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I ran into some problems on this famous paradox.
if you move fast time is supposed to slow down. so lets say what will happen in this case: I have one stationary clock and another one is sent some to distance away and it returns back to same point. later we compare them and do they show different time ? Some Time ago I expected that they should show different time, but now I think that they will show exactly same time like no relativity ever existed. because all effects will cancel if you return to the same point. |
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The Same Point is the point here. You are considering a return to the same point. But it hasn't, it is at a different point in the four dimensional sense. Both clocks have left that original point "somewhere back there" on their individual time lines. The usual set up is for the clock that is "stationary" to be assigned coordinate time because it will have the longest proper time possible for the twins scenario you describe. Whilst the traveled clock will have less time elapsed meaning it was observed to be time-dilated by the "stationary clock" Also SR is largely about speed, a scalar, so the direction relative to you doesn't matter, so a difference is not cancelled out.
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The one that have changed reference frames(the one that moved) will be behind the one that stayed behind.
If you have clock a and b, and they start in the same reference frame(same speed and position), one accelerates at 1g for a week, does nothing for a week, then decelerates for a week. Now that clock will be behind the one left behind.. Now if the OTHER clock does the same thing, then when they meet up they will show the same time. But if the one that traveled first travels back, it will still be behind. |
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Lets say two clocks are set to exactly the same time. Neither will wear down with time or anything. One clock is left on Earth, while the other is sent out into the cosmos at some non-relativistic speed, say 20k mph. The clock going out into space spends 2 billion years going out, and then 2 billion years returning to Earth.
Should the clocks still show the same time?
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and if we think in that way then time will slow down when distance increases, and it will speed up if it increases. all that because of simple Dopler shift. which can explain everything on all relativity cases. in case if we assume that speed is scalar, I don't see any way to solve problem with invariance. neither observer can tell who is moving and who is not. acceleration cant be used for that, because we can accelerate for few minutes and then fly free for many years. And relativity does not mention acceleration anywhere too. in case if all this happens because of acceleration, then just putting clock into centrifuge should slow down it indefinitely, since acceleration is constant for unlimited time. Quote:
experiments where clock trawled only one direction doest count since effect will not cancel in that way since to read data from clock you must catch your clock so all experiments will be performed on decreasing distance or else if clock is running away you cant catch and measure it. Last edited by Digix; 09-November-2008 at 12:28 PM.. |
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none of the formulas mentions acceleration, and acceleration is also non constant but only temporary so after acceleration process ended all observers are equal and are free to think that they are stationary and another observer is moving. |
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The clock that traveled 4Gyears relative to an observer that is stationary WRT to a clock on earth will have had less time elapse. The equation being 4GyearsX Squareroot(1-(8940.8^2/c^2))= not quite 4Gyears. It comes down to the precision of the calculator used but 8940^2/c^2 is very small. Nevertheless 4Gyears should be plenty enough time for a small dilation at non-relativistic speeds to be seen; especially given the clocks would be 12hr or 24hr Edit: Managed to get3.999999998 billion years, approx 73days (Edit correction 730 days being two years, sorry )shorter time on the clock that travelled not counting leap years
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"You can't talk to a brick wall but you can do Graffiti" Last edited by sirius0; 10-November-2008 at 03:30 AM.. |
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No Digix. It has to be scalar. Your scenario would have two people waiting on two train stations with synchronised watches seeing two different effects for a relativistic train travelling between those two stations. But observers stationary relative to one another must agree on what they observe.
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but the whole idea is if I not use any clock synchronization. just 2 watches, (not 3) and you do all measuring in the starting point. alternative question would be if I put some clock into centrifuge and rotate it there for some time, will it slow down? |
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Digix, speed is a scalar. Velocity is a vector. Vectors have a direction and a magnatude. In the case of velocity, that magnitude is the scalar, speed.
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so seems that moving clock will lag afterall. but again how to solve invariance problem here speed just cant have any effect. so it means that all is because of acceleration. |
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how can you be moving with no direction? |
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While the observers are now stationary, they took different world lines to get to that place from the original starting point. The observer whose world line included acceleration is the one whose time passed slower.
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Some try to tell me, thoughts they cannot defend,... - Moody Blues. Neptune- The original Dark Matter. The author feels that this technique of deliberately lying will actually make it easier for you to learn the ideas. - Donald Knuth |
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![]() so basically SR is just some approximation and real effects are because of that unmentioned acceleration Ok, now everything is almost fine. |
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No, check any begining physics book. The definition of a scalar is a one component quantity (a magnitude) that is invariant under rotations. Speed fits this definition as the quantity will stay the same no matter which direction you go. A vector has two components. A magnitude and a direction. In the case of velocity, it has two components. It has speed and a direction.
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Some try to tell me, thoughts they cannot defend,... - Moody Blues. Neptune- The original Dark Matter. The author feels that this technique of deliberately lying will actually make it easier for you to learn the ideas. - Donald Knuth |
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Be careful here. SR is not just an approximation. In the case of an observer going out and back, you have to calculate five different time effects. The original acceleration, the first coasting, the acceleration to turn around, the second coasting, and the final acceleration to arrive at the final point. All of those combine to determine how fast the observer aged. The acceleration will just tell you which of the observer's ages the least. The time during coasting parts can be calculated as relative motion using only the original SR equations.
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Some try to tell me, thoughts they cannot defend,... - Moody Blues. Neptune- The original Dark Matter. The author feels that this technique of deliberately lying will actually make it easier for you to learn the ideas. - Donald Knuth |
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it is like voltage only can be between 2 points and it cant be in single point. also back to the relativity Do I understand correctly now. if you accelerate in one direction then time slows down and it speed up if you accelerate in another direction, if there is no acceleration time speed does not change. basically time speed is just matter of energetic potential. like in gravity, if you move up time accelerates for you if you move down it slows down. |
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Some try to tell me, thoughts they cannot defend,... - Moody Blues. Neptune- The original Dark Matter. The author feels that this technique of deliberately lying will actually make it easier for you to learn the ideas. - Donald Knuth |
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Some try to tell me, thoughts they cannot defend,... - Moody Blues. Neptune- The original Dark Matter. The author feels that this technique of deliberately lying will actually make it easier for you to learn the ideas. - Donald Knuth |
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Digix,
It is quite easy to set up the twin "paradox" in a way that completely avoids acceleration. The clocks are already in relative motion and are compared at the instant they pass. Acceleration is not essential to understanding time dilation. It is pure special relativity. -- Jeff, in Minneapolis
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But we've talked about this before. ![]() |
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Some try to tell me, thoughts they cannot defend,... - Moody Blues. Neptune- The original Dark Matter. The author feels that this technique of deliberately lying will actually make it easier for you to learn the ideas. - Donald Knuth |
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But acceleration is essential for understanding the twin paradox, which involves not just time dilation. That's the point of it-- most people "get" time dilation at some level, but they think it's a "paradox" because it is symmetric with both observers-- both observers think the other is younger. But in the twin "paradox", one is definitely younger, because they have been reunited. This is why the resolution of the paradox absolutely does require acceleration, or gravity.
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In that case, can we go back in time before I posted that, please? I must
have had some other "paradox" in mind, if acceleration is essential to the "twin paradox". Thinking about it for a few seconds, I don't know how to get two clocks to tick at identical rates if they are in relative motion but one is not accelerated, so, uh, yeah... Sorry about that. Just go back two hours, that's all. ... However... You could eliminate the turnaround at the far end of the trip by having a third clock already in motion. That reduces the number of acceleration events from three to two. If that has any value... -- Jeff, in Minneapolis
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