|
| If this is your first visit, be sure to check out the FAQ by clicking the link above. You may have to register before you can post: click the register link above to proceed. To start viewing messages, select the forum that you want to visit from the selection below. |
|
|||||||
| Register | FAQ | Members List | Calendar | Mark Forums Read |
![]() |
|
|
LinkBack | Thread Tools | Display Modes |
|
|||
|
Quote:
|
|
||||
|
Quote:
|
|
|||
|
The puzzle only states that there are 5 blue-eyed people, but it doesn’t state how many brown-eyed or other-colored-eyed people there are.
If there are 5 blue-eyed people that we know of, and if we assume there are 15 brown-eyed people in the tribe, I don’t see how the professor’s statement would cause anyone to know what color their own eyes are, because both the blue-eyed people and the brown-eyed people would already know there are blue-eyed people and brown-eyed people in the tribe, but that wouldn’t tell anyone what color their own eyes are. So under the given fact of 5 blue-eyed and the assumption of 15 brown-eyed, what has the professor revealed that they didn’t already know? Remember that the professor was only talking about the group’s similarity to his own blue-eyed/brown-eyed family, and not about their similarity to all the various eye-colored people in the world. Now, suppose there are 5 blue-eyed people in the tribe, 14 green-eyed people in the tribe, and only one brown-eyed person in the tribe. The professor would have then revealed information that the one brown-eyed person did not already know, and since that person could see that no other person in the tribe is brown-eyed, that must mean that he is brown-eyed. |
|
||||
|
Quote:
Quote:
|
|
||||
|
Quote:
|
|
|||
|
Quote:
That’s changing the rules of the puzzle. The puzzle actually said, “Imagine a tribe of people who are legendary logicians, but who have a curious religious commitment that if they are ever able to determine the color of their own eyes, they must commit ritual suicide in front of the whole tribe at the tribe's daily meeting.” The puzzle doesn’t say anything about an option of leaving the island. If we are going to introduce possibilities that aren’t given in the premise to the puzzle, we can make up anything we want, and we might as well say that when the professor said what he did, all 20 people laughed and said, “Well, heck, there goes our religion, cause I ain’t gonna kill myself!” If you want to change the rules of the puzzle, then we might as well say the professor just talked them out of killing themselves. If you really want the “leaving the island” solution, you need to state that option in the premise of the puzzle, or not rule it out, because you said "they must kill themselves". You didn't say "they must either kill themselves or leave the island." You’ve already said they must kill themselves. Now you are saying they wouldn’t kill themselves. So the puzzle and the solution are both invalid. |
|
||||
|
Well, no. the OP doesn't preclude leaving the island. It does lay out some very specific things that are required for suicide. Leaving just invalidates one of these required things and precludes suicide.
__________________
Quaeso quousque humi defixa tua mens erit? Nonne aspicis, quae in templa veneris? |
|
||||
|
You misunderstand, Sam5. They must still kill themselves if they determine their own eye color. What we are looking for now is a way to prevent them from figuring out their eye color. That will require drastic measures, like leaving the island (which seems less drastic than suicide or murder). So the current question is, who must leave the island?
|
|
||||
|
Quote:
|
|
||||
|
Quote:
Much discussion about how to save the tribe revolves around a blue effectively being removed (or removing him/herself) from the game, to prevent the learning process that would otherwise take place. The discussion is then about what methods of removal are allowed, e.g., is murder acceptable, is indirect murder (my solution, telling a blue s/he's blue) acceptable, is exile allowed by the rules of the game, etc. But quite apart from that, I don't think removal of a blue from the game stops the catastrophe; it only postpones it. Right after the initial revelation, a learning process begins which, unless somehow stopped, leads to the mass suicide of the blues. Now, the same process by which the blues learn they are blue is also taking place among the browns. Furthermore, the learning process of the blues does not depend on the actions of the browns, and the learning process of the browns does not depend on the actions of the blues. But both take place simultaneously. However, because there are more browns than blues, the fuse on the brown bomb is longer than the fuse on the blue bomb, and the blue bomb therefore detonates first. The detonation of the blue bomb also causes the brown bomb to go off the next day, so the learning process taking place among the browns is wholly irrelevant. However, if we find a way to remove a blue from the game, thereby defusing the blue bomb, the brown bomb is still ticking, and will go off in fifteen days. So now everyone lives longer, and the blues live longer than the browns this time, but they still all end up dead. So, unless I have fallen into error, it is not enough to take a blue out of the game somehow; both a blue and a brown must be taken out... Nick |
|
||||
|
Let's work it up. Suppose the leaver was a bluey.
- If he was the only bluey, then everyone would only see brown. However, noone would know their own own colour (each would reason that they and the leaver may have been the only 2 blues), and would live happily ever after. - If there were 2 blues, the remaining bluey would see all browns (but still no idea that he was blue, as above). The others would see 1 blue (and not know whether they were blue as well). Both live happily ever after (even after 1 day, bluey would still have no idea). ... And so on. Neat, so it does restore the uncertainty. If the leaver was (as everyone knows) a brown, then the blues know that nothing's changed. However, once the leaver has gone, another tribe member may make a similar gesture (and then another, and another ...) until the tribe sees that a blue-eyed hero has departed, whereupon they all breathe a big sigh of relief ![]() (I still think it might have been easier for the visitor to say "You know, my colour-blindness stops me from distinguishing blue and green!") [ Edited to remove incorrect preamble] |
|
|||
|
Quote:
There is not enough information in the original puzzle for any of them to determine their own eye color, if we know that 5 are blue-eyed and we assume, as Ken says, that the other 15 are brown-eyed. Because 15 brown-eyed ones already know that 5 are blue-eyed and that 14 are brown eyed. And 5 blue-eyed ones already know that 15 are brown-eyed and 4 are blue-eyed. They don’t have to wait 4 or 5 days to learn this. They already know this before the professor arrives on the island. But no one knows if they themselves are blue-eyed or brown-eyed, because the professor didn’t tell them and they didn't tell each other and the professor didn't tell them the number of how many had which color. This is something that WE know, if Ken’s assumption about the 15 is correct, but this is not something that THEY know if the professor didn’t tell them. Based on the original puzzle and Ken’s assumption that 15 are brown-eyed, the visitor to the island gives them no new information that would allow any of them to determine their own eye color. ![]() So, I think something is missing from the premise of the puzzle or that Ken’s assumption is not correct. |
|
||||
|
Quote:
|
|
||||
|
Quote:
Quote:
|
|
||||
|
Quote:
|
|
|||
|
Quote:
|
|
||||
|
Quote:
Begin with some counter-factual scenarios, but these need to be considered to figure out what happens. Case 1 - only one blue. If this is the case, then the next day the only blue commits suicide, because s/he can't see anyone else with blue eyes, but knows a blue exists. Knowledge required - everyone knows that there is at least one blue (actually, that's more than good enough, but let's go with it). Case 2 - only two blues. The two blues are not aware that there are two blues, they think there might be only one. But if there were only one blue, that person would have committed suicide on the first day. It didn't happen. The two blues now know there must be two blues, but they can only see one. Guess who the other one is? Time to commit suicide on the second day. Knowedge required - everyone knows there is at least one blue (guarantees suicide will take place the first day if there is one blue), and everyone knows that everyone knows there is at least one blue (so they will correctly interpret the non-suicide of the first day). Case 3 - three blues. The three blues don't know there are three blues, they think there might be only two. If there are only two, the two blues will commit suicide on the second day. They didn't. There must be three blues, and since they can only see two other blues, each blue has now figured out that s/he is a blue. Knowledge required - same knowledge as in case 2, and also everyone knows that everyone knows the same knowledge as in case 2 (so they will correctly interpret the two days of non-suicides). Keep going this way until we get to five, and presto, all the blues off themselves on the fifth day... Nick |
|
|||
|
Quote:
But Ken has already said in the puzzle itself that there are 5 blues and 15 browns. There are no other "cases" but that. The professor gives them no information to tell any of them which they are, blue or brown, since he mentions no numbers to them. Ken mentioned the numbers to US but the professor didn't mention any numbers to THEM. And they already knew there were blues and browns on the island. |