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I asked this question in another thread, and was not satisfied with the answer, so I'm posing it here in the Q&A section.
Interferometers measure a phase-change between two beams of light that take different paths. This phase-change is interpreted as a change in distance, with the implicit assumption that the wavelength of light does not change. I.e. a phase change of 360 degrees is interpreted as a change in distance of 1 wavelength of the light used. For example, in high-precision measurements of thermal coefficient of expansion, an interferometer will be attached to a metal rod of a known length. The the rod is heated by a known amount, say 10 degrees. The interferometer measures the phase change in the length of the path between the ends of the rod. The phase change is interpreted as a chnage in length of the rod, under the implicit assumption that the wavelength of light does not change with temperature. In other words, the measurement rests on the assumption that the "measuring stick," the wavelength of light, does not change with temperature, that which is being measured. The interferometer used in the Gravity Wave Detector works on the same principle--and same underlying assumption. This is the question. According to GR, does the wavelength of light not stretch or compress in exact proportion to the expansion/compression of space? How can an interferometer yield anything but a null result? If a gravity wave passes perpendicular to one arm, and lengthens it by 1 part per zillion, will the wavelength of light along that arm not also increase by 1 part in a zillion? This will yield zero phase change, i.e. a null result, like the Michelson-Morley experiment. So far, a null result is all the interferometer G-wave detectors have offered up. But how can it be otherwise? How can a measuring stick be used to measure G-waves, when the meareuing stick itelf expands and contracts in the same proportion as that which is being measured?
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PW -- Plant Whisperer |
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The period of the gravity wave is much longer than the time it takes for the light to be emitted, travel down and back the arms, and be detected again. That is, each photon sees very little change in the distance during its lifetime, so its wavelength does not change much.
Regardless, the wavelength does not matter. Send a pulse down the arms and if they arrive back at the same time, the arms are the same length. Send a pulse a moment later (say, when the gravitational wave has reached its "peak") and if they do not arrive back at the same time, the path lengths must have changed. It does not matter if you sent additional pulses between those two sets (or even different numbers of additional pulses along the different arms), the fact that the pulses no longer match up means the arm lengths have changed. Think of the pulses as the peaks in the EM wave, then you can see this applies to frequencies/wavelengths. Since the speed of light is constant, the travel time changes regardless of if the frequency of light also changes. |
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aren't the photons also effected by the gravity waves?
seems to me we're trying to detect something where the detector and the detectee are being changed exactly the same. If I grow an inch and you grow an inch then we're still the same height relatively. I understand the concept, perpendicular arms will not be the same length if hit by a gravity wave. But how do we know that it will change the length anyway? and again, isn't the photon changed in the same way?
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"I will do my best to understand and explain the universe from big to small without invoking miracles, unrepeatable events, or divine intervention. In place of those things I will use observations, mathematics, and science." -Cross My travel blog Some of my Astrophotography Those that lack education have a hard time understanding its value. - Cross |
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| crosscountry |
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This message has been deleted by crosscountry.
Reason: double post
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But the photons in each of the arms is changed by a different amount. That difference is what is detected. It's not the actual amount of change that is dectected, but the difference in the amount of change.
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Some try to tell me, thoughts they cannot defend,... - Moody Blues. |
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Think about this. There is an ignorable degree of freedom embedded in reality, which has to do with size. If everything grows by a factor of 2, and time slows down accordingly to keep the speed of light the same, there would be no way for us to tell the difference. If there's no way to tell the difference, then there is no difference. So your question is, why don't gravity waves do the same thing? If they did, they would do nothing-- they wouldn't exist. There'd be no need for a theory that does nothing. So we know that the theory of gravity waves must describe a different kind of effect. It is an effect that changes distances in a way that is measurable, because time applies the same way to both directions, and the speed of light is the same in both directions, so if the distances are relatively different, there will be a relative change in time too. That's what is measured.
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I guess that's what I was asking. I ask that because even though I've studied (just a little) gravity waves they are still unresolveable to me. Quote:
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What I've studied shows that if gravity waves do exist they affect the physical world so minutely it is nearly impossible to detect. Even a nearby pulsar, which is supposed to create quite a lot of gravity waves, would barely be within the order of magnitude of our greatest detectors.
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"I will do my best to understand and explain the universe from big to small without invoking miracles, unrepeatable events, or divine intervention. In place of those things I will use observations, mathematics, and science." -Cross My travel blog Some of my Astrophotography Those that lack education have a hard time understanding its value. - Cross |
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Before the beams are split, any effects the wave produces will be same on both split beams. Once brought back together, at the detector, the beams will again be affected by the wave by the same amount. Neither of these has any effect on the measurement. It is while the beams are split and in the different legs that each beam will change by a different amount. It is that difference that is detected when the beams are brought back together.
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Some try to tell me, thoughts they cannot defend,... - Moody Blues. |
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interferometry right? I get that part. it seems to me the photon will move accordingly when the wave passes to ofset the new length. Even that, don't these waves come by at the speed of gravity/light? if so the effect would/could go by before the photon was able to reflect - thus no measureable change.
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"I will do my best to understand and explain the universe from big to small without invoking miracles, unrepeatable events, or divine intervention. In place of those things I will use observations, mathematics, and science." -Cross My travel blog Some of my Astrophotography Those that lack education have a hard time understanding its value. - Cross |
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Regarding the distance and wavelength changing but the speed of light being the same, let us try another thought experiment: the mirrors on each arm of the interferometer are 1 exactly zillion wavelengths apart. A gravitational wave from a supernova, which should have low frequency and thus long wavelength, happens to line up with one arm, and as it passes the instrument, the wave increases the distance between mirrors by 1 wavelength, or 1 part per zillion (ppz). The wavelength of the light also increases by 1 ppz, so there is no phase-change at the detector, but the time-of-travel has also increased by 1 ppz, which should be detectable as a relative change in time...except, the gravitational wave as it passes causes my clock to run 1 ppt slow, so my measurement of the round-trip time between mirros is the same ![]()
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PW -- Plant Whisperer |
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Some try to tell me, thoughts they cannot defend,... - Moody Blues. |
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For LIGO, you are talking about waves with legths from 10's of Kilometers to the diameter of the earth. There is plenty of time, even moving at c, for the wave to cause a change in the length.
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Some try to tell me, thoughts they cannot defend,... - Moody Blues. |
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You have caught the essence of my questions.![]()
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"I will do my best to understand and explain the universe from big to small without invoking miracles, unrepeatable events, or divine intervention. In place of those things I will use observations, mathematics, and science." -Cross My travel blog Some of my Astrophotography Those that lack education have a hard time understanding its value. - Cross |
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__________________
"I will do my best to understand and explain the universe from big to small without invoking miracles, unrepeatable events, or divine intervention. In place of those things I will use observations, mathematics, and science." -Cross My travel blog Some of my Astrophotography Those that lack education have a hard time understanding its value. - Cross |
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I hesitate, only because it could very well be that you are not understanding this becuase of the way I am describing it. But to your question, yes, there would be time for each of the legs to stretch, return to zero and then shrink several times as the waves pass (there shouldn't be just one GW, there should be a train of them). Basically, as the waves pass, the legs continually change their lengths, the interference pattern would be constantly changing.
__________________ Some try to tell me, thoughts they cannot defend,... - Moody Blues. |