If this is your first visit, be sure to check out the FAQ by clicking the link above. You may have to register before you can post: click the register link above to proceed. To start viewing messages, select the forum that you want to visit from the selection below.

Go Back   Bad Astronomy and Universe Today Forum > Space and Astronomy > General Science
Register FAQ Members List Calendar Mark Forums Read

Reply
 
LinkBack Thread Tools Display Modes
  #31 (permalink)  
Old 07-July-2005, 04:02 AM
nutant gene 71's Avatar
nutant gene 71 nutant gene 71 is offline
Senior Member
 
Join Date: Mar 2005
Location: desert city limits, CA USA
Posts: 584
Default

Quote:
Originally Posted by Tassel
Quote:
Originally Posted by davidlpf
Heres my two cents, mass is the amount of stuff in an object, weight is the effect that two objects have on one another say the earth and a person which is F in both equations.
f=m*a or sometimes written f=m*g is the force of acceraleration in gravitional feild of the the earth and can change if the mass of the larger object changed to like a star or blackhole or another planet and the f= m*m*G/(r^2) is just two particles in isolated system like deep
space but this G is a constant of the universe. At least that my version of whats going on i could be could wrong I am often.
Particularly because this thread is in the "General Astronomy" forum, I think that it should be pointed out that you're right on the money, David. All evidence points to a constant G and it seems to me that you correctly understand the difference between weight and mass.
This is all we know for now. If we had reason to suspect otherwise, I am sure we'd be looking into it. And looking is exactly what we are about to do.

Also:
Quote:
Originally Posted by papageno
So, why do you think anomalies like the Pioneer anomalies, have anything to do with G?
Let's leave that to ESA's future probe, where they will have a separated "flywheel" registering inertial mass, and the equivalence principle. But what if they find that inertial mass and spin are different there? Would "equivalence" not dictate a different gravity at work in that part of space, say at 10-30 AU from the Sun, for example? And if that gravity is different, would it not impact how G is measured out there? And if it shows to be a variable, are we prepared to cope with that conceptually?

But I personally think the Pioneers Anomaly is the least of our problems,that there are enough holes out there in our cosmological theories to allow for new thinking. For example:
  • [1.] How are stars born from hydrogen clouds, since there is insufficient gravity to make the clouds come together with enough force to start nuclear fusion, a mystery.

    [2.] "Dark matter" foils our understanding of how galaxies rotate, in violation of the inverse square law for gravity.

    [3.] Why do the gas giants sport such massive atmospheres, especially if the inner core planet is small? Why does our local moon have no atmosphere, but Pluto a small planet a fraction of our moon, or Saturn's Arizon sized Enceladus, does have an atmosphere?

    [4.] How can a "dark matter galaxy" exist, when it has no visible stars?

    [5.] Cosmic light redshift, though now ascribed to a Doppler effect of expanding universe, may find a different interpretation if gravity is different for 99.99% of the spacevacuum between galaxies.

    [6.] Why are there unmodeled gravitational anomalies on Mars, or Venus, for their prominent features? Or why are the giant's rings dirtier near the planet than further out, where they're almost pure water ice?

    [7.] Why did astronomers find "clumps of dark matter" in space?
I think the Pioneers Anomaly is the smallest of our mysteries, judging from the list above. Explaining these things takes incredible contortions of reason, if not outright fancy, such as the Big Bang; including theorized gravity waves never detected, or more "elementary" particles yet to be discovered, like the Higgs boson. There's lots of room for an improved theory on how gravity works, or how it interacts closer in to star generated energies. Can a variable gravity, a variable G as discussed here, be the answer? I don't know. But we should try to see if that may not work better than what we had been working with so far, assuming a universal Newton's 1 G proportional for the whole cosmos.
__________________
Credibility is simply incredible... sometimes even to me.
disclaimer
Reply With Quote
  #32 (permalink)  
Old 07-July-2005, 04:19 AM
Celestial Mechanic's Avatar
Celestial Mechanic Celestial Mechanic is offline
Senior Member
 
Join Date: Jun 2002
Location: Milwaukee, WI
Posts: 3,918
Default

Quote:
Originally Posted by nutant gene 71
Quote:
Originally Posted by Celestial Mechanic
A 10 kg mass weighs 98 Newtons on Earth. It weighs about 16 Newtons on the Moon, but still has a mass of 10 kg.

If somehow G were to be made 10 times bigger than it is now and if the Earth does not compress and get smaller then that 10 kg mass will still be 10 kg but it will weigh 980 Newtons.

This is elementary physics. Please review a good elementary physics text on the distinction between mass and weight.
Thanks C.M., that is how I see it too, in a 1 G universe scenario. I will show below the fundamental difference between that and a variable G universe scenario, should there be a different G elsewhere. It may have a profound effect on lots of things we now cannot seem to explain. Remember that the "kilogram" is dimensionless, a scalar, unlike G, which is a cubic meter per kilogram per second squared (m^3 kg^-1 s^-2) dimensional.
Wrong, the kilogram is a unit, coequal with the meter and the second.
Quote:
Originally Posted by nutant gene 71
Take out the kilograms, and you still have the cubic meters per second squared, so this is something not contingent on the kilogram itself, but a "proportional" force in its own right which affects the mass. The mass is in kilograms.
Again, the kilogram is a unit and cannot be dispensed with. There is an exception to this, though. It is a common practice to set c=1 (eliminating seconds in favor of meters) and h-bar=1 (eliminating meters in favor of kilograms^-1). This simplifies computations considerably. However, it is understood that when it is time to give real results in SI units the answers must be multiplied by the appropriate powers of c and h-bar so that the answer is in SI units. We haven't really dispensed with any of these units at all.
Quote:
Originally Posted by nutant gene 71
Now, the current existing physics books do not address the possibility that these kilograms, really an arbitrary unit developed from the (metric system) cubic decimeter of water, which we use to measure mass are capable of being anything else. That's what's being explored here.
You (and your various previous incarnations/identities) have been pointed to numerous references in the literature where variable G and variable masses have been considered.

I happen to believe in variable G and variable masses myself, but not in anything as drastic and noticeable as what you and the now-banned Jerry have been promoting. In my theory (which is a long way from ready for prime time) the masses of leptons and quarks depend on the expectation values of at least two scalar fields, and ...

Excuse me, there's a knock at the door.

[A little later]

It's OK, it was a razor salesman at the door. I assured him that I was not multiplying entities endlessly, in fact, I use those two scalar fields to provide the value for my varying G. The curious thing is that while the lepton and quark masses vary, the nucleon masses do not vary as much because chromodynamic fields are the main source of nucleon mass, not the quark content. In my theory, if the scalar fields are smaller by a factor of x, lepton and quark masses are smaller by a factor of x, nucleon masses are maybe (1-x/20) times as large (can't calculate this yet), spectral lines are longer (redder) by a factor of 1/x and G is stronger by a factor of x^-2.

I am not optimistic of this variability existing on the galactic scale where it could explain the velocity curves, but there may be a small variation on cosmological scales. More research is needed.
__________________
Microsoft is over if you want it.

The bar has been lowered for the promotion of ATM ideas; the bar for the acceptance of ATM ideas must remain high.
Reply With Quote
  #33 (permalink)  
Old 07-July-2005, 10:15 AM
papageno's Avatar
papageno papageno is offline
Senior Member
 
Join Date: Feb 2004
Location: Silicon Saxony
Posts: 3,200
Send a message via MSN to papageno
Default

Quote:
Originally Posted by nutant gene 71
Per the Equivalence Principle, gravitational mass equals inertial mass, always. "Gravitational" mass is a function of G, as my basket of apples illustration shows above, which is equivalent to its "inertial" mass. The same basket, or cubic decimeter of water, can be either one kilograms (in 1 G), or ten kilograms (in 10 G).
:roll:
I see that you still do not grasp the difference between kilogram-mass and kilogram-weight.

You basket has a weight of 1 kg-weight = 1 kg-mass * g on Earth, and of 10 kg-weight = 1 kg-mass * (10*g) on your planet.
The inertial mass of 1 kg-mass has not changed.

Quote:
Originally Posted by nutant gene 71
If we want the whole universe to be figured in Earth's arbitrary measure for mass, our kilograms, then 10 G means the inertial-gravitational masses are always 10 kilograms.
Wrong.
The force on them is ten time higher: their masses are not.

Quote:
Originally Posted by nutant gene 71
But this causes a problem with how masses interact locally, because if kilograms for their local measure of G are different from ours, then each kilogram will need to be "locally" different from ours.
Of course you are referring to the weight, measured in kg-weight, and not to the mass, measured in kg-mass.

Quote:
Originally Posted by nutant gene 71
The ramifications of this is that local mass interacts differently than here on Earth. If so, then using Earth's kilograms becomes a poor, and ingenuous choice, since it fails to explain how in a different gravitational G "proportional" masses may hold together in ways that our 1 G (1 kg) cannot explain. Let me explain this further in your next.
The masses are not proportional to G.

Quote:
Originally Posted by nutant gene 71
Why would you say G is a "physical quantity"?
Because it can be measured.
Newton's law for gravitation gives at least an operative definition of G, which allows researchers to measure it.

Quote:
Originally Posted by nutant gene 71
Is it not merely a "proportional" quantity between gravitationally attracted masses?
Is it not a quantity that can be measured?

Quote:
Originally Posted by nutant gene 71
If G attracts at 1 G, that is the proportional attraction between the masses, which are measured in kilograms. If G's proportional attracts at ten times our 1 G, then the proportional attraction between masses increases by tenfold.
The force increases, but not the masses.

Quote:
Originally Posted by nutant gene 71
But if each mass is now tenfold in terms of its (equivalent) inertial mass,....
It is not: the gravitational force increased because you increased G not the masses.

Quote:
Originally Posted by nutant gene 71
... then the attraction is ten times ten (two bodies interacting), so the interaction between them is what?
Why?
You already increased G: G' = 10 G.
Then you assume out of the blue an increase in mass: m' = 10 m, M' = 10 M.
That would make the force: F' = 10*10*10*F = 1000 F.


Quote:
Originally Posted by nutant gene 71
If each side has an "eqivalent" mass that is ten times greater, and the G "proportional" between them is ten times greater, saying merely that the mass is now 10 kilograms is not enough, because they attract by a larger proportional. And that, really, is why it is important to redefine our (arbitrary) kilogram in a different G scenario.
It is not, because the definition of kilogram-mass does not depend on the value of G.

Quote:
Originally Posted by nutant gene 71
This is also why I brought up the question in the first place, because I don't know if the answer is tenfold or one hundredfold. This question cannot be raised in a 1 G universe,...
Your question can be raised with G as universal constant.
Your problem is the distinction between kg-mass and kg-weight: you just need to go to the Moon to raise that question, and find the answer.

Quote:
Originally Posted by nutant gene 71
....but it can be raised in a (hypothetical) variable G universe. So, yes, I understand what you are saying, if the universe is only 1 G throughout, but I am forced to disagree with you, because it does not apply in a variable G universe.
No, you do not understand.
You still confuse weight with mass.

Quote:
Originally Posted by nutant gene 71
No. The Equivalence Principle is NOT independent of the value of G.
So, how come it does not show up in the relevant equation?
M(grav) = M(inertial).

Quote:
Originally Posted by nutant gene 71
We know the inertial mass and gravitational mass are the same. Gravity acceleration is a function of its "proportional" G.
And of the distance and mass of the other mass (for example, Earth).

Quote:
Originally Posted by nutant gene 71
Acceleration of mass is inertially "proportional" to G.
Because the gravitational force is proportional to G.

Quote:
Originally Posted by nutant gene 71
Therefore, they are BOTH a function of the G proportional.
:roll:
If the acceleration of a mass is due to gravity, then your "gravity acceleration" and "acceleration of mass" are one and the same!
And sinc this acceleration depends on the garvitational force exerted on the mass, of course it depends on G.
But this does not imply that the mass that is accelerated depends on G.


Quote:
Originally Posted by nutant gene 71
Change G and you change the "proportional" to how mass interacts.
Because the force changes.

Quote:
Originally Posted by nutant gene 71
Why is this so difficult to understand? Or is it because you think ONLY of G as a "universal constant", and cannot imagine it being something different? Okay, for now, that is how the world of physics sees it. But change G, hypothetically, and what have you got? The same "proportinal"? No!
Change G and you change the force.
Change the force and you change the acceleration.

G mM/r^2 = F = a M, and
G' mM/r^2 = F' = a' M
If G' = 10 G,
G mM/r^2 = F = a M, and
(10 G) mM/r^2 = (10 F) = (10 a) M.

You see? M is subjected to ten times the acceleration, becasue the force is ten times stronger.
But you, with no justification whatsoever, assume a change in M.


Quote:
Originally Posted by nutant gene 71
Quote:
Originally Posted by papageno
Quote:
Originally Posted by papageno
Newtons' formula for gravitation:
F = G * (m*M) / r^2 (1)

Newton's second law:
F = M * a (2)

Equivalence principle: M in (1) is the same as M in (2).
M(1) = M(2): where does G enter?
a = G * m/ r^2.
So, you admit that G, even through a, does not enter M(1) = M(2).


Quote:
Originally Posted by nutant gene 71
Quote:
Originally Posted by papageno
Weight is a force!
Changing G changes the force, hence the weight. It does not affect the mass.
You're really stubbornly holding on to this notion that our 1 G is it. Let's go back to this:

F = Ma

If the gravity F is ten times, then (as an either or case) either 10 F = M * 10 a; or, 10 F = 10 M * a. Which would you choose?
Experimental results show that it is (10 a).
Why are you attributing the change to M?


Quote:
Originally Posted by nutant gene 71
They are not the same: If you choose the prior, mass is calculated in Earth's 1 G kilograms, and acceleration is tenfold (gravity acts ten times on mass). This has been your argument all along, I believe. On Jupiter, a much greater mass than Earth's, the acceleration is increased by its greater (1 G) gravity.
And on Jupiter the weight of 1 kg-mass is higher!


Quote:
Originally Posted by nutant gene 71
But if you choose the latter, you're in a 10 G universe, then mass is calculated in 10 G "kilograms" (where each kilogram is tenfold ours, same cubic decimeter of water but "weighs" ten times ours, and ten times per equivalence), but acceleration remains the "same".
Unfortunately for you, we observe the first case, where the acceleration is larger.


Quote:
Originally Posted by nutant gene 71
Is this the same acceleration we had in our 1 G universe? I don't think so, since it is already tenfold ( a = 10 G * m/ r^2 ), so that it pulls ten times as hard on the (tenfold kilograms) of mass. The end result is that in 10 G universe, tenfold acceleration pulls on tenfold mass.
You forgot to justify where the change in mass comes from.


Quote:
Originally Posted by nutant gene 71
Whether we are pushing or pulling on this mass, it should remain equivalent. If 10 F = 10 M * a, and the "a" is already tenfold because G is tenfold, then gravity acts ten times on a mass that is ten times greater.
You cannot even be consistent.
You had mutually exclusive options: either 10 M or 10 a.
You chose 10 M, so you cannot change a: a stay the same (not the "same").



Quote:
Originally Posted by nutant gene 71
Therefore, in 10 G universe, the 10 F (gravitational equivalence) acting on mass is tremendous (a square of 10), and that means matter interacts there differently from our 1 G universe. Conversely, per equivalence, the nertial mass will now take a much greater (1 G) force to move the 10 G mass (10 squared). If the inertial mass is now ten times (10 kg) what it was in our 1 G universe, the force needed to move it will be 100 times our 1 G force. but only tenfold in local 10 G "kilograms". And THAT is why a variable G universe is different from our known 1 G universe.
You forgot that the inertial mass can be measure using non-gravitational forces.
And by doing such experiments, you would see that the inertial mass has not changed, even if G changes.


Quote:
Originally Posted by nutant gene 71
Are we conceptually prepared to think this way? In my opinion, we are not.
Your opinion on serious misconceptions and deep misunderstandings.
I explained to you uncountable times that a variable G is not an exotic concept, nor mathematically challenging.
It would exactly like a variable dielectric constant in electrostatics, which is commonplace, and easily dealt with.


Quote:
Originally Posted by nutant gene 71
Equivalence is still preserved, but it takes a different set of rules for a (hypothetical) universe where G is variable:

Mass has not changed, only how we measure it changed.
:roll:
You still do not understand how mass is measured.


Quote:
Originally Posted by nutant gene 71
Quote:
Originally Posted by papageno
Quote:
Originally Posted by nutant gene 71
To "weigh" mass is merely to subject it to Earth's gravitational acceleration, a = 9.8 m/s^2, so its "weight" could be said to be 9.8 kg m s^-2, but it's still the same kilogram. The apples still "weigh" one kilogram on the balance scale, their mass had not changed. If per equivalence you accelerated the basket of apples by the same rate, they would show the same "weight", but they are still one kilogram of mass, mass had not changed.

The question then remains, that if this one "kilogram" of apples were accelerated at 98 m/s^2 (where Earth's G' is tenfold), would it still be the same "kilogram"? No, the "weight" would change to 98 kg m/s^2, but the mass is still the same (1 kg) basket of apples, but now they weight 10 kgs.
kilogram is a unit of mass, not weight.
The weight you get is (1 kg)*(local g) N, where "local g" is the local gravitational acceleration on the surface of the planet; on Earth local g = 9.8 m/s^2, so 1 kg -> 9.8 N of weight.
On your planet, local g = 98 m/s^2, so 1 kg -> 98 N of weight.

Quote:
Originally Posted by nutant gene 71
Same 1 kg. basket of apples, same mass, but Earth changed its G. What happened? Does the balance scale tip towards the apples rather than towards the one cubic decimeter of water? No, it does not. Now the cubic water mass is 10 kg. Does 1 kg = 10 kg? No sir, it does not.
I see that you are confusing weight and mass.
1 kg(weight on Earth) = 1 kg(mass)*g = 9.8 N.
On your planet, g is different: g' = 10 g, hence
1 kg(weight on planet) = 1 kg(mass)*g' = 98 N.
ibid.
So, you still do not understand.


Quote:
Originally Posted by nutant gene 71
Quote:
Originally Posted by papageno
Quote:
Originally Posted by nutant gene 71
Now can you see why I find this hypothetical question so challenging? I realize this is merely a "what if" question, but what if we find that other worlds or regions of space have a different G? If we find this, then it is truly exciting!
I see only a confusion about the unit kilogram.
It is not for weight, but for mass.
ibid.
You persist in your misconception.


Quote:
Originally Posted by nutant gene 71
Quote:
Originally Posted by papageno
Quote:
Originally Posted by nutant gene 71
Quote:
Originally Posted by papageno
Quote:
Originally Posted by nutant gene 71
Now, if the Xians (per illustration above) think their 10G is merely Gx (one unit of G'), then of necessity their equation would be: Gx = r^2 * 10a/ (?m). This is the problem I'm trying to show. Should (?m) now not be, in Xian kilograms, 10m? So per "their" equivalence, kgx = 10kg in ours.
And how is that different from using another system of units?
Who is right, the Xians or the Earthians?
They are both right: they are just using different units.
Europeans are right when they say that I am 180 cm tall;
US citizens are right when they say that I am 71 inches tall.
Yes! It's all relative to where you measure.

...snip...
The numbers attributed to physical quantities depends on the system of units.
You have shown that this concept is beyond your grasp.


Quote:
Originally Posted by nutant gene 71
Quote:
Originally Posted by papageno
Quote:
Originally Posted by nutant gene 71
Quote:
Originally Posted by papageno
Quote:
Originally Posted by nutant gene 71
In fact, if Gx is ten times G, the density of the planet need not be affected, only the results of what things would weigh there, and by equivalence, how things would respond to acceleration (and perhaps also affect their centripetal force, so affect their planetary spin).
Wrong.
The dynamical measurements would not be affected by a different value of G.
Only the gravitational force would be different, not the mass.
Wrong. Yes, only "the gravitational force would be different", but so also would the effective "kilograms" for mass.
In this case, there is no such thing as "effective kilograms".
The kg unit for mass odes not change.
What changed is the gravitational acceleration at the surface, hence the gravitational force is difeerent = different weight.
Mass does not change, same basket of apples. But the inertial mass changed.
You are contradicting yourself: either mass does not change, or it does.


Quote:
Originally Posted by nutant gene 71
Quote:
Originally Posted by papageno
Quote:
Originally Posted by nutant gene 71
Same mass, but in 10 G, equivalence is now 10 kg (for the 1 kg basket of apples). Remember that it is G we're talking about for a planet that had not changed in size or volume, only the G changed. The cubic decimeter of water had not changed, only its effective "weight" had changed. Where m = 1 kg before (at 1 G), the mass (same mass, still cubic decimeter) is now m' = 10 kg (at 10 G).
Only if you use kg for weight, which is wrong.
You should use N, the unit for force.
Either or. Kilograms are derived from Earth's gravitational force on one cubic centimeter of water (plantinum-irridium artefact) and also a standard of measure for weight through most of the world.
:roll:
Why can't you understand the difference between kg-mass and kg-weight?
Why is it so hard for you?


Quote:
Originally Posted by nutant gene 71
Quote:
Originally Posted by papageno
Quote:
Originally Posted by nutant gene 71
I see that as a change in the mass's "dynamic measurement", where a new "kilogram" defines (measures) the cubic decimeter of water. (Remember, 1 kg does not equal 10 kg for the same mass.)
And you see wrong.
Becuase the inertial mass has not changed.
In your 1 G universe, inertial mass has not changed. In a variable G universe, it has changed, as per above.
The "above" is misguided and wrong.


Quote:
Originally Posted by nutant gene 71
Quote:
Originally Posted by papageno
Quote:
Originally Posted by nutant gene 71
Quote:
Originally Posted by papageno
Quote:
Originally Posted by nutant gene 71
Can you see where this is taking me?
You start from a very serious and deep misunderstanding of measurement unit, force, mass and acceleration.
This won't take you anywhere.
I am beginning to see you have a serious conceptual disconnect with what is being discussed here.
You do not grasp the difference between weight and mass, confusing the unit kg(mass) with the unit kg(weight on Earth) = 1 kg(mass)*9.8 m/s^2.
ibid.
Translated: "I have no clue." Is this what you mean?


Quote:
Originally Posted by nutant gene 71
Quote:
Originally Posted by papageno
Quote:
Originally Posted by nutant gene 71
It looks to me like you're still thinking 1 G, but ten times more powerful, in a 1 G universe. The conceptual adjustment necessary is to think in terms of a 10 G (or any variable G) universe, and then measure the new "kilograms" from there.
Wrong.
I already explaiend to you uncountable times that a variable G is not an exotic concept, but unsupported by observations.
Correct, a variable G is unsupported by current observations. That's why this exercise in reason is only hypothetical.
But you clearly do not grasp the basics for this kind of speculations.
Hence you are reaching wrong conclusions.


Quote:
Originally Posted by nutant gene 71
[snip!]
Quote:
Originally Posted by papageno
Quote:
Originally Posted by nutant gene 71
How would such a buble of gas exist otherwise? We're not talking about soap bubbles here (where the outer surface is held together by water tension), but vast collections of molecules put into immense spin, around what? More gas? Since I obviously don't know, I'd be curious as to your idea of what's inside Jupiter, really!
I see no numbers to support your idea.
Can you show that the mass of Jupiter cannot be held together by gravity?
I don't see your answer.
You made claim: the burden of proof is yours.


Quote:
Originally Posted by nutant gene 71
...snip...

Quote:
Originally Posted by papageno
Quote:
Originally Posted by nutant gene 71
Quote:
Originally Posted by papageno
Quote:
Originally Posted by nutant gene 71
These were my reasons for bringing up this question. (At this point, however, I don't even want to get close to what this means for Einstein's General Relativity theory.) For this reason, I titled this question as "hypothetical" only, until such time that we find G to be otherwise than now postulated.
The postulate is based on a wealth of experimental evidence, which you simply ignored.
No, not ignored, but only considering as possible theoretical explanations without final verdict.
Where did you consider it?
Experiments are not final judgements forever. They need to be periodically and critically reviewed, so new models emerge. Otherwise, your skating dangerously close to the thin edges of dogma.
:roll:
Galileo's experimental results are still valid today.
__________________
papageno


"Why waste time learning, when ignorance is instantaneous?" - Hobbes (Calvin and Hobbes)

"It's all about context!" - Vince Noir (The Mighty Boosh)

"I've never heard of such a brutal and shocking injustice that I cared so little about!" - Zapp Brannigan (Futurama)
Reply With Quote
  #34 (permalink)  
Old 07-July-2005, 12:32 PM
Maksutov's Avatar
Maksutov Maksutov is offline
Honored Member
 
Join Date: Jan 2004
Location: Fifth corner of the Earth
Posts: 16,731
Default Re: Hypothetical variable mass in hypo variable G?

Jerry may be gone, but his "spirit" lives on.

You have a lot more patience than I, papageno! That's praiseworthy. But after all these corrections with no meaningful responses, it must be wearing at least a little thin by now.

Meanwhile, good work re your replies. A shame your target audience doesn't seem to comprehend physics fundamentals. :-?
__________________
A person's name, or a mark representing it, as signed personally or by deputy, as in subscribing a letter or other document.
Reply With Quote
  #35 (permalink)  
Old 07-July-2005, 12:42 PM
papageno's Avatar
papageno papageno is offline
Senior Member
 
Join Date: Feb 2004
Location: Silicon Saxony
Posts: 3,200
Send a message via MSN to papageno
Default Re: Hypothetical variable mass in hypo variable G?

Quote:
Originally Posted by Maksutov
A shame your target audience doesn't seem to comprehend physics fundamentals. :-?
My jaw dropped to the ground when I realized nutant gene 71's misconception about the kilogram.
It's a pity that he persists in it.
__________________
papageno


"Why waste time learning, when ignorance is instantaneous?" - Hobbes (Calvin and Hobbes)

"It's all about context!" - Vince Noir (The Mighty Boosh)

"I've never heard of such a brutal and shocking injustice that I cared so little about!" - Zapp Brannigan (Futurama)
Reply With Quote
  #36 (permalink)  
Old 07-July-2005, 11:12 PM
nutant gene 71's Avatar
nutant gene 71 nutant gene 71 is offline
Senior Member
 
Join Date: Mar 2005
Location: desert city limits, CA USA
Posts: 584
Default Re: Hypothetical variable mass in hypo variable G?

Quote:
Originally Posted by Maksutov
Jerry may be gone, but his "spirit" lives on.

You have a lot more patience than I, papageno! That's praiseworthy. But after all these corrections with no meaningful responses, it must be wearing at least a little thin by now.

Meanwhile, good work re your replies. A shame your target audience doesn't seem to comprehend physics fundamentals. :-?
Maksutov, I think all here have had a lot of patience with my attempt to communicate something I see as a conceptual conundrum, but it seems no one picked up on it. So I take it as my personal failure to communicate something I see, but I don't know how else to present it. I've run out of ideas!

In papageno's last big post I counted at least 10 times where he says I'm "wrong" or "don't understand", so must accept this as my failure. In my previous incarnation (as "Lunatik" now in permanent 'safing') I had shown a paper on Atomic Mass with some mathematical scratchings on how G is different for each orbital region (which happens to unexpectedly grow at the rate of one G per AU), but then too I was told how wrong I was, or didn't understand, by the same parties, so pulled it from its site for review (it's up for peer review at the moment). I don't have the answers, and would not have them unless further astrophysical research measured a different Newton's G, which has not happened. So I remain isolated with my conceptual conundrum, which is okay with me, as it is something on which I can further meditate.

I would like to leave off here with this article at Space.com: First Invisible Galaxy Discovered in Cosmology Breakthrough, which too me is worth more than "a picture's worth a thousand words", since no picture appears.

I sincerely hope we can discover a variable G in the future, because if we cannot, then God help us, for this universe, in the present form of our understanding, makes absolutely no sense. I see our present cosmology as pure fantasy.

In my vision of the universe, gravity is a variable determined by the G proportional where it is measured. That is not the same as to say that greater gravity is merely greater acceleration between masses, but it means that the actual mass itself has changed, per equivalence, and thus the resulting interactions of these masses is between the greater masses. Obviously, not one else thinks so, at least not at present.

No fault. My next project is to work out how much gravity we would need in the 99.99% of the space "vacuum" to account for redshift z = 1, but haven't worked it out yet. Thanks for your inputs, and to all who had their say, appreciate it.
__________________
Credibility is simply incredible... sometimes even to me.
disclaimer
Reply With Quote
  #37 (permalink)  
Old 08-July-2005, 09:49 AM
papageno's Avatar
papageno papageno is offline
Senior Member
 
Join Date: Feb 2004
Location: Silicon Saxony
Posts: 3,200
Send a message via MSN to papageno
Default Re: Hypothetical variable mass in hypo variable G?

Quote:
Originally Posted by nutant gene 71
In papageno's last big post I counted at least 10 times where he says I'm "wrong" or "don't understand", so must accept this as my failure. In my previous incarnation (as "Lunatik" now in permanent 'safing') I had shown a paper on Atomic Mass with some mathematical scratchings on how G is different for each orbital region (which happens to unexpectedly grow at the rate of one G per AU), but then too I was told how wrong I was, or didn't understand, by the same parties, so pulled it from its site for review (it's up for peer review at the moment).
Let's be clear: it has been shown and explained where you are wrong.


Quote:
Originally Posted by nutant gene 71
I don't have the answers, and would not have them unless further astrophysical research measured a different Newton's G, which has not happened. So I remain isolated with my conceptual conundrum, which is okay with me, as it is something on which I can further meditate.
We tried to get you out of your coneptual conudrum, but you simply dismiss our explanations by saying that we just would not understand.

Now, do you understand that kilogram-mass is not the same as kilogram-weight?
__________________
papageno


"Why waste time learning, when ignorance is instantaneous?" - Hobbes (Calvin and Hobbes)

"It's all about context!" - Vince Noir (The Mighty Boosh)

"I've never heard of such a brutal and shocking injustice that I cared so little about!" - Zapp Brannigan (Futurama)
Reply With Quote
  #38 (permalink)  
Old 08-July-2005, 11:42 PM
nutant gene 71's Avatar
nutant gene 71 nutant gene 71 is offline
Senior Member
 
Join Date: Mar 2005
Location: desert city limits, CA USA
Posts: 584
Default Re: Hypothetical variable mass in hypo variable G?

Quote:
Originally Posted by papageno
Quote:
Originally Posted by Maksutov
A shame your target audience doesn't seem to comprehend physics fundamentals. :-?
My jaw dropped to the ground when I realized nutant gene 71's misconception about the kilogram.
It's a pity that he persists in it.
Sure hope you didn't break a tooth!

You forget I wrote in my above, July 5th:
Quote:
Originally Posted by nutant gene 71
To "weigh" mass is merely to subject it to Earth's gravitational acceleration, a = 9.8 m/s^2, so its "weight" could be said to be 9.8 kg m s^-2, but it's still the same kilogram. The apples still "weigh" one kilogram on the balance scale, their mass had not changed. If per equivalence you accelerated the basket of apples by the same rate, they would show the same "weight", but they are still one kilogram of mass, mass had not changed.

The question then remains, that if this one "kilogram" of apples were accelerated at 98 m/s^2 (where Earth's G' is tenfold), would it still be the same "kilogram"? No, the "weight" would change to 98 kg m/s^2, but the mass is still the same (1 kg) basket of apples, but now they weight 10 kgs. Same 1 kg. basket of apples, same mass, but Earth changed its G. What happened? Does the balance scale tip towards the apples rather than towards the one cubic decimeter of water? No, it does not. Now the cubic water mass is 10 kg. Does 1 kg = 10 kg? No sir, it does not.
Mass does not change. But it's measured inertial mass, per equivalence, just like its weight, does change. Place 1 kilogram cubic decimeter of water on a balance scale in a 10 G universe, it would still balance with 1 kg of platinum-iridium rod on the other side; but this rod/cubic water is now on a scale in 10G; so it registers (each side independently) as 10 kg. That's the equivalence of gravitational mass (weight/gravity related) and inertial mass (acceleration related/equivalence) that makes a difference in the new measure of mass, where the same 1 kg of mass registered differently, now as m' = 10 kg for G' = 10 G. And that dear sir, is the conundrum.

It's not that the Earth is suddenly ten times larger in mass, same planet same mass, but the G changed, and that is what changes the (measured) mass, not the acceleration, but the mass. Remember my original question:

Hypothetically, per Equivalence Principle, what would kilograms be for any given mass in a variable G?

You answer it with 'acceleration' changes in terms of G; I answer 'mass' changes in terms of G.

Your answer makes sense in a 1 G universe, forever universally the same. My answer makes sense in a universe where G is variable. But I know you cannot (or will not?) see this. My conclusion is that if you did see it, you'd have to admit to the possibility our current take on the universe is possibly wrong, and variable gravity is a real possibility. By rejecting my idea, you're safe, nothing need change, and G is a universal constant.

I do not wish to offend you Sir, but that is how I read your responses, though I do appreciate them all the same, really.
__________________
Credibility is simply incredible... sometimes even to me.
disclaimer
Reply With Quote
  #39 (