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You should be able to calculate the fuel by using the appropriate equation twice. First, work out how much fuel will be required for the return trip (when the ship's mass is 10,000 tonnes); then work out how much fuel will be required for the first half of the journey (treating the return fuel as cargo, so that the Golightly's mass is 10,000 tonnes + mass of return fuel).
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However, we had to haul this amount of fuel with us to Procyon. Therefore, the total payload to Procyon would be the 10,000 tonnes plus the return fuel of 253,400 tonnes, or, say, 263,000 tonnes. The M/m ratio for 1/4 the trip (midpoint) is 12.67, double for one way, or 25.34. This times the 263,000 tonnes yields 6.7 million tonnes of fuel needed at departure to make the entire round trip. I hope I'm wrong. Of course, IIRC, Procyon is a binary with a white dwarf. With proper timing, and a tidally [and other stress] resistant hull and crew ( ), a tight turn-around at the moment the dwarf's orbital tangent points to Earth should save a few gallons. ![]()
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The equation I used was: scontracted = [c2/g]*[logn(gs+c2) - 2*lognc] where s is the uncontracted distance.
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Lighten up! This is a stellar board! Author: duh. "The Sun, with all the planets revolving around it, and depending on it, can still ripen a bunch of grapes as though it had nothing else in the universe to do..." Author: Galileo supposedly. |
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7.48 lyrs.? (4 x distance to midpoint seen by travelers per your equation, I hope)
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Lighten up! This is a stellar board! Author: duh. "The Sun, with all the planets revolving around it, and depending on it, can still ripen a bunch of grapes as though it had nothing else in the universe to do..." Author: Galileo supposedly. |
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That's what I got.I think I've waited long enough. I was hoping for some more feedback because I'm not entirely confident that my answers are correct. Anyway, these are the figures I worked out (all approximate): Total Earth-time of the Golightly's journey: 26.4 years Total ship-time: 10.1558 years Distance travelled as measured by the ship's crew: 7.48 light-years Total fuel required at launch: 349 million tonnes! I believe George has already posted his question: Quote:
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![]() According to your formula, they would average .74c, whereas their tape measure results per elapsed time would average .41c (assuming my viewpoint is right, of course, though it most likely is not). Even with a contracted spacetime affecting the tape measure, wouldn't they still physically measure 13.3 lyrs. total self-measured distance traveled?
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Lighten up! This is a stellar board! Author: duh. "The Sun, with all the planets revolving around it, and depending on it, can still ripen a bunch of grapes as though it had nothing else in the universe to do..." Author: Galileo supposedly. |
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I derived the equation for calculating the contracted distance thus. I plotted the Gamma-1 factor on the Y-axis against s (uncontracted distance) on the X-axis. Integrating gives the area under the graph, which is the contracted distance (I think!).
According to Relativistic Rocket, Gamma = as/cs+1. Therefore, Gamma-1 = c2/(as+c2). The area under the graph, then, is: s' = c2 ∫ 1/(as+c2) ds = (c2/a)(logn|as+c2| - 2lognc) The equations seem to be correct, then. Taking just the first quarter of the ship's trip (halfway to Procyon), the stats are: Distance (Earth): 5.7 LY Distance (ship): 1.87 LY Time (Earth): 6.6 years Time (ship): 2.54 years. I don't know that you can plug these figures into s=ut+½at2, as that equation is derived from the linear function v=u+ft. Perhaps someone else can explain how the crew can reconcile the fact that they have covered 1.87 LY in 2.54 years, reaching a speed of 0.74c, with the other fact that they can still feel an acceleration of 1.03 LY/year-2.
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for a bonus question, quickly guessed and easily gotten (not to mention worthless in the context of this thread)
what do Polaris and Sirius have in common? besides one r?
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The both have companions brighter in the X-ray band than they are.
William Keel's (ngc3314) new book, The Sky at Einstein's Feet, shows Sirius and SiriusB and talks of this. In the visible Sirius is 10,000xs brighter than its companion. The current question is still active.... Name a single receiver interferometer. [hint: It was an early creation and implented by Aussies succesfully.]
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Lighten up! This is a stellar board! Author: duh. "The Sun, with all the planets revolving around it, and depending on it, can still ripen a bunch of grapes as though it had nothing else in the universe to do..." Author: Galileo supposedly. |
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Another hint, maybe...
It involved Dover and ID. It was from Dover that the IDentity of the size of a radio galaxy was less than 8 arc seconds. ![]()
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Lighten up! This is a stellar board! Author: duh. "The Sun, with all the planets revolving around it, and depending on it, can still ripen a bunch of grapes as though it had nothing else in the universe to do..." Author: Galileo supposedly. |
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Is the question about a "single receiver interferometer"? There are several used in astronomy. Michaelson inerferometers are single receiver and have been used for IR spectroscopy (I acually help with one at Lick Observatory). I suspect what is wanted here may be a Sea Surface Reflection Interferometer.
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It's now yours, IMO. ![]()
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Lighten up! This is a stellar board! Author: duh. "The Sun, with all the planets revolving around it, and depending on it, can still ripen a bunch of grapes as though it had nothing else in the universe to do..." Author: Galileo supposedly. |
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In 1920 a "debate" over the distance scale of the universe took place at the Smithsonian in Washington. On the event of the Diamond Anniversary of this debate, another took place in the same venue with a closely related topic. Name the topics and participants of both debates.
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