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In the interest of science, I will break my vow of silence and accept whatever wrath this incurs
![]() Mr. Mozina, when I asked about additional images under different filter sets, I was inquiring if such existed of the arcs/filaments (can I just call 'em filaments? It just comes naturally to me that way) in question, as a means of comparing the iron content to that of other elements. Obviously, when filtered specifically for a given element, that element will prove to be the most abundant visible. If we could filter for a spectral signature for lead, it would be the most abundant element in those images also. But, with proper calibration, a true estimation of the proportions of the various elements could be acquired from such a set of images. The reason this seems significant to me is that if it came out that there was only evidence of say, < 1% of the material in the "filaments" being iron, through analysis of properly calibrated images, that would, by definition, affect your proposed model. Images of that nature do not appear on your website, and I am asking if you have searched for such, and, if so, what you have found. As a neophyte, I am intensely curious also about what the curent model's explanation for the arcs might be, and do hereby beg anybody who knows to present as persuasive an argument as possible about their nature under the current model. The description of the shifted magnetic fields causing a difference in electrical potential, resulting in massive electrical equatorial arcs *does* seem almost intuitive to me if approached from the (vaguely defined) model that has been described. Note to all involved: it is no flattery to convince me one way or the other - I lack the foundation most of you so eloquently display. But you could consider this a kind of "public outreach" to the uninitiated, if you chose. Many thanks. Sincerely, Derrick Baumer |
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1. Light emitted by atom/molecule transition from one energy level to another; since those levels are quantized the emitted spectrum is discreet and unique for each chemical element, therefore this kind of emission is used in spectroscopy. 2. Blackbody radiation, emitted in a continuous spectrum and depending only on the temperature. (I must point out that both those mechanisms have the same origin: the energy is emitted in quanta, so you accept or reject them both.) 3. Synchrotron/cyclotron radiation: produced by an accelerated charged particle. It has a continuous spectrum. There are other mechanisms that produce light, but already you may see that our sun give a spectra that is a superposition from (at least) three other spectra, two continuous and one discreet. Quote:
Why don't you ask dr. Manuel or dr. Bruce what do they think about this "50 cents" formula? You'll be surprised. Quote:
You can do your own calculations for what spectra will have a body with a specific temperature using the formula at the bottom of this page: http://scienceworld.wolfram.com/phys...cementLaw.html Of course a highly ionised Fe ion will give also a photon having exactly 284 A; fortunately for us the sun has only 6000 °K at the surface, therefore it's thermal emission at 284 A is very weak and is not masking the Fe ions emission. Quote:
And there is more; actually any body that surround you is emitting at 171 A: your computer screen, your chair, yourself. By using that "50 cents" formula you can compute how much energy you're releasing at this wavelength. (you'll need to know your temperature: it should be around 300 °K ) Quote:
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The neon inside a fluorescent bulb don't give off VISIBLE light; that's why the fluorescent bulbs are coated with phosphor. The phosphor is the one actually shining in a neon lamp... since the sun give visible light would you concede that is actually phosphor on it's surface and not neon? Quote:
Last edited by Baloo; 25-September-2005 at 10:57 PM. Reason: Remove double quote |
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I'm curious - do the blackbody radiation formulae apply in the case of the filaments? The argument seems to be that the amount of radiation with that particular spectral signature, *if the source is ionized iron* (correct me if that isn't the proper term), cannot be produced without the kind of heat generated by massive electrical arching through them. That argument is being countered by the possibility that the filaments are emitting at that frequency through a basic blackbody radiation mechanism? If so, the calculations would be based on the area of the filament in question, right? Not the area of the sun? Do the numbers still hold up then?
As usual, I won't be offended if I'm ignored. Derrick Baumer |
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The point being that in the case of neon lights, as opposed to fluorescent lights, it actually is the neon that is emitting the light under electrical current, or argon, or whatever other esoteric element they came up with. Sincerely, Derrick Baumer
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If I'm wrong, you probably asked me the wrong question. Last edited by seohtu; 25-September-2005 at 11:29 PM. Reason: Typo alert! |
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Thank you for those links, Baloo. Now I don't have to learn anything else new until tomorrow. Phew!
![]() Am I correct in my understanding, then, that one side is arguing that we are looking at continuous spectra in the provided images, which would be visible equally regardless of the elemental composition or source of heat in the filaments, at various wavelengths, and the other side is arguing that we are looking at emission spectra from ionized iron, which could only occur under extreme electrical current or other source of extreme heat, and should only be highly visible at specific frequencies? The easies validation on this specific point, then, would be to locate a spectral analysis of such an arc projecting from the sun, without the light from the sun interfering with the reading. Do we have the technology to do this? Has it been done? Can we acquire that data? Should cartoonists be required to be drawn cartoon characters fully dressed? Where would one look for this kind of data? As the theory being presented is Mr. Mozina's, do I understand correctly that it would be his responsibility to acquire such data (if it is, indeed, relevant) and explain the results of its analysis in terms of his theory?
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If I'm wrong, you probably asked me the wrong question. |
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What I've said is indeed true only for argon/mercury fluorescent lamps. Concerning Neon emission: "The neon spectrum is dominated by red lines. That's why neon signs are red." (from here) Doesn't look like sun light to me... ![]() |
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If you would like to show me how your admittedly viable option applies to these images, I will consider it. I will concede that it "could" apply, but not that it "does" apply. Quote:
Point noted. Now if you will be so kind as to show me how it applies to our sun...... ![]() Quote:
Before I go any further, I would like to start there. Agreed? What accelerates these emissions and concentrates them in the arcs that is not electrical in nature? |
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You may take a look here and here and here to see what is all about...you could jump to the last pages in each thread since they're pretty long. ![]() |
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When you are ready to discuss the g_band frequency and how it relates to the photosophere, I believe I am ready. That frequency just so happens to form with neon and helium, which in my model would define the boundry zone between the neon and helium layers. If ever there was a strong argument for my model this is it. Thanks for dropping that bit of info in my lap. I should have made that link already and your question piqued my curiousity. As you see this particular frequency is linked to helium and neon and the border areas of my model, specifically the heat conducting tops of the phenumbral filament layer, where neon meets helium. |
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Am I illustrating my ignorance by asking what is the evidence that these projections are accompanied by increasing magnetic fields? I don't doubt that such evidence exists - I am simply unaware of it.
I think (God help us) that Baloo is trying to establish what is apparently an accepted scientific fact that "Continuous spectra (also called a thermal or blackbody spectra) are emitted by any object that radiates heat (has a temperature). The light is spread out into a continuous band with every wavelength having some amount of radiation. For example, when sunlight is passed through a prism, it's light is spread out into it's colors." --- http://coolcosmos.ipac.caltech.edu/c...rial/spec.html and that this means the specific wavelength you are referring to can, indeed, be emitted by any element. It would just be stronger in relation if the source were electrically-charged iron. I may be projecting my own question onto his by asking if a thorough spectral analysis of these projections would be able to differentiate between the continuous spectra emitted by *any* element in the arcs and the specific spectra produced by ionized iron. It appears that simply detecting energy at those wavelengths does not necessarily prove a strong presence of iron.
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If I'm wrong, you probably asked me the wrong question. |
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I'll keep working on it however. |
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Incidently, a "running difference" image is made to show and emphasize differences between frames. It is not the same as a conventional photograph. It is a perfect example of why you cannot just "look at the picture." Unless you have the full context and understand what it means, your assumptions will likely be incorrect. Now, I have a hunch you won't agree with my answer, but will you "be a man" and accept that I answered it and put it to rest? Or will you deny it and ask endless questions based on your interpretations? Quote:
If somebody points out an error in my statements I take it as constructive criticism and study the subject and drop out of the discussion until I understand where I made my error. If somebody suggests I study a subject, and if I don't know why, I'll ask for details. Then, where appropriate, I'll study the subject to correct my misunderstandings. You have said a number of things that lead me to suspect you are unfamiliar with certain subjects. For instance: Quote:
It comes down to this: I'm far from the only one who has noticed apparent misunderstandings in your statements. Given that you are the one that is trying to overthrow a good chunk of well established science, don't you think it would help to research these subjects in more detail?
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I say there is an invisible elf in my backyard. How do you prove that I am wrong? Disclaimer: Avatar is not an official NASA image and does not imply any specific interplanetary or interstellar capability. The Leif Ericson Cruiser |