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http://www.newtonphysics.on.ca/Anoma...eleration.html
This says it's due to dust in the Kuiper belt. Whaddaya think of that? |
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I say the next probe should bring some Pledge and a dusting rag along to clean up the belt.
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People who think they know everything are a great annoyance to those of us who do. |
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I found this near the end interesting.
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![]() Kizarvexis
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"We don't just borrow words; on occasion, English has pursued other languages down alleyways to beat them unconscious and rifle their pockets for new vocabulary." - James D. Nicoll |
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A giant asteroid that started life off as an alien probe, and then fell to Earth killing the dinos off. Bummer that. |
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But, I am concerned about the titles on the FAQ page. "Series #8 Why Quantum Mechanics is Non-sense? " for instance, or "Series #14 They burn heretics, don't they?". I looked into the Series #10: Energy Required to Move a Mass from the Pole to the Equator. Although I didn't wade through the math, it looks like the conclusions were OK. I was concerned because of the blurb on the main page: " It requires external (Earth) energy to move from the equator to the pole..." That is wrong, as Paul's writeup goes to great lengths to show. The surface at the pole and the surface at the equator are in an equilibrium, as the main body of the article states. The entire surface (geoid, or "sealevel") of the Earth is an equipotential surface, in other words. That's why the water is "flat". ![]() It also neatly explains the relativity phenomenon. |
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I pointed out the IRAS picture to Paul. It's interesting that the Pioneer drag data may be the only direct measurement of the dust density. I was a little surprised that it hadn't been considered before.
The IRAS picture has always been interesting to me because it dramatically shows that the projection of the plane of the ecliptic crosses the galactic plane right at the center of the galaxy. I've always wondered if there's a gravitational reason for this and if it is true for other planetary systems. Unfortunately, so far as I have been able to find out, there is not yet a way to determine the orbital planes of extrasolar planets. We also studied the zodiacal light and gegenschein from Skylab. I collected the pictures for this chapter: http://history.nasa.gov/SP-404/ch3.htm |
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:P
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"As I lay beneath the Southern Cross, the stars tell more than I could" . . . David Meece |
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I'm not impressed. As far as I can tell, once you remove the "filler", they just assume a density and size of "sand" grains which then magically accounts for the acceleration and then they claim their assumptions as the result!
The "study" makes no reference to changes in acceleration over different time frames. If this idea was correct, there should be no anomalous acceleration except while traversing the Kuniper belt. This is not what has been observed. The level of analysis here is pretty laughable when compared to the 2002 study (54 pages worth) by Anderson, et. al. And note that the authors still think there is a systematic reason for the acceleration, so they are not arguing for "farfetched hypotheses". http://xxx.lanl.gov/abs/gr-qc/0104064 |
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Use asteroids to investigate
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Everything I need to know I learned through Googling. |
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Nick :wink: |
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Not to hijack the thread or anything ops: but I'd say you may be on to something.
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My message board, now more fun than ever - Text effects - Sky photos - Element spectra Remember I before E except after C, or be seized by your weird neighbors who have had too much caffeine. |
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But having completed a survey of binary stars with known orbit planes, I did find something interesting. I measured the apparent declination of the galactic center (GC) as seen from each star, referenced to the plane of its companion's orbit. I also took into account the obliquity of the orbit to the galactic plane. If my math is correct (and please do correct me if I've made any errors) then in a perfectly random distribution one would expect a mean obliquity of 90° / sqrt(2), and a mean declination equal to the mean obliquity / sqrt(2). In fact, I found a mean obliquity of 57.46° which is a little over 90% of the expected figure. So there's a slight tendency for stellar orbits to want to lay flat against the galactic plane. The mean declination of the GC is only 71% of the expected figure, meaning the orbits have a considerably greater tendency to line up to the GC as you describe. Furthermore, when each individual star system's apparent GC declination is divided by its obliquity, the resulting mean is higher - closer to 74%. The difference between the 71% and 74% figures can be explained if stars whose orbit planes lie closer to the plane of the galaxy have less tendency to line up with the GC than stars whose planes have a high obliquity. Here is a complete MS Excel spreadsheet of the stars I surveyed and resulting figures.
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My message board, now more fun than ever - Text effects - Sky photos - Element spectra Remember I before E except after C, or be seized by your weird neighbors who have had too much caffeine. |
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Planetary Society coverage of the
2005 Pioneer Anomaly Conference November 6-11, 2005 Quote:
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Everything I need to know I learned through Googling. |