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Voltage is the amount of Electron Pressure in a power source, or a curcit. Amperage is the Flow Rate (or current rate) of the electrons though a conductor or semi-conductor Wattage is the factor of both counted together V*A = W However you are right they do have a duality, Voltage (In an AC or RF circit can be stepped down, this increases the available current and vis versa. If you double your voltage you halve your Amperage, halve you voltage you double your amperage.
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"There is no problem that cannot be solved by a suitable application of high explosives" - US Army Demolitions School http://worldsofothersuns.home.comcast.net/ |
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) framework of Duality. In electric terms, voltage is energy per unit charge, which is the dimension of both (scalar) potential and EMF. In SI units, which I'll use throughout, that's a joule per coloumb. However, that is the same thing as a weber per second, and the curl E/Faraday's Law relation shows: Integral(E dot dl) = -d(Phi_B)/dt. That equates voltage which magnetic current (flux per time). Flux and charge have the same units -- indeed, they're the same thing really. And likewise, the curl H equation shows that magnetic voltage, MMF, is given by: Integral(H dot dl) = I + d(Phi_D)/dt. The unit of MMF is an Amp. And you can verify that an amp can also be expressed as a joule per weber, and an A/m (unit of H) is a Newton per weber, or force per magnetic charge. Let's look at that just for fun. And amp is a coulomb per second, electric charge per time. But an amp is a Watt per volt, or Joule per (volt-second). From the above relation, we know a volt-second is a weber, so there we have it, an Amp is a joule per weber, or magnetic voltage. You can also see this from magnetic energy relations, such as Energy = 1/2 LI^2 = 1/2(Phi_B)I --> I = 2*(Energy)/Phi_B, showing the units of I, electric current, are energy per magnetic flux/charge. And finally, for those who want to get really deep, what is the product of magnetic and electric charge/flux? That is, what is a coulomb-weber? Get a piece of that action (very punny). -Richard |
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Jackson (and other advanced, graduate level texts) go in the details of Duality. But if anyone is interested in discovering duality for themselves, here's something to get you started. It's more fun and meaningful when you figure it out for yourself, I think:
To start, write Maxwell as she would be in her full form with both monopoles and electric charges: div D = rho_e; curl E = -J_m - dB/dt div B = rho_m; curl H = J_e + dD/dt D = epsilon*E, and B = mu*H rho_e and J_e are the electric charge and current densities, and rho_m and J_m are the corresponding monopole densities. Note the minus sign on the curl E equation -- that's what Ken and I were talking about with Lenz's law. Note I've written it in perfectly symmetric form without the constants as I prefer to keep the constants in the relations between the (E, H) and (D, B) pairs. Adding monopoles shows the perfect symmetry. Now, consider a transform of the following form: E' = aE + bH H' = cE + dH where a, b, c, d are just scalar constants, and a^2 + b^2 = c^2 + d^2 = 1 Substitute that in for E and H and get a new set of Maxwell equations in E' and H'. Consider the relationship between (a, b) and (c, d). Think of E and H as orthogonal basis vectors in a plane. Choose (c, d) in terms of (a, b) so H' is orthogonal to E'. Thus a/b is the tangent of an angle of rotation in that plane. What happens when you do that? Now, pay careful attention to what happens to the *source terms* in that transform. Pay careful attention to how that a/b ratio affects the source terms. That is Duality. We could, if we wished, do a 90 degree rotation and say electric charge is now "magnetic monopoles", and E is H and B is D (but pay careful attention to the relative sign of D vs what we now call B under such a rotation -- you'll see we must preserve the minus sign on curl E). Everything would work just as it is now, except everything would "flip". We'd be measuring voltages in amps, and currents in volts. Capacitance would in henries and inductance in farads. Resistance(reactance, impedence) would be in mhos(siemen is the official name, now) and conductance(susceptance, admittance) in ohms. A bar magnet would be a bar electret -- the earth would have an electric field, not a magnetic one. And there would be no electric monopoles. At first blush, you may protest, No, no, that can't work, that's crazy! But trust me, it does. All physical interactions would be the same, the only difference is the *words* (and words for units) we use to describe it. That is Duality. And, if we wanted to be even more complicated, we say do a 45 degree rotation. Electrons have equal amounts of electric and magnetic charge, producing a combination of divergent electric and magnetic fields. Currents produce a combination of solenoidal electric and magnetic fields. The earth's magnetic field would now be both electric and magnetic. Bar magnets would have both components as well. That would make the bookeeping a bit more complex, but it would work exactly the same. -Richard |
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