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Old 14-April-2006, 12:44 PM
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Smile Time for Pythagoras?

This is a great graphical puzzle.

Here is quarter of a circle centred at the cartesian origin. We can see the x and y axes. A vertical line drawn upwards from mid-point B touches the circle and then goes across horizontally to point A.

What is the length of the line AB? Please show your working.



Don't cheat!

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Old 14-April-2006, 12:52 PM
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Let the triangle shown be ABC.
10^2 - 5^2 = 8.66 = BC (This is calculated by connecting the origin O and the point C)

AC = 5
AB^2 = 5*5 + 8.66*8.66
AB = 10
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Old 14-April-2006, 12:55 PM
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Quote:
Originally Posted by randb
Let the triangle shown be ABC.
10^2 - 5^2 = 8.66 = BC (This is calculated by connecting the origin O and the point C)

AC = 5
AB^2 = 5*5 + 8.66*8.66
AB = 10
Hmm very fast. But you didn't need Pythagorus.

clop
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Old 14-April-2006, 12:59 PM
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Line AB would be the same length as the line that runs from the center of the circle to the point where the tip of the rectangle touches the arc. This means that this line would be 10 units long. 5 from 0,0 to A and 5 from A to the point where the arc crosses the x Axis.

Line AB=raius of circle which is 10. (5+5)
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Old 14-April-2006, 01:20 PM
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lol...i figured that out after I got the answer.
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Old 14-April-2006, 04:54 PM
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Default Non Sequitur

'But it's so simple. All I have to do is divine from what I know of you: are you the sort of man who would put the poison into his own goblet or his enemy's? Now, a clever man would put the poison into his own goblet, because he would know that only a great fool would reach for what he was given. I am not a great fool, so I can clearly not choose the wine in front of you. But you must have known I was not a great fool, you would have counted on it, so I can clearly not choose the wine in front of me.'


Uh... sorry, wrong question
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Old 14-April-2006, 08:41 PM
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No Pythagorus, just simple trig: since the cosine of angle A is 1/2, that's a 30-60-90 triangle, and the length of the hypotenuse AB is then the radius of the circle, 10 units.

(BTW, Roy Batty and others who get his joke, go look at absurdnotions.org. Actually, that's amazingly doubly applicable to this thread now.)
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Old 14-April-2006, 09:36 PM
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Without having seen any other posts :- 10, because it is equal to the radius of the circle.
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Old 15-April-2006, 01:46 AM
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I haven't seen anything yet after the words "don't cheat",
though I know there are several replies already.

Informally...

Since the line from B to the circle is vertical, and the line
from there to A is horizontal, you have drawn a rectangle.
The line AB is a diagonal of the rectangle. The other diagonal
(not drawn) goes from the center to the circle, so its length
is 10. The diagonals of a rectangle are equal, so the length
of AB is 10.

-- Jeff, in Minneapolis
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Old 15-April-2006, 11:51 AM
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I didn't get it.

What I can tell you is, the name's Pythagoras, not Pythagorus. Even if you don't need him.
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Old 15-April-2006, 12:22 PM
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Quote:
Originally Posted by Arneb
I didn't get it.

What I can tell you is, the name's Pythagoras, not Pythagorus. Even if you don't need him.
Sounds very much like a case of sour grapes to me.

clop
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Old 15-April-2006, 05:43 PM
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Quote:
Originally Posted by clop
Sounds very much like a case of sour grapes to me.

clop
No, clop, that was Aesop, not Pythagoras.
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Old 15-April-2006, 07:45 PM
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I think there is a special rule for 30/60/90 triangle.

short leg = a
long leg = a * sqrt(3)
hypotenuse = 2a

2a = 2(5) = 10
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Old 15-April-2006, 07:50 PM
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Quote:
Originally Posted by clop
Sounds very much like a case of sour grapes to me.

clop
Oh no, I can live with my mathematical limitations. Just a case of the nitpicking gene breaking through. No offence .
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Old 15-April-2006, 07:50 PM
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Quote:
Originally Posted by Dr Nigel
No, clop, that was Aesop, not Pythagoras.
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Old 16-April-2006, 08:04 AM
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Quote:
Originally Posted by Dr Nigel
No, clop, that was Aesop, not Pythagoras.
No, Dr Nigel, that was Ęsop, not Aesop.
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