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My question is, can't you just look up with a powerful enough telescope and see the remains of the moon landings? I mean I know it would have to be REALLY powerful, but can it be done, like with a large ground based scope, or Hubble?
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No. You would need a telescope an order of magnitude (pardon the pun) larger than any existing Earthbound telescope. Search on "Hubble Apollo" to see various discussions in this forum.
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"Slapping a guy on the head is just as funny now as it was eighty years ago." |
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To resolve footprints, about 0.1 meters in size, you'd need a resolving angle about:
resolving angle = 0.1 m/ 4 X 10(8) m = 3 X 10(-10) radians = 5/ 100,000 arc-seconds. This seems way above the resolving ability of any telescope yet built. I would estimate best resolving power with adaptive/active optics would be 1/100 arc-seconds. This would be the diffraction limit for a single 10 m circular aperature, like Keck. (I would estimate with adaptive optics we should be able to reach somewhere in the ball-park of the theoretical limit). The only solution I see is an optical interferometer . Maybe one of those upcoming planet searching telescope arrays will have this feature and will be able to see the footprints? The Terrestrial Planet Finder looks like somewhat of an interferometer array (but that might be IR which I don't think is useful for footprints, maybe for the lunar dune buggies). I doubt Buzz would have gotten so worked up and punched that guy if he really didn't land on moon. ![]()
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"fifty is nifty" , unknown poet Last edited by HypothesisTesting : 11-February-2008 at 08:30 PM. |
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Quote:
resolving angle= width/distance goes to Distance= width/ resolving angle D= 1.2x10^6 m / 3x10^-10 D= .4x10^16 m= about .4 light years so an earth sized exoplanet would be harder to resolve if it were further away then .4 light-years. |
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going by what i've seen on CSI:Miami, they should be able to take any run of the mill digital pic of the moon and enhance it a little bit to make out every individual grain of sand on the moon.
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"blacker than the blackest black... times infinity."- Nathan Explosion The.. Best.. Thread..Ever... |
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Some more answers on this page.
http://www.tass-survey.org/richmond/...ar_lander.html This is the closest we've ever come to revisiting an Apollo landing site. (Scroll to bottom.) |
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Quote:
great. The closest earth-like planet would be further than 4 LY. So to resolve this planet would take angle = 1.2X10(6) / 4 X 10(16) = 3 X 10^-11 radians = 5 X 10^-6 arc-sec. Wow! Also, to resolve continents on these planets would take even more resolution. To estimate the size of aperature required: diffraction limit angle = (wavelength)/ diameter diameter = wavelength / angle = 5 X 10^-7 / 3 X 10^-11 = 20 kilometer (aprox.). So I would conclude we need an optical interferometer at least 20 km in effective diameter to resolve the closest earth-sized planets. To really get medium distance exoplanets and resolve surface features would probably take about a 1,000 km optical interferometer array (with great computing and navigation/pointing ability). Is NASA/ESA planning such an array (or something in that ball-park to resolve earth-like planets). They'd probably use coronographs to reduce starlight also. When I was young, some texts taught that imaging exoplanets was sci fi. But I'm not so sure any more. We could quibble about what the major advances since then are, but I think computers and electronics were the biggest advance . I think NASA/ESA will someday (maybe 20 years?) show images of exoplanets.
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"fifty is nifty" , unknown poet Last edited by HypothesisTesting : 12-February-2008 at 04:38 PM. |
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