An event horizion is a spherical surface enclosing an area. It isnt a circle, it is a spherical shell.

To the distant observer, the length contraction is subsumed into the time dialation. The space that a black hole occupies does not look distorted from outside.

You should read on wiki about the Schwarzschild radius. That explains the radius of the event horizion.

To find the radius of the event horizion you use an energy balance equation.

You start with a particle at a position r with a velocity v in a gravitational field. You then have the particle escape to infinity. This is how you find escape velocity. This equation looks like this

.5mv^2+(-GmM/r^2)=.5m(vf)^2+(-GmM/(rf)^2)

In this equation m is the test mass, M is the BH mass, v is the start test velocity, G is the gravitational constant, r is the start test radius, (vf) is the final test velocity, (rf) is the final test distance.

In this case we are looking at the particle escaping. We look at the minimum requirements for escape. In this case vf goes to 0 as rf goes to infinity. This is convenent cause it makes the two terms on the right side equal zero giving us

.5mv^2+(-GmM/r^2)=0

now for escaping from a black hole, we look for the point where v=c to escape.

.5mc^2-GmM/r^2=0

Solve for r

r^2=2GM/c^2

Square root both sides and you get a radius at which the escape velocity equals the speed of light. The definition of event horizon

Notice that this radius is in all directions. This gives you a spherical shell of radius r.

How can a spherical shell exist without having distance inside? The two poles meet. It has 0 depth. What is a spherical shell with 0 depth.

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I get all of this ... but it is not real space inside the black hole so ... what is really meant by a spherical shell ... does that mean that this shell displaces v ammount of space? What does that even mean?

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Where did you get that from?

And that?

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It's not "my reasoning", it is simple general relativity. It is a fact of science, whether you think it holds true or not. If you don't like it, think of a better theory than general relativity, and you will become justifiably famous. But as it is, you aren't making much progress in understanding anything.
It does have distance inside.
Yes it is real space inside the black hole.

Everything you think you know about black holes is entirely wrong. Furthermore, you refuse to believe that anyone could possibly know more about black holes than you do. All we ever get is what you "think about on the way to work" or some such fantasy. If you want to learn, I mean if you really want to learn about black holes, then do it. There are plenty of reasonable books out there, and you have already been directed towards perfectly reasonable sources. All you are doing here is demonstrating a remarkable & stubborn resistance to knowledge that will not serve you well.

Edited to add: I posted this before realizing that tommac had been banned and cannot reply. Nonetheless, should he see it, I stick by my advice.

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In case Tommac takes a peek at this thread, I suggest reading through the previous BAUT thread "Black hole dimension", as well as the website I linked to in this page.

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Your incorrect assumption is this:-
Escape velocity is proportional to the gravitational pull and distance from centre of mass. They are not the same as they are not in the same units - m/s as opposed to m/s^2.

The escape velocity from the surface of the Earth is 11 000 m/s and the gravitational pull is 9.8m/s^2.

The escape velocity of a BH at the event horizon (EH) is 3x10^8m/s and is dependent on BH mass alone. The gravitational acceleration at the EH will be dependent on BH mass alone too but you should be able to see that it is not going to be the same figure.

cool

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