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It's difficult to know if Warren Platts will be pleased or irritated to learn that a variant of his ATM idea has been submitted and accepted for publication in Revista Mexicana de Astronomía y Astrofísica by Poveda & Lara: The Exo-planetary System of 55 Cancri and the Titius-Bode Law.
Grant Hutchison |
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Hmmm, the Titus-Bode law seems to be similar to the "Gas Giants only exist in the ice belt" way of thinking that all solar systems will be similar to ours. The article is trying to make 55 Can., fit into our mode of thinking of planet formation, which is looking to be incorrect due to our system bias.
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Fields of Space LOGIC, n. The art of thinking and reasoning in strict accordance with the limitations and incapacities of the human misunderstanding. In the Year 2525. "One small step for (a) man. One giant leap for mankind". If an astronaut doesn't need good grammar, niether does you. Host of Seraphim |
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But first let me say it's great to hear from you again Dr. Hutchison! How goes it in the land of Hume? ![]() I knew if I sat around, I was going to get scooped. It only took three months. We should have jumped on it Tony! There goes the Nobel. Oh well. . . . ![]() It's a nice paper, (skimmed so far--detailed comments soon to follow) but I don't think they plagiarized me because they left out the most important part: the Monte Carlo simulations. They haven't shown that the 55 Cancri distribution is statistically significant. ![]() But hey, I must say that the best thing of all is that it's nice to know that I'm not the only completely crazy person on the planet! ![]() Edit: Dr. Hutchison, I couldn't help noticing you started this thread in the mainstream astronomy section. Thanks for the compliment! ![]()
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Fitting a three-parameter curve of uncertain form to ten points with three exceptions certainly brings one to the far edge of the known world. -- Bradley Ephron Last edited by Warren Platts : 20-April-2008 at 02:54 PM. Reason: remove rude comment regarding Scotland, an American comedian, and felt production--sorry :) |
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Fitting a three-parameter curve of uncertain form to ten points with three exceptions certainly brings one to the far edge of the known world. -- Bradley Ephron |
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Fitting a three-parameter curve of uncertain form to ten points with three exceptions certainly brings one to the far edge of the known world. -- Bradley Ephron |
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After reading the paper, I still fail to see the significance after the papers by Graner and Dubrulle. Although a nice little result, it is a paper that tells 2 + 2 = 4, but why this is is left untouched.
Secondly, the reason for not assuming Mercury as one of the planets to make the new exponential TB law seems totally superfluous, no reason is given for it, apart from the original TB law also did not use this planet. Does not sound like a real reason to me. And if you have to do this, why not leave out the first planet in the 55 Cancri system? I think maybe reading Lynch and Neslusan will give some more insight into real or chance. From the latter abstract: Quote:
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************************************************** ************************* Optimism does not change the laws of physics. (T'Pol) A good scientist has freed himself of concepts and keeps his mind open to what is. (Dao De Jing 27) ************************************************** ************************* Martin ( http://www.geocities.com/DrMartinV ) |
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Hey tsenfem
Glad to hear from you! Quote:
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Fitting a three-parameter curve of uncertain form to ten points with three exceptions certainly brings one to the far edge of the known world. -- Bradley Ephron |
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![]() In any case, they didn't get into significance testing, so thus the meaning of their R2 is open to interpretation, to say the least. Dayton, in his letter goes on to say that Quote:
(BTW, there was an interesting flurry of interest in the Titius-Bode law among certain American statisticians in the very late 1960's and very early 1970's. I'm trying to put together a bibliography.) But nowadays, a typical desktop computer could do 1 billion or more simulations in a single day if it wanted to. So I think I was on the right track by calculating a probability distribution for each specific scenario. However, reading through the statistical literature on the TBL has made me realize that I perhaps made too much of the actual distributions that I constructed. This is because the question of whether any proposed hypothesis is statistically significant is relative to an alternative null hypothesis that is rejected. Here is what Ephron has to say: Quote:
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![]() Quoting Good, Ephron added Quote:
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On the other hand, if it could be shown that the law of increasing differences as a comparatively uninteresting, alternative, null hypothesis to the Titius-Bode law should be rejected, that would indeed warrant the assertion that the Titius-Bode spacing pattern of 55 Cancri is a real pattern. So, naturally, I had to try it. ![]() I used a simple broken stick algorithm to generate random systems that satisfy the law of increasing differences. The first step is to break a stick of length 1 into 7 pieces--2 end pieces and 5 interior pieces. This is accomplished by drawing six numbers from the uniform distribution ([U[0, 1]). These numbers are then sorted in a nondescending order. Then I calculated the length of the interior sticks by taking the absolute value of the differences between adjacent random numbers, and then the interior sticks themselves were sorted. The next step to generating the random system was to reconstruct the semimajor axes: a2, a3, a4, a5. Note that the one exception to the law of increasing differences in our Solar System is Mercury, in that it is 0.4 AU from the Sun, whereas the distance to Venus is 0.7 AU, thus the difference is only 0.3 AU. Thus, a1 and a6 are already given because the two end pieces were never sorted. The final step was to throw out the 5th planet, because of the empty orbital that Poveda and Lara's model assumes. Once the random system is generated, then the r2 can be computed in the ordinary matter, and stored into the histogram to construct the probability distribution necessary to conduct a significance test. Once the histogram was constructed out of 100 million random solar systems (see attached chart), it was determined that the 95th percentile of r2 fell out at right about 0.9967. Thus, for a 5% level of significance, 0.9967 would be the critical value. The r2 reported by Poveda and Lara of 0.997 exceeds the critical value. (I reported an r2 of 0.9975; but that was rounded up from 0.997488; if I had chosen three significant figures, I also would have had 0.997.) Therefore, we can say with 95% confidence that we can reject the null hypothesis of the law of increasing differences as a possible explanation for the spacing pattern an 55 Cancri. ![]() Granted, a 95% confidence level is not nearly as high as the 99.9% confidence level I reported in that other thread, but there's no glory to be gained in showing that a straw man is false with a confidence level of 99.9%; it is much more satisfying to be 95% sure that one is warranted in rejecting the strongest null hypothesis proposed in the literature so far. (Caveat: these are preliminary results, I need to double check everything and increase the number of random systems to 1 billion to smooth out the curve even more before I send the manuscript into Icarus!)
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Fitting a three-parameter curve of uncertain form to ten points with three exceptions certainly brings one to the far edge of the known world. -- Bradley Ephron |
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REM *** Increasing differences model: Solar System
REM *** Use broken stick technique to generate distances, REM *** then sort the distances to get random system with REM *** increasing distances. Then figure out new A(I)'s. REM *** Then calculate R-squared and add to histogram. REM *** input the number of orbitals (planets) LET ORBITALS = 9 REM *** input the semimajor axis of the innermost planet REM *** note that INNERMOST = mercury's semimajor axis REM *** less A(min) (which is 0.15 AU) LET INNERMOST = 0.23710 REM *** input the semimajor axis of the outermost planet LET OUTERMOST = 29.91107 REM *** input average x for least squares now, because it REM *** never changes LET AVGX = 5 REM *** number of trials between PRNG seed changing LET MAXTRIALS = 100000 REM *** number of PRNG seed changes REM *** MAXTRIALS x MAXCYCLES = total # systems generated LET MAXCYCLES = 10000 REM *** A(i) is for the semimajor axes. A(1) and A(outermost) REM *** never change, so we can set their values now DIM A(ORBITALS) LET A(1) = INNERMOST LET A(ORBITALS) = OUTERMOST REM *** we transform the semimajor axes into logs to compute REM *** the R-squared goodness of fit statistic DIM LOGA(ORBITALS) LET LOGA(1) = LOG(INNERMOST) LET LOGA(ORBITALS) = LOG(OUTERMOST) REM *** D(i) the differences between consecutive orbitals DIM D(ORBITALS - 1) REM *** X(i) is for the x-axis in the least squares zone REM *** X(i) aka the ordinal of the orbitals w/ planets DIM X(ORBITALS) REM *** load the x-axis that keeps track of 9 planets REM *** note it goes {1,2,3,4,5,6,7,8,9} because the REM *** scenario calls for 9 planets, no skipped orbitals, FOR I = 1 TO ORBITALS LET X(I) = I NEXT I REM *** HIST(i) is the histogram that defines the REM *** probability distribution which is the final goal DIM HIST(10001) FOR CYCLE = 1 TO MAXCYCLES REM *** we print the cycle # to keep track of progress of program PRINT CYCLE RANDOMIZE FOR TRIAL = 1 TO MAXTRIALS REM *** We are normalizing to the size of the whole system. REM *** We generate random numbers from within the innermost REM *** to the outermost orbitals FOR I = 2 TO (ORBITALS - 1) LET A(I) = INNERMOST + (OUTERMOST - INNERMOST) * RND NEXT I REM *** now sort in ascending order LET J = 3 DO LET I = J DO IF A(I - 1) > A(I) THEN LET BUFF = A(I) LET A(I) = A(I - 1) LET A(I - 1) = BUFF END IF LET I = I - 1 LOOP UNTIL I = 2 LET J = J + 1 LOOP UNTIL J = ORBITALS REM *** calculate the length of the sticks FOR I = 1 TO ORBITALS - 1 LET D(I) = A(I+1) - A(I) NEXT I REM *** now sort the sticks LET J = 2 DO LET I = J DO IF D(I - 1) > D(I) THEN LET BUFF = D(I) LET D(I) = D(I - 1) LET D(I - 1) = BUFF END IF LET I = I - 1 LOOP UNTIL I = 1 LET J = J + 1 LOOP UNTIL J = ORBITALS REM *** now reconstruct the semimajor axes REM *** you already know A(1) and A(ORBITALS) FOR I = 2 TO ORBITALS - 1 LET A(I) = A(I - 1) + D(I - 1) NEXT I REM *** the following statements are for debugging purposes REM FOR I = 1 TO ORBITALS REM PRINT A(I) REM NEXT I REM PRINT "R-SQUARED = "; REM *** time to figure out the r-squared score REM *** start by tranforming data by taking logarithm REM *** of the semimajor axes, A(i) REM *** we already know the logs of the first and last A(i) LET SUMY = LOGA(1) + LOGA(ORBITALS) FOR I = 2 TO ORBITALS - 1 LET LOGA(I) = LOG(A(I)) LET SUMY = SUMY + LOGA(I) NEXT I LET AVGY = SUMY / ORBITALS REM *** now figure the sums of the squares of the REM *** deviations (x - avg(x)) and (y - avg(y)) REM *** note I don't do X^2 because X*X is faster LET SUMXSQ = 0 LET SUMYSQ = 0 LET SUMXY = 0 FOR I = 1 TO ORBITALS - 1 LET SUMXSQ = SUMXSQ + ((X(I) - AVGX) * (X(I) - AVGX)) LET SUMYSQ = SUMYSQ + ((LOGA(I) - AVGY) * (LOGA(I) - AVGY)) LET SUMXY = SUMXY + ((X(I) - AVGX) * (LOGA(I) - AVGY)) NEXT I REM *** B is the slope of the best-fit least squared REM *** line of the form y = a + bx LET B = SUMXY / SUMXSQ REM *** SSRESID is the so-called residual sum of squares LET SSRESID = SUMYSQ - (B * SUMXY) REM *** now we calculate the R-squared score! LET RSQ = 1 - (SSRESID / SUMYSQ) REM *** next statement for debugging purposes REM PRINT RSQ REM *** this adds the R-squared to the histogram that will REM *** eventually form the probability distribution for REM *** determining the critical value that the observed REM *** R-squared of 55Cnc must exceed in order to reject REM *** the law of increasing differences null hypothesis LET HIST(INT(RSQ * 10000)) = HIST(INT(RSQ * 10000)) + 1 NEXT TRIAL NEXT CYCLE REM *** time to output the probability distribution REM *** the left hand tail is of no interest, so we skip that part FOR I = 1 TO 4999 LET COUNTER = COUNTER + HIST(I) NEXT I FOR I = 5000 TO 9999 REM *** prints out the bins corresponding an R-squared score PRINT USING "%.####": (I / 10000); REM *** print out the number of systems for that bin PRINT USING "##########": HIST(I); REM *** the running total of bins from lowest to highest LET COUNTER = COUNTER + HIST(I) PRINT USING "###########": COUNTER NEXT I LET TOTALTRIALS = (TRIAL -1) * (CYCLE - 1) PRINT "TOTAL TRIALS = "; TOTALTRIALS PRINT "FOR TOTAL PLANETS = "; ORBITALS PRINT "TOTAL LENGTH IS "; OUTERMOST - INNERMOST; "FROM "; INNERMOST; "TO "; OUTERMOST END
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Fitting a three-parameter curve of uncertain form to ten points with three exceptions certainly brings one to the far edge of the known world. -- Bradley Ephron Last edited by Warren Platts : 13-May-2008 at 01:56 PM. Reason: Add source code for the most recent simulation |
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Hello fellow amateurs,
After 17 hours of cranking, my computer generated random solar systems resembling 55 Cancri in that there are 5 planets, 6 orbitals, with the 5th orbital apparently empty--as our near-sighted telescopes report for the real 55 Cancri system--and, best of all, all1,000,000,000 random solar systems satisfy the law of increasing differences.1,000,000,000 I also rechecked every single mathematical and statistical step against the textbooks. The only thing that changed, is that the critical value, once interpolated, edged up ever so slightly from about 0.99673 to 0.99678. The attached chart only shows the very right-handed portion of the probability distribution (the left-handed tail extends all the way back to 0.5003, so it's useless showing all that). But you can see the critical value, and how the R-squared exceeds the critical value. Therefore, we must reject the null hypothesis--the law of increasing differences--in favor of our old friend--the Titius-Bode law--for 55 Cancri. I challenge anybody to find anything wrong with the present analysis. . . . Next stop: The Solar System
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Fitting a three-parameter curve of uncertain form to ten points with three exceptions certainly brings one to the far edge of the known world. -- Bradley Ephron |
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Well, I tryed out the new technique on the Solar System. At first I was dismayed and bummed out that the Solar System didn't even come close to satisfying the 95% confidence level. Now, I'm merely perplexed. It turns out that the probability distributions based on the law of increasing differences behave oppositely compared to the distributions based on the pure random spacing null hypothesis. That is, as you add planets, the former more closely resemble exponential progressions and the median R-squared scores actually improve, whereas for the latter, the median and 95% critical values decline as one adds planets.
Thus, the R-squared for the Solar System, 0.9933--figure includes Mercury and Ceres, but excludes Pluto for the a priori reasons (1) that we know enough about Pluto to know that it is Kuiper Belt object that has somehow made its way into the inner Solar System, and (2) Pluto is in any case locked in an orbital resonance with Neptune, and therefore does not constitute an independent sample--is less than that for 55 Cancri (0.9975); but on the purely random null hypothesis, they had the same level of significance (0.1%). I had expected that under the law of increasing differences null hypothesis, the situation would be similar. However, the Solar System's R-squared fell out at about the 87th percentile according to the probability distribution I generated based on 9 planets, no empty slots, rather than close to the expected 95th percentile. But as you can see from the attached charts, the first clearly shows how sensitive the median R-squared is to increasing planets. The second chart shows that the 95% critical value is not as sensitive, but the important point is that it doesn't decline when more planets are added. (The arrow at the far left is the observed R-squared of the Solar System. The number of trials for each distribution was 10 million.) So now I'm coming around to Hayes and Tremaine's (1998) way of thinking: that the law of increasing differences is an unfair null hypothesis to test against Titius-Bode laws. I'm open to suggestions at this point. Meanwhile, back to the drawing board. . . . ![]()
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Fitting a three-parameter curve of uncertain form to ten points with three exceptions certainly brings one to the far edge of the known world. -- Bradley Ephron |
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I've been reading, and I found this paper by Neslusan (2004), and he says that it's not Mercury or Neptune that are the odd planets out--Earth is the odd planet. So I tryed in my own way to replicate Neslusan's results--and it's true: Earth is by far the planet that doesn't belong! Consider the table below (in all scenarios Ceres is included, but Pluto is excluded because of the a priori reasons that we know enough about Pluto to say it's obviously a Kuiper Belt object, and since it's locked in an orbital resonance with Neptune, Pluto wouldn't constitute an independent sample in any case). The numbers are the corresponding r2 scores: Code:
Only Pluto Excluded 0.9933 Mercury Excluded as well 0.9918 Neptune Excluded " 0.9905 Earth Excluded " 0.9984 |