If this is your first visit, be sure to check out the FAQ by clicking the link above. You may have to register before you can post: click the register link above to proceed. To start viewing messages, select the forum that you want to visit from the selection below.

Go Back   Bad Astronomy and Universe Today Forum > Space and Astronomy > General Science
Register FAQ Members List Calendar Mark Forums Read

Reply
 
LinkBack Thread Tools Display Modes
  #1 (permalink)  
Old 17-May-2008, 04:00 AM
yawyaw's Avatar
yawyaw yawyaw is offline
Member
 
Join Date: Oct 2007
Posts: 62
Default Maxwell's Equations Revealed

Maxwell's Equations represents the Conservation of the Electric field strength E. E is the Force per unit charge. Maxwell's Equations are usually represented by four equations, two scalar or real equations and two vector equations.

These four equations are really just a single quaternion equation. Quaternions are four dimensional and model the spacetime universe. It is time to abandon spacetime and just talk about quaternion four space. Quaternion four space contains the Real Space and the Complex Space.

Quaternions consist of a real unit (1) and 3 vector units(i, j and k). The Rules that define quaternions are:

i2 = j2= k2=ijk=-1

A quaternion E-field is E= Er + iEx + jEy + kEz = Er + Ev, where Er is the real part and Ev is the vector part.

In traditional Maxwell's Equations the real part of E is not seen.

William Rowan Hamilton developed quaternion in 1843 as a means of mathematically rotating a line in three space. It took him 15 years to discover that he needed a four space to mathematically do the rotation.

Hamilton developed vectors and the vector differential operator called Del:

Del= id/dx + jd/dy + kd/dz

Hamilton's Del is not a quaternion differential operator so I added d/dr to Del to have a Quaternion Differential Operator, I call X for change:

X= d/dr + Del = d/dR + id/dx + jd/dy + kd/dz

R is the real space and is also "time" in spacetime, r=ct. dr= cdt.

Thus X= d/cdt + id/dx + jd/dy + kd/dz


With this introduction lets look at Maxwell's Equations in their complete form.

0=XE=(d/dr + Del)(Er + Ev) = (dEr/dr - Del.Ev) + (dEv/dr + DelxEv + Del Er)


Many of you may not recognize Maxwell's Equations becuase they were developed in the days before spacetime. Lets introduce time into the equations with r=ct:

0=XE=(d/cdt + Del)(Er + Ev) = (dEr/cdt - Del.Ev) + (dEv/cdt + DelxEv + Del Er)


Still don't recognize Maxwell's Equations then lets rediscover Maxwell's discovery that there is a relationship between the Electric and the Magnetic fields such that: E=cB = zH = zcD

0=XE=(d/cdt + Del)(Er + Ev) = (dBr/dt - Del.Ev) + (dBv/dt + DelxEv + Del Er)


Now things are coming into view. These are two of Maxwell's Equations. The real part is the Continuity Equation and the vector part is Faraday's Equation.

0=(dBr/dt - Del.Ev)

0=(dBv/dt + DelxEv + Del Er)

Substituting H for E gives the other two equations:

0=XE=(d/cdt + Del)(Hr + Hv) = (dDr/dt - Del.Hv) + (dDv/dt + DelxHv + Del Hr)


We really don't need four Maxwell's Equations there is really only one Equation, the Invariance of the Electric Field. The equations 0=XE is the four space invariance equation.

Let's understand this equation better. 0=XE says that E is spacetime Invariant. It also says E is is bounded, it has limits. It also says that E is continuous, it also says that E is homeostatic. The sum of the vectors being zero means the vectors are coplanar and form a closed polygon in this case a triangle. Two legs of the triangle are right angles to each other so it is a right triangle. The hypotenuse is the dEv/dr = dEv/cdt. DelxEv is called the curl of Ev and Del Er is called the Gradient of Er. The curl is perpendicular to the Gradient. under 0=XE, Del Er = Del.Ev n where n is the unit radial vector. The curl specifies rotation around the origin and the gradient specifies expansion or contraction towards the origin.

The real part of 0=XE is the Continuity Equation and dEr/dr = Del.Ev.

You can compare these Equations to the traditional and see differences.

Is there a reason to use mixed space and time units or can we just use space units with the r=ct?

Finally, the vector derivatives are not intuitive ,their geometric equivalents may help.

0=XE=(d/cdt + Del)(Er + Ev) = (dBr/dt - Del.Ev) + (dBv/dt + DelxEv + Del Er)


0=XE=(d/cdt + Del)(Er + Ev) = (dBr/dt - Ev/r cos Ev) + (dBv/dt + t Ev/r sin Ev + n Ev/r cos Ev)


Cos Ev is the cosine of the angle between Ev and radius unit vector n for normal . The transverse unit vector is t in th plane of Ev and n vectors. dBv/dt is the hypotenuse of the right triangle formed by the three vector terms.

Last edited by yawyaw : 21-May-2008 at 06:21 PM.
Reply With Quote
  #2 (permalink)  
Old 20-May-2008, 08:23 PM
Christopher Ferro's Avatar
Christopher Ferro Christopher Ferro is offline
Senior Member
 
Join Date: Oct 2001
Location: The Space Coast
Posts: 1,221
Default

My head a splode!!!

CJSF
__________________
Two years ago moved from my town
I was looking up past the city lights
But the city lights got in my way

See the constellation ride across the sky
No cigar, no lady on his arm
Just a guy made of dots and lines

-from "See The Constellation"
by They Might Be Giants
Reply With Quote
  #3 (permalink)  
Old 26-May-2008, 04:37 PM
Fortis Fortis is online now
Senior Member
 
Join Date: May 2004
Posts: 2,156
Default

Yawyaw, what happened to the source term, i.e. charge and current densities?
Reply With Quote
  #4 (permalink)  
Old 27-May-2008, 03:00 PM
yawyaw's Avatar
yawyaw yawyaw is offline
Member
 
Join Date: Oct 2007
Posts: 62
Default

Quote:
Originally Posted by Fortis View Post
Yawyaw, what happened to the source term, i.e. charge and current densities?
The fields are related by E= cB = zH = zcD = D/epsilon.

The charge density Del.Dv= dDr/dR=dDr/cdt = rho charge density = d(e/4pi R^2)/dR= -2Dr/R= -e/2pi R^3.

The charge density is the real derivative of the real field or the time derivative of the real field divided by the speed of light, c.

The real change of the real surface density (Dr) is the charge density. At the boundary or continuity condition, the real change of the surface density is the divergence of the vector field. The vector boundary condition gives the current densities:
0 = dDv/dR + DelxDv + Del Dr = dDv/dt + DelxcDv + Del cDr= dDv/dt + DelxHv + Del Hr= dDv/dt + DEl xHv + Jr (current density)

Last edited by yawyaw : 13-June-2008 at 07:40 PM.
Reply With Quote
Reply


Thread Tools
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

vB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are On
Pingbacks are On
Refbacks are On


Similar Threads
Thread Thread Starter Forum Replies Last Post
Why There's More Matter Than Antimatter in the Universe Fraser Universe Today Story Comments 29 30-April-2008 01:38 PM
The energy machine of Joseph Newman banquo's_bumble_puppy Off-Topic Babbling 179 12-December-2007 11:01 PM
Densemass Equations snp.gupta Against the Mainstream 18 27-September-2007 01:30 AM
Maxwell's equations and constant c grav Questions and Answers 9 08-September-2007 05:40 AM
Maxwell's equations, electromagnetism, etc - what does it all mean?? Nereid Questions and Answers 70 06-June-2007 09:48 AM


All times are GMT. The time now is 10:30 PM.


Powered by vBulletin® Version 3.6.8
Copyright ©2000 - 2008, Jelsoft Enterprises Ltd.
LinkBacks Enabled by vBSEO 3.0.0
©  2006 Bad Astronomy and Universe Today