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Old 27-December-2008, 03:10 AM
jra-xp jra-xp is offline
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Default Roots/Exponents equation help

Hello there,

I'm stuck on two problems that have exponents/radicals. I have the answer to each of them but can't figure out how to get there. I know this may seem a little 'below' what normally goes on here but it's pretty much a lock that any help I get will be right.

The first is this: y^3/4SQRTy (not sure how to write that) It's "y" to the third power over (index of) 4 (radical sign) with a "y" under the radical sign. The answer (back of the book...with NO explaination, gah!) is y with the exponent fraction of 11/4.

The second is x^-2 y^2 over 2 with the whole fraction in ( ) to the -3 power.
The answer is 8x^6 over y^6.

What I'd really like to hear is that the book is wrong.

It would be great to know what this operation is called, then I could look it up. But I don't even know what property (or maybe even properties) should be used. I tried a couple of the "math help" sites but they really don't go into exponent fractions. I had three problems that I couldn't get but got one worked out. These two are killing me.

Thanks for your time.
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Old 27-December-2008, 03:39 AM
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For the 2nd one, multiply the -3 into the parenthesis:

((x^-2 y^2)/2)^-3 = x^6 y^-6 / (2^-3)

see if you can take it from there.
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Old 27-December-2008, 03:52 AM
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You can't have a radical as a denominator. You have to multiply both the numerator and denominator by the sqrt y.
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Old 27-December-2008, 03:55 AM
Tinaa Tinaa is offline
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Try this page: http://www.wtamu.edu/academic/anns/m...ationalize.htm
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Old 27-December-2008, 04:03 AM
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Quote:
Originally Posted by jra-xp View Post
Hello there,

I'm stuck on two problems that have exponents/radicals. I have the answer to each of them but can't figure out how to get there. I know this may seem a little 'below' what normally goes on here but it's pretty much a lock that any help I get will be right.

The first is this: y^3/4SQRTy (not sure how to write that) It's "y" to the third power over (index of) 4 (radical sign) with a "y" under the radical sign. The answer (back of the book...with NO explaination, gah!) is y with the exponent fraction of 11/4.

The second is x^-2 y^2 over 2 with the whole fraction in ( ) to the -3 power.
The answer is 8x^6 over y^6.

What I'd really like to hear is that the book is wrong.

It would be great to know what this operation is called, then I could look it up. But I don't even know what property (or maybe even properties) should be used. I tried a couple of the "math help" sites but they really don't go into exponent fractions. I had three problems that I couldn't get but got one worked out. These two are killing me.

Thanks for your time.
The following is from my wife, the math teacher. It took us awhile to puzzle out the first problem, but this seems to provide the correct answer.

ETA: We had some problems attaching the solution (JPEG format). Let me know if you have problems reading it.
Attached Images
File Type: jpg answer1.jpg (38.6 KB, 17 views)
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Old 27-December-2008, 04:06 AM
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Shoot I was thinking 4 times sqrt y.
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Old 27-December-2008, 04:09 AM
tony873004 tony873004 is online now
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Quote:
Originally Posted by ABR. View Post
The following is from my wife, the math teacher. It took us awhile to puzzle out the first problem, but this seems to provide the correct answer.

ETA: We had some problems attaching the solution (JPEG format). Let me know if you have problems reading it.
That's why I couldn't get the 1st one! I was reading 4*sqrt(y), not y^(1/4). It's too bad this forum doesn't have LaTex.

edit: Tinaa too I see!
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Old 27-December-2008, 04:10 AM
Tinaa Tinaa is offline
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I couldn't get it to work either.
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Old 27-December-2008, 04:11 AM
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I worked the problem several different ways myself before giving up and showing it to my wife. It took her a minute or two to figure it out so I didn't feel totally ignorant. Incidentally, she used MathType to write out the equations which we then converted to jpg for the attachment.
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Old 27-December-2008, 04:33 AM
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Quote:
Originally Posted by ABR. View Post
The following is from my wife, the math teacher. It took us awhile to puzzle out the first problem, but this seems to provide the correct answer.
Ha ha! I used to be a math teacher, too, some number of moons ago, and I looked at that first problem, confident that I could solve any high school problem at least, and thought... "Huh?"

The stopwatch was running. So I was a little rusty. It was six seconds later that I recalled that the key to the problem was that the fourth root of y in the denominator was equivalent to y to the one-fourth (in the denominator), which is the same as y to the minus one-fourth in the numerator.

From there, there are a number of ways to "crunch the numbers."

I went from y3/y1/4 to y2+3/4 to y11/4.
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Old 27-December-2008, 04:49 AM
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My problem was figuring out what the original problem was. Oh, to have a scratch pad capability. Having the answer is what allowed us to figure it out and then on to the solution. Is there a math editor/equation writer available here on BAUT?

More importantly, jra-xp...did any of this help? Next time you log in, hopefully, you'll let us all know.
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Old 27-December-2008, 04:55 AM
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From there, there are a number of ways to "crunch the numbers."
One must note, however, that the bases of these oddly occurring exponents are the same: y. Otherwise, one cannot simply add or subtract exponents to simplify the expression.
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Old 27-December-2008, 04:59 AM
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My problem was figuring out what the original problem was. Oh, to have a scratch pad capability.
Oh, right. I had to transcribe it onto... a scratch pad.
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Old 27-December-2008, 05:09 AM
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More importantly, jra-xp...did any of this help? Next time you log in, hopefully, you'll let us all know.
It helped me as I couldn't understand the first problem at all. Thanks and especially thanks to your wife. Nicely explained.
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Old 27-December-2008, 05:12 AM
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Originally Posted by jra-xp View Post
The first is this: y^3/4SQRTy (not sure how to write that) It's "y" to the third power over (index of) 4 (radical sign) with a "y" under the radical sign.
"(index of) 4" is the correct terminology for a fourth root....
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Old 27-December-2008, 07:48 PM
jra-xp jra-xp is offline
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Wow! Thanks guys!

That helped completely!

Quote:
Originally Posted by Tinaa View Post
Great site. Does that mean these are college algebra questions? Which would be cool.



Quote:
Originally Posted by ABR. View Post
The following is from my wife, the math teacher. It took us awhile to puzzle out the first problem, but this seems to provide the correct answer.

ETA: We had some problems attaching the solution (JPEG format). Let me know if you have problems reading it.
Awsome. Tell Mrs. ABR she's a friggin hero. The write up was what I needed.
3. change 3 over 1 to 12 over 4 by multiplying top and bottom by four.
This is actually in the book, but I didn't make the connection. You have to really know the basic rules to get this stuff to work out right. Once you know the rules its knowing when to do what that matters.

And the second problem,
2. move the x squared from the bottom to the top to make the exponent positive.

I think this is a combination of Property 5 and 6. (also in the book...sheesh)

a^-n = 1 over a^n
a^-1 = 1 over a

I think what those mean is that you can flip the exponent up or down by just changing the sign.

I got all the other questions right, these two were by far the hardest because what you had to do wasn't right out in front.

Thanks again, I'm glad some of you were stumped as well.
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Old 27-December-2008, 07:55 PM
jra-xp jra-xp is offline
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Sorry!

I didn't realize that the posts went to the moderator first before being put up. I posted the same thing like 8 times thinking it was busted....

Sorry for that.

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That's weird. This post went up fast. Maybe it's the quotes that make it moderator checked....
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Old 27-December-2008, 09:16 PM
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Glad to be of help, jra-xp (says the guy who just attached the jpg). I've passed your message along to my wife -- yours, too Veeger. She reminded me that this stuff is what she does for a living!
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