. I have stated that an electron is a jet of fluid energy that starts out with a diameter equal to that of the nucleon and then spreads out so think of them as I suggested above as being more like the petals of a flower.
So, again another number that we cannot verify and have to trust you to be correct. This starts to look like fundamental religious dogmas, believe them!!!

For the rest, you have not yet said anything about mainstream taking temperature into account in gravitational collapse.
We get no calculations only magical numbers.
"everything will be revealed in the sacred book number 2"

Well, whatever.
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  #159 (permalink)  
Old 02-July-2008, 01:53 PM
Chris Hillman Chris Hillman is offline
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Arrow Wise and unwise approaches for those ambitious to do big things in physics

Looks like the clock has just about run out on this thread. Just wanted to point out that with regard to the issues I raised in this thread, Mash never even attempted to respond to:
  • the elementary logical error I pointed out in my Post #33,
  • the question in my Post #38,
  • the issues raised in my Posts #45-47,
  • my critique of is reponses in my Posts #50-51.
(And I might add that it seems to me, Mash never responded directly to the issues raised by a half dozen other posters. There are so many problems with Mash's claims that we pretty much all addressed nonoverlapping subsets!)

My other posts mostly consisted of my repeating that he had not yet responded to my questions/critiques, with the exception of my Post #63 (written after he seemed to say he would let the thread die), in which I explained why I took the unusual step of making an example of Mash. It seems to me that this is the only post which really matters in the end, because it has general significance. I hope it will help young persons ambitious to do something important in physics to achieve that goal, by making a genuine contribution to science rather than becoming a regular poster of unsupported (and incorrect) ATM claims. Real science is so much more fun and satisfying!
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Last edited by Chris Hillman; 02-July-2008 at 01:59 PM. Reason: add internal link
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